Holt Mcdougal Larson Algebra 2: Student Edition 2012
Holt Mcdougal Larson Algebra 2: Student Edition 2012
1st Edition
ISBN: 9780547647159
Author: HOLT MCDOUGAL
Publisher: HOLT MCDOUGAL
bartleby

Concept explainers

Unitary Method
The word “unitary” comes from the word “unit”, which means a single and complete entity. In this method, we find the value of a unit product from the given number of products, and then we solve for the other number of products.
Speed, Time, and Distance
Imagine you and 3 of your friends are planning to go to the playground at 6 in the evening. Your house is one mile away from the playground and one of your friends named Jim must start at 5 pm to reach the playground by walk. The other two friends are 3 …
Profit and Loss
The amount earned or lost on the sale of one or more items is referred to as the profit or loss on that item.
Units and Measurements
Measurements and comparisons are the foundation of science and engineering. We, therefore, need rules that tell us how things are measured and compared. For these measurements and comparisons, we perform certain experiments, and we will need the experime…
bartleby

Videos

Expert Solution & Answer
Book Icon
Chapter 2.8, Problem 6MRPS
Solution

(a.)

A labelled diagram of the sculpture in terms of x .

A labelled diagram of the sculpture in terms of x, is given as follows:

  Holt Mcdougal Larson Algebra 2: Student Edition 2012, Chapter 2.8, Problem 6MRPS , additional homework tip 1

Given:

A sculpture is shaped as a pyramid with a square base.

The height of the pyramid is 4 inches less than the length of a side of the base.

The volume of the sculpture is 200 cubic inches.

Concept used:

Assuming an unknown dimension as x and determining the other dimensions in terms of x , a labelled diagram of the given figure can be constructed.

Calculation:

Let x represent the length (in inches) of a side of the sculpture’s base.

It is given that the height of the pyramid is 4 inches less than the length of a side of the base.

Then, the height of the pyramid shaped sculpture is x−4 .

Now, a labelled diagram of the sculpture is given as follows,

  Holt Mcdougal Larson Algebra 2: Student Edition 2012, Chapter 2.8, Problem 6MRPS , additional homework tip 2

Conclusion:

A labelled diagram of the sculpture in terms of x, is given as follows:

  Holt Mcdougal Larson Algebra 2: Student Edition 2012, Chapter 2.8, Problem 6MRPS , additional homework tip 3

(b.)

A function that gives the volume V of the sculpture, in terms of x .

It has been determined that the function that gives the volume V of the sculpture, in terms of x , is V=13x2x−4 .

Given:

A sculpture is shaped as a pyramid with a square base.

The height of the pyramid is 4 inches less than the length of a side of the base.

The volume of the sculpture is 200 cubic inches.

Concept used:

The volume V of a pyramid with square base equals one-third the product of the area of the square base and the height.

Calculation:

As assumed previously, x represents the length (in inches) of a side of the sculpture’s base and the height (in inches) of the pyramid shaped sculpture is x−4 .

Then, the area of the square base (in square inches) is given as x2 .

Now, according to the discussed formula, the volume V of the pyramid shaped sculpture (in cubic inches) is given as,

  V=13×x2×x−4

Rewriting,

  V=13x2x−4

This is the required function that gives the volume V of the sculpture, in terms of x .

Conclusion:

It has been determined that the function that gives the volume V of the sculpture, in terms of x , is V=13x2x−4 .

(c.)

The graph of the function obtained in part (b) and the estimate of the value of x for the sculpture.

The graph of the function obtained in part (b) is given as:

  Holt Mcdougal Larson Algebra 2: Student Edition 2012, Chapter 2.8, Problem 6MRPS , additional homework tip 4

It has been determined that the estimate of the value of x for the sculpture is x=10 .

Given:

A sculpture is shaped as a pyramid with a square base.

The height of the pyramid is 4 inches less than the length of a side of the base.

The volume of the sculpture is 200 cubic inches.

Concept used:

If either the abscissa or the ordinate is known, the corresponding ordinate or the abscissa can be obtained from the graph of the function.

Calculation:

The function obtained in part (b) is,

  V=13x2x−4

The graph of this function is given as,

  Holt Mcdougal Larson Algebra 2: Student Edition 2012, Chapter 2.8, Problem 6MRPS , additional homework tip 5

It is given that the volume of the sculpture is 200 cubic inches.

So, V=200 .

It can be seen from the graph that V=200 corresponds to x=10 .

This is the required estimate.

