Concept explainers
In Exercises 35–48 the graph of f is given. Use the graph to compute the quantities asked for. [HINT: See Examples 4–5.]
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Applied Calculus
- In Exercises 75–78, sketch the graph of a function y = f(x) that satis- fies the given conditions. No formulas are required-just label the coordinate axes and sketch an appropriate graph. (The answers are not unique, so your graphs may not be exactly like those in the answer section.) 75. f(0) = 0, f(1) = 2, f(-1) = -2, lim f(x) = -1, and x--00 lim f(x) = 1 76. f(0) = 0, lim f(x) = 0, lim f(x) = 2, and lim f(x) = -2 x→0* %3D 77. f(0) = 0, lim f(x) = 0, lim f(x) = lim f(x) = ∞, x-too x→1- x--1+ = -0, and lim f(x) = -∞ lim f(x) x→1* 78. f(2) = 1, f(-1) = 0, lim f(x) = 0, lim f(x) = ∞, x→0* lim f(x) = -00, and lim f(x) = 1 X -00arrow_forwardIn Exercises 51–54, graph the function ƒ to see whether it appears to have a continuous extension to the origin. If it does, use Trace and Zoom to find a good candidate for the extended function’s value at x = 0. If the function does not appear to have a continuous extension, can it be extended to be continuous at the origin from the right or from the left? If so, what do you think the extended function’s value(s) should be?arrow_forwardIn Exercises 3–10, differentiate the expression with respect to x, assuming that y is implicitly a function of x.arrow_forward
- In Exercises 25–30, give a formula for the extended function that iscontinuous at the indicated point.arrow_forwardIn Exercises 79–82, find a function that satisfies the given conditions and sketch its graph. (The answers here are not unique. Any function that satisfies the conditions is acceptable. Feel free to use formulas defined in pieces if that will help.) 79. lim f(x) = 0, lim f(x) = ∞, and lim f(x) = ∞ x→too x-2+ 80. lim g(x) = 0, lim g(x) = –∞, and lim g(x) = ∞ x→3- x→3* 81. lim h(x) = -1, lim h(x) = 1, lim h(x) = -1, and x -00 lim h(x) = 1 x→0+ 1, lim k(x) x→l¯ = 00, and lim k(x) x→I* 82. lim k(x) = -00arrow_forwardIn Exercises 1–4, show that the limit leads to an indeterminate form. Then carry out the two-step procedure: Transform the function alge- braically and evaluate using continuity.arrow_forward
- In Exercises 15–22, calculate the approximation for the given function and interval.arrow_forwardSuppose f and g are the piecewise-defined functions defined here. For each combination of functions in Exercises 51–56, (a) find its values at x = -1, x = 0, x = 1, x = 2, and x = 3, (b) sketch its graph, and (c) write the combination as a piecewise-defined function. f(x) = { (2x + 1, ifx 0 g(x) = { -x, if x 2 8(4): 51. (f+g)(x) 52. 3f(x) 53. (gof)(x) 56. g(3x) 54. f(x) – 1 55. f(x – 1)arrow_forwardThe process by which we determine limits of rational functions applies equally well to ratios containing noninteger or negative powers of x: Divide numerator and denominator by the highest power of x in the denominator and proceed from there. Find the limits in Exercises 23–36.arrow_forward
- In Exercises 83–85, you will use a CAS to help find the absolute extrema of the given function over the specified closed interval. Per-form the following steps. a. Plot the function over the interval to see its general behavior there. b. Find the interior points where ƒ′ = 0. (In some exercises, you may have to use the numerical equation solver to ap-proximate a solution.) You may want to plot ƒ′ as well. c. Find the interior points where ƒ′ does not exist. d. Evaluate the function at all points found in parts (b) and (c) and at the endpoints of the interval. e. Find the function’s absolute extreme values on the interval and identify where they occur. 83. ƒ(x) = x4 - 8x2 + 4x + 2, [-20/25, 64/25] 84. ƒ(x) = -x4 + 4x3 - 4x + 1, [-3/4, 3] 85. ƒ(x) = x^(2/3)(3 - x), [-2, 2]arrow_forwardIn Exercises 5 and 6, find the value that limarrow_forwardIn Exercises 83–86, determine whether thestatement is true or false. If it is false, explain why or give anexample that shows it is false. If the graph of a function has three x-intercepts, then it musthave at least two points at which its tangent line is horizontalarrow_forward
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