(a)
Interpretation: The mass of acrylonitrile produced from
Concept introduction: The relation between moles of reaction species is estimated through the
(a)
Answer to Problem 88E
The mass of acrylonitrile produced from
Explanation of Solution
The given reaction is shown below.
The values of molar masses of
The formula to calculate moles is shown below.
Substitute the value of mass and molar mass of ammonia in equation (1).
Substitute the value of mass and molar mass of oxygen in equation (1).
Substitute the value of mass and molar mass of propylene in equation (1).
For the reactants ammonia and
For the reactants ammonia and
Since the actual ratio is more than the required ratio, therefore, ammonia is in excess as compared to
For the reactants
For the reactants
Since the actual ratio is more than the required ratio, therefore, oxygen is also in excess as compared to
Thus, the limiting reagent is
From the reaction, it is clear that
So,
The mass of
Therefore, the mass of acrylonitrile is
(b)
Interpretation: The mass of water produced from
Concept introduction: The relation between moles of reaction species is estimated through the stoichiometric coefficients written with each species in the reaction. These coefficients are useful in calculating reaction’s yield. The stoichiometry calculations are useful in determining the limiting reactant on which the yield of reaction is actually dependent.
(b)
Answer to Problem 88E
The mass of water produced from
Explanation of Solution
The given reaction is shown below.
From the reaction, it is clear that
So,
The mass of
Therefore, the mass of water produced is
In the reaction,
So,
The mass of excess ammonia is calculated using equation (1) as follows.
Therefore, the mass of ammonia in excess is
In the reaction,
So,
The mass of excess oxygen is calculated using equation (1) as follows.
Therefore, the mass of oxygen in excess is
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Chapter 3 Solutions
Chemical Principles
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