Conclusion:

The graph of the function obtained in part (b) is given as:

  Holt Mcdougal Larson Algebra 2: Student Edition 2012, Chapter 2.8, Problem 6MRPS , additional homework tip 6

It has been determined that the estimate of the value of x for the sculpture is x=10 .

(d.)

The value of x , by writing and solving an equation, its comparison with the estimate from part (c) and the dimensions of the sculpture.

The value of x , by writing and solving an equation, has been determined to be x=10 , which is equal to its estimate from part (c).

It has been determined that the base of the sculpture is 10 inches by 10 inches and the height of the sculpture is 6 inches.

Given:

A sculpture is shaped as a pyramid with a square base.

The height of the pyramid is 4 inches less than the length of a side of the base.

The volume of the sculpture is 200 cubic inches.

Concept used:

An equation can be solved by factorizing.

Calculation:

The function obtained in part (b) is,

  V=13x2x−4

It is given that the volume of the sculpture is 200 cubic inches.

So, V=200 .

Put V=200 in V=13x2x−4 to get,

  200=13x2x−4

Simplifying,

  x2x−4=600

On further simplification,

  x3−4x2=600

Finally,

  x3−4x2−600=0

Factorizing,

  x3−10x2+10x2−4x2−60x+60x−600=0x3−10x2+6x2−60x+60x−600=0x2x−10+6xx−10+60x−10=0x−10x2+6x+60=0

Note that the discriminant of x2+6x+60 is given as,

  62−4160=36−240<0

This implies that the roots of x2+6x+60=0 are complex.

So, the only real root of the obtained equation is x=10 .

Now, the estimated value from part (c.) was also x=10 .

As assumed in part (a), the length of a side of the square base is x=10 inches and the height of the pyramid is x−4=10−4=6 inches.

So, the base of the sculpture is 10 inches by 10 inches and the height of the sculpture is 6 inches.

Conclusion:

The value of x , by writing and solving an equation, has been determined to be x=10 , which is equal to its estimate from part (c).

It has been determined that the base of the sculpture is 10 inches by 10 inches and the height of the sculpture is 6 inches.

Previous
Chapter 2.8, Problem 5MRPS
Next
Chapter 2.8, Problem 7MRPS

Chapter 2 Solutions

Holt Mcdougal Larson Algebra 2: Student Edition 2012

Ch. 2.1 - Prob. 1GPCh. 2.1 - Prob. 2GPCh. 2.1 - Prob. 3GPCh. 2.1 - Prob. 4GPCh. 2.1 - Prob. 5GPCh. 2.1 - Prob. 6GPCh. 2.1 - Prob. 7GPCh. 2.1 - Prob. 8GPCh. 2.1 - Prob. 1ECh. 2.1 - Prob. 2E
Ch. 2.1 - Prob. 3ECh. 2.1 - Prob. 4ECh. 2.1 - Prob. 5ECh. 2.1 - Prob. 6ECh. 2.1 - Prob. 7ECh. 2.1 - Prob. 8ECh. 2.1 - Prob. 9ECh. 2.1 - Prob. 10ECh. 2.1 - Prob. 11ECh. 2.1 - Prob. 12ECh. 2.1 - Prob. 13ECh. 2.1 - Prob. 14ECh. 2.1 - Prob. 15ECh. 2.1 - Prob. 16ECh. 2.1 - Prob. 17ECh. 2.1 - Prob. 18ECh. 2.1 - Prob. 19ECh. 2.1 - Prob. 20ECh. 2.1 - Prob. 21ECh. 2.1 - Prob. 22ECh. 2.1 - Prob. 23ECh. 2.1 - Prob. 24ECh. 2.1 - Prob. 25ECh. 2.1 - Prob. 26ECh. 2.1 - Prob. 27ECh. 2.1 - Prob. 28ECh. 2.1 - Prob. 29ECh. 2.1 - Prob. 30ECh. 2.1 - Prob. 31ECh. 2.1 - Prob. 32ECh. 2.1 - Prob. 33ECh. 2.1 - Prob. 34ECh. 2.1 - Prob. 35ECh. 2.1 - Prob. 36ECh. 2.1 - Prob. 37ECh. 2.1 - Prob. 38ECh. 2.1 - Prob. 39ECh. 2.1 - Prob. 40ECh. 2.1 - Prob. 41ECh. 2.1 - Prob. 42ECh. 2.1 - Prob. 43ECh. 2.1 - Prob. 44ECh. 2.1 - Prob. 45ECh. 2.1 - Prob. 46ECh. 2.1 - Prob. 47ECh. 2.1 - Prob. 48ECh. 2.1 - Prob. 49PSCh. 2.1 - Prob. 50PSCh. 2.1 - Prob. 51PSCh. 2.1 - Prob. 52PSCh. 2.1 - Prob. 53PSCh. 2.1 - Prob. 54PSCh. 2.1 - Prob. 1DCCh. 2.1 - Prob. 2DCCh. 2.1 - Prob. 3DCCh. 2.1 - Prob. 4DCCh. 2.1 - Prob. 5DCCh. 2.1 - Prob. 6DCCh. 2.2 - Prob. 1GPCh. 2.2 - Prob. 2GPCh. 2.2 - Prob. 3GPCh. 2.2 - Prob. 4GPCh. 2.2 - Prob. 5GPCh. 2.2 - Prob. 6GPCh. 2.2 - Prob. 7GPCh. 2.2 - Prob. 8GPCh. 2.2 - Prob. 9GPCh. 2.2 - Prob. 10GPCh. 2.2 - Prob. 11GPCh. 2.2 - Prob. 12GPCh. 2.2 - Prob. 1ECh. 2.2 - Prob. 2ECh. 2.2 - Prob. 3ECh. 2.2 - Prob. 4ECh. 2.2 - Prob. 5ECh. 2.2 - Prob. 6ECh. 2.2 - Prob. 7ECh. 2.2 - Prob. 8ECh. 2.2 - Prob. 9ECh. 2.2 - Prob. 10ECh. 2.2 - Prob. 11ECh. 2.2 - Prob. 12ECh. 2.2 - Prob. 13ECh. 2.2 - Prob. 14ECh. 2.2 - Prob. 15ECh. 2.2 - Prob. 16ECh. 2.2 - Prob. 17ECh. 2.2 - Prob. 18ECh. 2.2 - Prob. 19ECh. 2.2 - Prob. 20ECh. 2.2 - Prob. 21ECh. 2.2 - Prob. 22ECh. 2.2 - Prob. 23ECh. 2.2 - Prob. 24ECh. 2.2 - Prob. 25ECh. 2.2 - Prob. 26ECh. 2.2 - Prob. 27ECh. 2.2 - Prob. 28ECh. 2.2 - Prob. 29ECh. 2.2 - Prob. 30ECh. 2.2 - Prob. 31ECh. 2.2 - Prob. 32ECh. 2.2 - Prob. 33ECh. 2.2 - Prob. 34ECh. 2.2 - Prob. 35ECh. 2.2 - Prob. 36ECh. 2.2 - Prob. 37ECh. 2.2 - Prob. 38ECh. 2.2 - Prob. 39ECh. 2.2 - Prob. 40ECh. 2.2 - Prob. 41ECh. 2.2 - Prob. 42ECh. 2.2 - Prob. 43ECh. 2.2 - Prob. 44ECh. 2.2 - Prob. 45ECh. 2.2 - Prob. 46ECh. 2.2 - Prob. 47ECh. 2.2 - Prob. 48ECh. 2.2 - Prob. 49ECh. 2.2 - Prob. 50ECh. 2.2 - Prob. 51ECh. 2.2 - Prob. 52ECh. 2.2 - Prob. 53ECh. 2.2 - Prob. 54PSCh. 2.2 - Prob. 55PSCh. 2.2 - Prob. 56PSCh. 2.2 - Prob. 57PSCh. 2.2 - Prob. 58PSCh. 2.2 - Prob. 59PSCh. 2.2 - Prob. 60PSCh. 2.2 - Prob. 1PCh. 2.2 - Prob. 2PCh. 2.2 - Prob. 3PCh. 2.2 - Prob. 4PCh. 2.2 - Prob. 5PCh. 2.2 - Prob. 6PCh. 2.2 - Prob. 7PCh. 2.2 - Prob. 8PCh. 2.2 - Prob. 9PCh. 2.2 - Prob. 10PCh. 2.3 - Prob. 1GPCh. 2.3 - Prob. 2GPCh. 2.3 - Prob. 3GPCh. 2.3 - Prob. 4GPCh. 2.3 - Prob. 5GPCh. 2.3 - Prob. 6GPCh. 2.3 - Prob. 1ECh. 2.3 - Prob. 2ECh. 2.3 - Prob. 3ECh. 2.3 - Prob. 4ECh. 2.3 - Prob. 5ECh. 2.3 - Prob. 6ECh. 2.3 - Prob. 7ECh. 2.3 - Prob. 8ECh. 2.3 - Prob. 9ECh. 2.3 - Prob. 10ECh. 2.3 - Prob. 11ECh. 2.3 - Prob. 12ECh. 2.3 - Prob. 13ECh. 2.3 - Prob. 14ECh. 2.3 - Prob. 15ECh. 2.3 - Prob. 16ECh. 2.3 - Prob. 17ECh. 2.3 - Prob. 18ECh. 2.3 - Prob. 19ECh. 2.3 - Prob. 20ECh. 2.3 - Prob. 21ECh. 2.3 - Prob. 22ECh. 2.3 - Prob. 23ECh. 2.3 - Prob. 24ECh. 2.3 - Prob. 25ECh. 2.3 - Prob. 26ECh. 2.3 - Prob. 27ECh. 2.3 - Prob. 28ECh. 2.3 - Prob. 29ECh. 2.3 - Prob. 30ECh. 2.3 - Prob. 31ECh. 2.3 - Prob. 32ECh. 2.3 - Prob. 33ECh. 2.3 - Prob. 34ECh. 2.3 - Prob. 35ECh. 2.3 - Prob. 36ECh. 2.3 - Prob. 37ECh. 2.3 - Prob. 38ECh. 2.3 - Prob. 39ECh. 2.3 - Prob. 40ECh. 2.3 - Prob. 41ECh. 2.3 - Prob. 42ECh. 2.3 - Prob. 43ECh. 2.3 - Prob. 44ECh. 2.3 - Prob. 45ECh. 2.3 - Prob. 46ECh. 2.3 - Prob. 47ECh. 2.3 - Prob. 48ECh. 2.3 - Prob. 49ECh. 2.3 - Prob. 50ECh. 2.3 - Prob. 51ECh. 2.3 - Prob. 52ECh. 2.3 - Prob. 53ECh. 2.3 - Prob. 54ECh. 2.3 - Prob. 55ECh. 2.3 - Prob. 56ECh. 2.3 - Prob. 57ECh. 2.3 - Prob. 58ECh. 2.3 - Prob. 59PSCh. 2.3 - Prob. 60PSCh. 2.3 - Prob. 61PSCh. 2.3 - Prob. 62PSCh. 2.3 - Prob. 63PSCh. 2.3 - Prob. 64PSCh. 2.3 - Prob. 1QCh. 2.3 - Prob. 2QCh. 2.3 - Prob. 3QCh. 2.3 - Prob. 4QCh. 2.3 - Prob. 5QCh. 2.3 - Prob. 6QCh. 2.3 - Prob. 7QCh. 2.3 - Prob. 8QCh. 2.3 - Prob. 9QCh. 2.3 - Prob. 10QCh. 2.3 - Prob. 11QCh. 2.3 - Prob. 12QCh. 2.3 - Prob. 13QCh. 2.3 - Prob. 14QCh. 2.3 - Prob. 15QCh. 2.3 - Prob. 16QCh. 2.4 - Prob. 1GPCh. 2.4 - Prob. 2GPCh. 2.4 - Prob. 3GPCh. 2.4 - Prob. 4GPCh. 2.4 - Prob. 5GPCh. 2.4 - Prob. 6GPCh. 2.4 - Prob. 7GPCh. 2.4 - Prob. 8GPCh. 2.4 - Prob. 9GPCh. 2.4 - Prob. 10GPCh. 2.4 - Prob. 11GPCh. 2.4 - Prob. 1ECh. 2.4 - Prob. 2ECh. 2.4 - Prob. 3ECh. 2.4 - Prob. 4ECh. 2.4 - Prob. 5ECh. 2.4 - Prob. 6ECh. 2.4 - Prob. 7ECh. 2.4 - Prob. 8ECh. 2.4 - Prob. 9ECh. 2.4 - Prob. 10ECh. 2.4 - Prob. 11ECh. 2.4 - Prob. 12ECh. 2.4 - Prob. 13ECh. 2.4 - Prob. 14ECh. 2.4 - Prob. 15ECh. 2.4 - Prob. 16ECh. 2.4 - Prob. 17ECh. 2.4 - Prob. 18ECh. 2.4 - Prob. 19ECh. 2.4 - Prob. 20ECh. 2.4 - Prob. 21ECh. 2.4 - Prob. 22ECh. 2.4 - Prob. 23ECh. 2.4 - Prob. 24ECh. 2.4 - Prob. 25ECh. 2.4 - Prob. 26ECh. 2.4 - Prob. 27ECh. 2.4 - Prob. 28ECh. 2.4 - Prob. 29ECh. 2.4 - Prob. 30ECh. 2.4 - Prob. 31ECh. 2.4 - Prob. 32ECh. 2.4 - Prob. 33ECh. 2.4 - Prob. 34ECh. 2.4 - Prob. 35ECh. 2.4 - Prob. 36ECh. 2.4 - Prob. 37ECh. 2.4 - Prob. 38ECh. 2.4 - Prob. 39ECh. 2.4 - Prob. 40ECh. 2.4 - Prob. 41ECh. 2.4 - Prob. 42ECh. 2.4 - Prob. 43ECh. 2.4 - Prob. 44ECh. 2.4 - Prob. 45ECh. 2.4 - Prob. 46ECh. 2.4 - Prob. 47ECh. 2.4 - Prob. 48ECh. 2.4 - Prob. 49ECh. 2.4 - Prob. 50ECh. 2.4 - Prob. 51ECh. 2.4 - Prob. 52ECh. 2.4 - Prob. 53ECh. 2.4 - Prob. 54ECh. 2.4 - Prob. 55ECh. 2.4 - Prob. 56ECh. 2.4 - Prob. 57ECh. 2.4 - Prob. 58PSCh. 2.4 - Prob. 59PSCh. 2.4 - Prob. 60PSCh. 2.4 - Prob. 61PSCh. 2.4 - Prob. 62PSCh. 2.4 - Prob. 63PSCh. 2.4 - Prob. 64PSCh. 2.4 - Prob. 65PSCh. 2.4 - Prob. 1PCh. 2.4 - Prob. 2PCh. 2.4 - Prob. 3PCh. 2.4 - Prob. 4PCh. 2.4 - Prob. 5PCh. 2.4 - Prob. 6PCh. 2.4 - Prob. 7PCh. 2.4 - Prob. 8PCh. 2.4 - Prob. 9PCh. 2.4 - Prob. 10PCh. 2.5 - Prob. 1GPCh. 2.5 - Prob. 2GPCh. 2.5 - Prob. 3GPCh. 2.5 - Prob. 4GPCh. 2.5 - Prob. 5GPCh. 2.5 - Prob. 6GPCh. 2.5 - Prob. 7GPCh. 2.5 - Prob. 8GPCh. 2.5 - Prob. 9GPCh. 2.5 - Prob. 1ECh. 2.5 - Prob. 2ECh. 2.5 - Prob. 3ECh. 2.5 - Prob. 4ECh. 2.5 - Prob. 5ECh. 2.5 - Prob. 6ECh. 2.5 - Prob. 7ECh. 2.5 - Prob. 8ECh. 2.5 - Prob. 9ECh. 2.5 - Prob. 10ECh. 2.5 - Prob. 11ECh. 2.5 - Prob. 12ECh. 2.5 - Prob. 13ECh. 2.5 - Prob. 14ECh. 2.5 - Prob. 15ECh. 2.5 - Prob. 16ECh. 2.5 - Prob. 17ECh. 2.5 - Prob. 18ECh. 2.5 - Prob. 19ECh. 2.5 - Prob. 20ECh. 2.5 - Prob. 21ECh. 2.5 - Prob. 22ECh. 2.5 - Prob. 23ECh. 2.5 - Prob. 24ECh. 2.5 - Prob. 25ECh. 2.5 - Prob. 26ECh. 2.5 - Prob. 27ECh. 2.5 - Prob. 28ECh. 2.5 - Prob. 29ECh. 2.5 - Prob. 30ECh. 2.5 - Prob. 31ECh. 2.5 - Prob. 32ECh. 2.5 - Prob. 33ECh. 2.5 - Prob. 34ECh. 2.5 - Prob. 35ECh. 2.5 - Prob. 36ECh. 2.5 - Prob. 37ECh. 2.5 - Prob. 38ECh. 2.5 - Prob. 39ECh. 2.5 - Prob. 40ECh. 2.5 - Prob. 41PSCh. 2.5 - Prob. 42PSCh. 2.5 - Prob. 43PSCh. 2.5 - Prob. 44PSCh. 2.5 - Prob. 45PSCh. 2.5 - Prob. 46PSCh. 2.5 - Prob. 1MRPSCh. 2.5 - Prob. 2MRPSCh. 2.5 - Prob. 3MRPSCh. 2.5 - Prob. 4MRPSCh. 2.5 - Prob. 5MRPSCh. 2.5 - Prob. 6MRPSCh. 2.5 - Prob. 7MRPSCh. 2.6 - Prob. 1GPCh. 2.6 - Prob. 2GPCh. 2.6 - Prob. 3GPCh. 2.6 - Prob. 4GPCh. 2.6 - Prob. 5GPCh. 2.6 - Prob. 6GPCh. 2.6 - Prob. 7GPCh. 2.6 - Prob. 1ECh. 2.6 - Prob. 2ECh. 2.6 - Prob. 3ECh. 2.6 - Prob. 4ECh. 2.6 - Prob. 5ECh. 2.6 - Prob. 6ECh. 2.6 - Prob. 7ECh. 2.6 - Prob. 8ECh. 2.6 - Prob. 9ECh. 2.6 - Prob. 10ECh. 2.6 - Prob. 11ECh. 2.6 - Prob. 12ECh. 2.6 - Prob. 13ECh. 2.6 - Prob. 14ECh. 2.6 - Prob. 15ECh. 2.6 - Prob. 16ECh. 2.6 - Prob. 17ECh. 2.6 - Prob. 18ECh. 2.6 - Prob. 19ECh. 2.6 - Prob. 20ECh. 2.6 - Prob. 21ECh. 2.6 - Prob. 22ECh. 2.6 - Prob. 23ECh. 2.6 - Prob. 24ECh. 2.6 - Prob. 25ECh. 2.6 - Prob. 26ECh. 2.6 - Prob. 27ECh. 2.6 - Prob. 28ECh. 2.6 - Prob. 29ECh. 2.6 - Prob. 30ECh. 2.6 - Prob. 31ECh. 2.6 - Prob. 32ECh. 2.6 - Prob. 33ECh. 2.6 - Prob. 34ECh. 2.6 - Prob. 35ECh. 2.6 - Prob. 36ECh. 2.6 - Prob. 37ECh. 2.6 - Prob. 38ECh. 2.6 - Prob. 39ECh. 2.6 - Prob. 40ECh. 2.6 - Prob. 41ECh. 2.6 - Prob. 42ECh. 2.6 - Prob. 43ECh. 2.6 - Prob. 44ECh. 2.6 - Prob. 45PSCh. 2.6 - Prob. 46PSCh. 2.6 - Prob. 47PSCh. 2.6 - Prob. 48PSCh. 2.6 - Prob. 49PSCh. 2.6 - Prob. 50PSCh. 2.6 - Prob. 51PSCh. 2.6 - Prob. 1QCh. 2.6 - Prob. 2QCh. 2.6 - Prob. 3QCh. 2.6 - Prob. 4QCh. 2.6 - Prob. 5QCh. 2.6 - Prob. 6QCh. 2.6 - Prob. 7QCh. 2.6 - Prob. 8QCh. 2.6 - Prob. 9QCh. 2.6 - Prob. 10QCh. 2.6 - Prob. 11QCh. 2.6 - Prob. 12QCh. 2.6 - Prob. 13QCh. 2.6 - Prob. 1PCh. 2.6 - Prob. 2PCh. 2.6 - Prob. 3PCh. 2.6 - Prob. 4PCh. 2.7 - Prob. 1GPCh. 2.7 - Prob. 2GPCh. 2.7 - Prob. 3GPCh. 2.7 - Prob. 4GPCh. 2.7 - Prob. 5GPCh. 2.7 - Prob. 6GPCh. 2.7 - Prob. 7GPCh. 2.7 - Prob. 8GPCh. 2.7 - Prob. 9GPCh. 2.7 - Prob. 10GPCh. 2.7 - Prob. 11GPCh. 2.7 - Prob. 12GPCh. 2.7 - Prob. 1ECh. 2.7 - Prob. 2ECh. 2.7 - Prob. 3ECh. 2.7 - Prob. 4ECh. 2.7 - Prob. 5ECh. 2.7 - Prob. 6ECh. 2.7 - Prob. 7ECh. 2.7 - Prob. 8ECh. 2.7 - Prob. 9ECh. 2.7 - Prob. 10ECh. 2.7 - Prob. 11ECh. 2.7 - Prob. 12ECh. 2.7 - Prob. 13ECh. 2.7 - Prob. 14ECh. 2.7 - Prob. 15ECh. 2.7 - Prob. 16ECh. 2.7 - Prob. 17ECh. 2.7 - Prob. 18ECh. 2.7 - Prob. 19ECh. 2.7 - Prob. 20ECh. 2.7 - Prob. 21ECh. 2.7 - Prob. 22ECh. 2.7 - Prob. 23ECh. 2.7 - Prob. 24ECh. 2.7 - Prob. 25ECh. 2.7 - Prob. 26ECh. 2.7 - Prob. 27ECh. 2.7 - Prob. 28ECh. 2.7 - Prob. 29ECh. 2.7 - Prob. 30ECh. 2.7 - Prob. 31ECh. 2.7 - Prob. 32ECh. 2.7 - Prob. 33ECh. 2.7 - Prob. 34ECh. 2.7 - Prob. 35ECh. 2.7 - Prob. 36ECh. 2.7 - Prob. 37ECh. 2.7 - Prob. 38ECh. 2.7 - Prob. 39ECh. 2.7 - Prob. 40ECh. 2.7 - Prob. 41ECh. 2.7 - Prob. 42ECh. 2.7 - Prob. 43ECh. 2.7 - Prob. 44ECh. 2.7 - Prob. 45ECh. 2.7 - Prob. 46ECh. 2.7 - Prob. 47ECh. 2.7 - Prob. 48ECh. 2.7 - Prob. 49ECh. 2.7 - Prob. 50ECh. 2.7 - Prob. 51ECh. 2.7 - Prob. 52ECh. 2.7 - Prob. 53ECh. 2.7 - Prob. 54ECh. 2.7 - Prob. 55ECh. 2.7 - Prob. 56ECh. 2.7 - Prob. 57ECh. 2.7 - Prob. 58ECh. 2.7 - Prob. 59PSCh. 2.7 - Prob. 60PSCh. 2.7 - Prob. 61PSCh. 2.7 - Prob. 62PSCh. 2.7 - Prob. 63PSCh. 2.7 - Prob. 64PSCh. 2.7 - Prob. 65PSCh. 2.8 - Prob. 1GPCh. 2.8 - Prob. 2GPCh. 2.8 - Prob. 3GPCh. 2.8 - Prob. 4GPCh. 2.8 - Prob. 5GPCh. 2.8 - Prob. 1ECh. 2.8 - Prob. 2ECh. 2.8 - Prob. 3ECh. 2.8 - Prob. 4ECh. 2.8 - Prob. 5ECh. 2.8 - Prob. 6ECh. 2.8 - Prob. 7ECh. 2.8 - Prob. 8ECh. 2.8 - Prob. 9ECh. 2.8 - Prob. 10ECh. 2.8 - Prob. 11ECh. 2.8 - Prob. 12ECh. 2.8 - Prob. 13ECh. 2.8 - Prob. 14ECh. 2.8 - Prob. 15ECh. 2.8 - Prob. 16ECh. 2.8 - Prob. 17ECh. 2.8 - Prob. 18ECh. 2.8 - Prob. 19ECh. 2.8 - Prob. 20ECh. 2.8 - Prob. 21ECh. 2.8 - Prob. 22ECh. 2.8 - Prob. 23ECh. 2.8 - Prob. 24ECh. 2.8 - Prob. 25ECh. 2.8 - Prob. 26ECh. 2.8 - Prob. 27ECh. 2.8 - Prob. 28ECh. 2.8 - Prob. 29ECh. 2.8 - Prob. 30ECh. 2.8 - Prob. 31ECh. 2.8 - Prob. 32ECh. 2.8 - Prob. 33ECh. 2.8 - Prob. 34ECh. 2.8 - Prob. 35ECh. 2.8 - Prob. 36ECh. 2.8 - Prob. 37ECh. 2.8 - Prob. 38ECh. 2.8 - Prob. 39PSCh. 2.8 - Prob. 40PSCh. 2.8 - Prob. 41PSCh. 2.8 - Prob. 42PSCh. 2.8 - Prob. 43PSCh. 2.8 - Prob. 44PSCh. 2.8 - Prob. 1QCh. 2.8 - Prob. 2QCh. 2.8 - Prob. 3QCh. 2.8 - Prob. 4QCh. 2.8 - Prob. 5QCh. 2.8 - Prob. 6QCh. 2.8 - Prob. 7QCh. 2.8 - Prob. 8QCh. 2.8 - Prob. 9QCh. 2.8 - Prob. 10QCh. 2.8 - Prob. 1MRPSCh. 2.8 - Prob. 2MRPSCh. 2.8 - Prob. 3MRPSCh. 2.8 - Prob. 4MRPSCh. 2.8 - Prob. 5MRPSCh. 2.8 - Prob. 6MRPSCh. 2.8 - Prob. 7MRPSCh. 2 - Prob. 1VECh. 2 - Prob. 2VECh. 2 - Prob. 3VECh. 2 - Prob. 4VECh. 2 - Prob. 5REAECh. 2 - Prob. 6REAECh. 2 - Prob. 7REAECh. 2 - Prob. 8REAECh. 2 - Prob. 9REAECh. 2 - Prob. 10REAECh. 2 - Prob. 11REAECh. 2 - Prob. 12REAECh. 2 - Prob. 13REAECh. 2 - Prob. 14REAECh. 2 - Prob. 15REAECh. 2 - Prob. 16REAECh. 2 - Prob. 17REAECh. 2 - Prob. 18REAECh. 2 - Prob. 19REAECh. 2 - Prob. 20REAECh. 2 - Prob. 21REAECh. 2 - Prob. 22REAECh. 2 - Prob. 23REAECh. 2 - Prob. 24REAECh. 2 - Prob. 25REAECh. 2 - Prob. 26REAECh. 2 - Prob. 27REAECh. 2 - Prob. 28REAECh. 2 - Prob. 29REAECh. 2 - Prob. 30REAECh. 2 - Prob. 31REAECh. 2 - Prob. 32REAECh. 2 - Prob. 33REAECh. 2 - Prob. 34REAECh. 2 - Prob. 35REAECh. 2 - Prob. 36REAECh. 2 - Prob. 37REAECh. 2 - Prob. 38REAECh. 2 - Prob. 39REAECh. 2 - Prob. 40REAECh. 2 - Prob. 1TCh. 2 - Prob. 2TCh. 2 - Prob. 3TCh. 2 - Prob. 4TCh. 2 - Prob. 5TCh. 2 - Prob. 6TCh. 2 - Prob. 7TCh. 2 - Prob. 8TCh. 2 - Prob. 9TCh. 2 - Prob. 10TCh. 2 - Prob. 11TCh. 2 - Prob. 12TCh. 2 - Prob. 13TCh. 2 - Prob. 14TCh. 2 - Prob. 15TCh. 2 - Prob. 16TCh. 2 - Prob. 17TCh. 2 - Prob. 18TCh. 2 - Prob. 19TCh. 2 - Prob. 20TCh. 2 - Prob. 21TCh. 2 - Prob. 22TCh. 2 - Prob. 23TCh. 2 - Prob. 24TCh. 2 - Prob. 25TCh. 2 - Prob. 26TCh. 2 - Prob. 27TCh. 2 - Prob. 28TCh. 2 - Prob. 29TCh. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 1TPCh. 2 - Prob. 2TPCh. 2 - Prob. 3TPCh. 2 - Prob. 4TPCh. 2 - Prob. 5TPCh. 2 - Prob. 6TPCh. 2 - Prob. 7TPCh. 2 - Prob. 8TPCh. 2 - Prob. 9TPCh. 2 - Prob. 10TPCh. 2 - Prob. 11TPCh. 2 - Prob. 12TPCh. 2 - Prob. 13TPCh. 2 - Prob. 14TPCh. 2 - Prob. 15TPCh. 2 - Prob. 16TPCh. 2 - Prob. 17TPCh. 2 - Prob. 18TPCh. 2 - Prob. 19TPCh. 2 - Prob. 20TPCh. 2 - Prob. 21TP
Knowledge Booster
Background pattern image
Algebra
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Algebra and Trigonometry (6th Edition)
Algebra
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:PEARSON
Text book image
Contemporary Abstract Algebra
Algebra
ISBN:9781305657960
Author:Joseph Gallian
Publisher:Cengage Learning
Text book image
Linear Algebra: A Modern Introduction
Algebra
ISBN:9781285463247
Author:David Poole
Publisher:Cengage Learning
Text book image
Algebra And Trigonometry (11th Edition)
Algebra
ISBN:9780135163078
Author:Michael Sullivan
Publisher:PEARSON
Text book image
Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:9780980232776
Author:Gilbert Strang
Publisher:Wellesley-Cambridge Press
Text book image
College Algebra (Collegiate Math)
Algebra
ISBN:9780077836344
Author:Julie Miller, Donna Gerken
Publisher:McGraw-Hill Education
SEE MORE TEXTBOOKS
Use of ALGEBRA in REAL LIFE; Author: Fast and Easy Maths !;https://www.youtube.com/watch?v=9_PbWFpvkDc;License: Standard YouTube License, CC-BY
Compound Interest Formula Explained, Investment, Monthly & Continuously, Word Problems, Algebra; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=P182Abv3fOk;License: Standard YouTube License, CC-BY
Applications of Algebra (Digit, Age, Work, Clock, Mixture and Rate Problems); Author: EngineerProf PH;https://www.youtube.com/watch?v=Y8aJ_wYCS2g;License: Standard YouTube License, CC-BY