University Physics with Modern Physics (14th Edition)
14th Edition
ISBN: 9780321973610
Author: Hugh D. Young, Roger A. Freedman
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 38, Problem 38.42PP
To determine
The maximum number of ionizations generated by one photon.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
While interacting with molecules (mainly water) in the tumor tissue, each Compton electron or photoelectron causes a series of ionizations, each of which takes about 40 eV. Estimate the maximum number of ionizations that one photon generated by this linear accelerator can produce in tissue. (a) 100; (b) 1000; (c) 104; (d) 105.
You use 0.124 nm x-ray photons in a Compton-scattering experiment. At what angle is the wavelength of the
scattered x rays 1.0% longer than that of the incident x rays?
O 70.6°
56.5°
67.0°
60.7°
s) The cutoff frequency of a specific metal is known to be 0.72x1015Hz. During a
photoelectric experiment, 3.7x102º photons with a wavelength of 167nm are striking a plate
every second. What is the power of the photons and what is the maximum kinetic energy of the
ejected electrons?
Chapter 38 Solutions
University Physics with Modern Physics (14th Edition)
Ch. 38.1 - Silicon films become better electrical conductors...Ch. 38.2 - Prob. 38.2TYUCh. 38.3 - Prob. 38.3TYUCh. 38.4 - Prob. 38.4TYUCh. 38 - Prob. 38.1DQCh. 38 - Prob. 38.2DQCh. 38 - Prob. 38.3DQCh. 38 - Prob. 38.4DQCh. 38 - Prob. 38.5DQCh. 38 - Prob. 38.6DQ
Ch. 38 - Prob. 38.7DQCh. 38 - Prob. 38.8DQCh. 38 - Prob. 38.9DQCh. 38 - Prob. 38.10DQCh. 38 - Prob. 38.11DQCh. 38 - Prob. 38.12DQCh. 38 - Prob. 38.13DQCh. 38 - Prob. 38.14DQCh. 38 - Prob. 38.15DQCh. 38 - Prob. 38.16DQCh. 38 - Prob. 38.17DQCh. 38 - Prob. 38.1ECh. 38 - Prob. 38.2ECh. 38 - Prob. 38.3ECh. 38 - Prob. 38.4ECh. 38 - Prob. 38.5ECh. 38 - Prob. 38.6ECh. 38 - Prob. 38.7ECh. 38 - Prob. 38.8ECh. 38 - Prob. 38.9ECh. 38 - Prob. 38.10ECh. 38 - Prob. 38.11ECh. 38 - Prob. 38.12ECh. 38 - Prob. 38.13ECh. 38 - Prob. 38.14ECh. 38 - Prob. 38.15ECh. 38 - Prob. 38.16ECh. 38 - Prob. 38.17ECh. 38 - Prob. 38.18ECh. 38 - Prob. 38.19ECh. 38 - Prob. 38.20ECh. 38 - Prob. 38.21ECh. 38 - An electron and a positron are moving toward each...Ch. 38 - Prob. 38.23ECh. 38 - Prob. 38.24ECh. 38 - Prob. 38.25ECh. 38 - Prob. 38.26PCh. 38 - Prob. 38.27PCh. 38 - Prob. 38.28PCh. 38 - Prob. 38.29PCh. 38 - Prob. 38.30PCh. 38 - Prob. 38.31PCh. 38 - Prob. 38.32PCh. 38 - Prob. 38.33PCh. 38 - Prob. 38.34PCh. 38 - Prob. 38.35PCh. 38 - Prob. 38.36PCh. 38 - Prob. 38.37PCh. 38 - Prob. 38.38PCh. 38 - Prob. 38.39PCh. 38 - Prob. 38.40CPCh. 38 - Prob. 38.41PPCh. 38 - Prob. 38.42PPCh. 38 - Prob. 38.43PPCh. 38 - Prob. 38.44PPCh. 38 - Prob. 38.45PP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- The stopping potential for photoelectrons emitted from a surface illuminated by light of wavelength 491nm is 0.71V. When the incident wavelength is changed to anew value, the stopping potential is found to be 1.43V.a) What is the work function for the surface? b) What is this new wavelength?arrow_forwardIn a Compton scattering experiment, an x-ray photon scatters through an angle of 17.0° from a free electron that is initially at rest. The electron recoils with a speed of 2,120 km/s. (a) Calculate the wavelength of the incident photon. 0.125 Your response differs from the correct answer by more than 10%. Double check your calculations. nm (b) Calculate the angle through which the electron scatters. 53.49 Your response differs from the correct answer by more than 10%. Double check your calculations.arrow_forwardA 90nm radiation falls on a photoelectric surface, and the work function of photoelectrode is 4.3 ev. The Plank's constant is 6.625 x 1034 J.s and mass of electron is 9.11 x 1031 kg. Determine ) The maximum kinetic energy of the electrons in Joules: () The velocity of the photoelectrons in m/s:| (C) The stopping potential in Volts. when the same surface is illuminated with light of wavelength 205 nmarrow_forward
- A light detector (your eye) has an area of 2.00*10-6 m2 and absorbs 80% of the incident light, which is at wavelength 500 nm. The detector faces an isotropic source, 3.00 m from the source. If the detector absorbs photons at the rate of exactly 4.000 s-1, at what power does the emitter emit light?arrow_forwardThe stopping potential for photoelectrons emitted from a surface illuminated by light of wavelength 491nm is 0.71V. When the incident wavelength is changed to a new value, the stopping potential is found to be 1.43V.a) What is the work function for the surface?b) What is this new wavelength?arrow_forwardIn a Compton scattering experiment, an x-ray photon scatters through an angle of 15.0° from a free electron that is initially at rest. The electron recoils with a speed of 2,200 km/s. (a) Calculate the wavelength of the incident photon. nm (b) Calculate the angle through which the electron scatters. Oarrow_forward
- In a Compton scattering experiment, an x-ray photon scatters through an angle of 12.2° from a free electron that is initially at rest. The electron recoils with a speed of 1,480 km/s. (a) Calculate the wavelength of the incident photon. 0.144 Your response differs from the correct answer by more than 10%. Double check your calculations. nm (b) Calculate the angle through which the electron scatters.arrow_forwardA beam of 400 nm light is adjusted to have the same intensity as a beam of 600 nm light. How does the number of photons in the 400nm beam, N400 compare to the number of photons, N600 in the 600 nm beam. Question 5 options: N400 = 2*N600 N400 = 32600 N400 = N600 N400 = 23600 N400 = 2600 None of the other responses are correct.arrow_forwardThe stopping potential for photoelectrons emitted from a surface illuminated by light of wavelength λ1 = 491nm is V1. When the incident wavelength is changed to a new value λ2 = 382nm, the stopping potential is doubled. a) What is the numerical value of V1? b) What is the work function for the surface?arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning