Holt Mcdougal Larson Algebra 2: Student Edition 2012
1st Edition
ISBN: 9780547647159
Author: HOLT MCDOUGAL
Publisher: HOLT MCDOUGAL
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Expert Solution & Answer
Chapter 2, Problem 21TP
Solution
(a.)
A model for the total number of hospital beds in U.S. hospitals.
It has been determined that the model for the total number of hospital beds in United States from 1980 to 2002, is given as P=(−58.7t+7070)(0.0066t3−0.192t2−0.174t+196) , where t is the number of years since 1980.
Given:
The number of hospitals in the United States from 1980 to 2002 is given as,
H=−58.7t+7070
The average number of hospital beds in each hospital from 1980 to 2002 is given as,
B=0.0066t3−0.192t2−0.174t+196
Here, t is the number of years since 1980.
Concept used:
The total number of hospital beds is the product of the average number of hospital beds in each hospital and the total number of hospitals.
Calculation:
The number of hospitals in the United States from 1980 to 2002 is given as,
H=−58.7t+7070
The average number of hospital beds in each hospital from 1980 to 2002 is given as,
B=0.0066t3−0.192t2−0.174t+196
Then, it follows that the total number of hospital beds from 1980 to 2002 is given as,
P=HB
Put the required values in the above expression to get,
P=(−58.7t+7070)(0.0066t3−0.192t2−0.174t+196)
Here, t is the number of years since 1980.
This is the required model for the total number of hospital beds in United States from 1980 to 2002.
Conclusion:
It has been determined that the model for the total number of hospital beds in United States from 1980 to 2002, is given as P=(−58.7t+7070)(0.0066t3−0.192t2−0.174t+196) , where t is the number of years since 1980.
(b.)
The number of beds in the U.S. hospitals in 1995, according to the obtained model.
It has been determined that the number of beds in the U.S. hospitals in 1995, according to the obtained model, is 1067472 .
Given:
The number of hospitals in the United States from 1980 to 2002 is given as,
H=−58.7t+7070
The average number of hospital beds in each hospital from 1980 to 2002 is given as,
B=0.0066t3−0.192t2−0.174t+196
Here, t is the number of years since 1980.
Concept used:
The number of beds in the U.S. hospitals in 1995, according to the obtained model, can be determined by plugging in the required value of t in the model.
Calculation:
As determined previously, in part (a), the model for the total number of hospital beds in United States from 1980 to 2002, is given as,
P=(−58.7t+7070)(0.0066t3−0.192t2−0.174t+196) , where t is the number of years since 1980.
Then, the year 1995 is represented by t=1995−1980=15 .
Put t=15 in the obtained model to get,
P(15)=(−58.7(15)+7070)(0.0066(15)3−0.192(15)2−0.174(15)+196)=(−880.5+7070)(0.0066(3375)−0.192(225)−2.61+196)=(6189.5)(22.275−43.2−2.61+196)=(6189.5)(172.465)
Solving,
P(15)=1067472.1175
This implies that the number of beds in the U.S. hospitals in 1995, according to the obtained model, is 1067472.1175 .
Since the number of beds must be a whole number, the obtained value can be rounded off to the nearest whole number to get the number of beds in the U.S. hospitals in 1995, according to the obtained model as 1067472 .
Conclusion:
It has been determined that the number of beds in the U.S. hospitals in 1995, according to the obtained model, is 1067472 .
(c.)
How the model changes if the number of hospital beds is required in thousands.
It has been determined that the model for the number of beds in the U.S. hospitals in thousands, is given as P=(−58.7t+7070)(0.0066t3−0.192t2−0.174t+196)1000 , where t is the number of years since 1980.
Given:
The number of hospitals in the United States from 1980 to 2002 is given as,
H=−58.7t+7070
The average number of hospital beds in each hospital from 1980 to 2002 is given as,
B=0.0066t3−0.192t2−0.174t+196
Here, t is the number of years since 1980.
Concept used:
If the number of hospital beds is required in thousands, then the obtained model which gives the number of hospital beds in units has to be divided by thousand.
Calculation:
As determined previously, in part (a), the model for the total number of hospital beds in United States from 1980 to 2002, is given as,
P=(−58.7t+7070)(0.0066t3−0.192t2−0.174t+196) , where t is the number of years since 1980.
If the number of hospital beds is determined in thousands, then multiplying it by thousand should give the number of hospital beds in units.
Then, the obtained model which gives the number of hospital beds in units should be divided by thousand to produce the model which gives the number of hospital beds in thousands.
So, the required model is,
P=(−58.7t+7070)(0.0066t3−0.192t2−0.174t+196)1000 , where t is the number of years since 1980.
Conclusion:
It has been determined that the model for the number of beds in the U.S. hospitals in thousands, is given as P=(−58.7t+7070)(0.0066t3−0.192t2−0.174t+196)1000 , where t is the number of years since 1980.
Chapter 2 Solutions
Holt Mcdougal Larson Algebra 2: Student Edition 2012
Ch. 2.1 - Prob. 1GPCh. 2.1 - Prob. 2GPCh. 2.1 - Prob. 3GPCh. 2.1 - Prob. 4GPCh. 2.1 - Prob. 5GPCh. 2.1 - Prob. 6GPCh. 2.1 - Prob. 7GPCh. 2.1 - Prob. 8GPCh. 2.1 - Prob. 1ECh. 2.1 - Prob. 2E
Ch. 2.1 - Prob. 3ECh. 2.1 - Prob. 4ECh. 2.1 - Prob. 5ECh. 2.1 - Prob. 6ECh. 2.1 - Prob. 7ECh. 2.1 - Prob. 8ECh. 2.1 - Prob. 9ECh. 2.1 - Prob. 10ECh. 2.1 - Prob. 11ECh. 2.1 - Prob. 12ECh. 2.1 - Prob. 13ECh. 2.1 - Prob. 14ECh. 2.1 - Prob. 15ECh. 2.1 - Prob. 16ECh. 2.1 - Prob. 17ECh. 2.1 - Prob. 18ECh. 2.1 - Prob. 19ECh. 2.1 - Prob. 20ECh. 2.1 - Prob. 21ECh. 2.1 - Prob. 22ECh. 2.1 - Prob. 23ECh. 2.1 - Prob. 24ECh. 2.1 - Prob. 25ECh. 2.1 - Prob. 26ECh. 2.1 - Prob. 27ECh. 2.1 - Prob. 28ECh. 2.1 - Prob. 29ECh. 2.1 - Prob. 30ECh. 2.1 - Prob. 31ECh. 2.1 - Prob. 32ECh. 2.1 - Prob. 33ECh. 2.1 - Prob. 34ECh. 2.1 - Prob. 35ECh. 2.1 - Prob. 36ECh. 2.1 - Prob. 37ECh. 2.1 - Prob. 38ECh. 2.1 - Prob. 39ECh. 2.1 - Prob. 40ECh. 2.1 - Prob. 41ECh. 2.1 - Prob. 42ECh. 2.1 - Prob. 43ECh. 2.1 - Prob. 44ECh. 2.1 - Prob. 45ECh. 2.1 - Prob. 46ECh. 2.1 - Prob. 47ECh. 2.1 - Prob. 48ECh. 2.1 - Prob. 49PSCh. 2.1 - Prob. 50PSCh. 2.1 - Prob. 51PSCh. 2.1 - Prob. 52PSCh. 2.1 - Prob. 53PSCh. 2.1 - Prob. 54PSCh. 2.1 - Prob. 1DCCh. 2.1 - 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Prob. 37ECh. 2.2 - Prob. 38ECh. 2.2 - Prob. 39ECh. 2.2 - Prob. 40ECh. 2.2 - Prob. 41ECh. 2.2 - Prob. 42ECh. 2.2 - Prob. 43ECh. 2.2 - Prob. 44ECh. 2.2 - Prob. 45ECh. 2.2 - Prob. 46ECh. 2.2 - Prob. 47ECh. 2.2 - Prob. 48ECh. 2.2 - Prob. 49ECh. 2.2 - Prob. 50ECh. 2.2 - Prob. 51ECh. 2.2 - Prob. 52ECh. 2.2 - Prob. 53ECh. 2.2 - Prob. 54PSCh. 2.2 - Prob. 55PSCh. 2.2 - Prob. 56PSCh. 2.2 - Prob. 57PSCh. 2.2 - Prob. 58PSCh. 2.2 - Prob. 59PSCh. 2.2 - Prob. 60PSCh. 2.2 - Prob. 1PCh. 2.2 - Prob. 2PCh. 2.2 - Prob. 3PCh. 2.2 - Prob. 4PCh. 2.2 - Prob. 5PCh. 2.2 - Prob. 6PCh. 2.2 - Prob. 7PCh. 2.2 - Prob. 8PCh. 2.2 - Prob. 9PCh. 2.2 - Prob. 10PCh. 2.3 - Prob. 1GPCh. 2.3 - Prob. 2GPCh. 2.3 - Prob. 3GPCh. 2.3 - Prob. 4GPCh. 2.3 - Prob. 5GPCh. 2.3 - Prob. 6GPCh. 2.3 - Prob. 1ECh. 2.3 - Prob. 2ECh. 2.3 - Prob. 3ECh. 2.3 - Prob. 4ECh. 2.3 - Prob. 5ECh. 2.3 - Prob. 6ECh. 2.3 - Prob. 7ECh. 2.3 - Prob. 8ECh. 2.3 - Prob. 9ECh. 2.3 - Prob. 10ECh. 2.3 - Prob. 11ECh. 2.3 - Prob. 12ECh. 2.3 - Prob. 13ECh. 2.3 - Prob. 14ECh. 2.3 - 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Prob. 9GPCh. 2.5 - Prob. 1ECh. 2.5 - Prob. 2ECh. 2.5 - Prob. 3ECh. 2.5 - Prob. 4ECh. 2.5 - Prob. 5ECh. 2.5 - Prob. 6ECh. 2.5 - Prob. 7ECh. 2.5 - Prob. 8ECh. 2.5 - Prob. 9ECh. 2.5 - Prob. 10ECh. 2.5 - Prob. 11ECh. 2.5 - Prob. 12ECh. 2.5 - Prob. 13ECh. 2.5 - Prob. 14ECh. 2.5 - Prob. 15ECh. 2.5 - Prob. 16ECh. 2.5 - Prob. 17ECh. 2.5 - Prob. 18ECh. 2.5 - Prob. 19ECh. 2.5 - Prob. 20ECh. 2.5 - Prob. 21ECh. 2.5 - Prob. 22ECh. 2.5 - Prob. 23ECh. 2.5 - Prob. 24ECh. 2.5 - Prob. 25ECh. 2.5 - Prob. 26ECh. 2.5 - Prob. 27ECh. 2.5 - Prob. 28ECh. 2.5 - Prob. 29ECh. 2.5 - Prob. 30ECh. 2.5 - Prob. 31ECh. 2.5 - Prob. 32ECh. 2.5 - Prob. 33ECh. 2.5 - Prob. 34ECh. 2.5 - Prob. 35ECh. 2.5 - Prob. 36ECh. 2.5 - Prob. 37ECh. 2.5 - Prob. 38ECh. 2.5 - Prob. 39ECh. 2.5 - Prob. 40ECh. 2.5 - Prob. 41PSCh. 2.5 - Prob. 42PSCh. 2.5 - Prob. 43PSCh. 2.5 - Prob. 44PSCh. 2.5 - Prob. 45PSCh. 2.5 - Prob. 46PSCh. 2.5 - Prob. 1MRPSCh. 2.5 - Prob. 2MRPSCh. 2.5 - Prob. 3MRPSCh. 2.5 - Prob. 4MRPSCh. 2.5 - Prob. 5MRPSCh. 2.5 - Prob. 6MRPSCh. 2.5 - Prob. 7MRPSCh. 2.6 - Prob. 1GPCh. 2.6 - Prob. 2GPCh. 2.6 - Prob. 3GPCh. 2.6 - Prob. 4GPCh. 2.6 - Prob. 5GPCh. 2.6 - Prob. 6GPCh. 2.6 - Prob. 7GPCh. 2.6 - Prob. 1ECh. 2.6 - Prob. 2ECh. 2.6 - Prob. 3ECh. 2.6 - Prob. 4ECh. 2.6 - Prob. 5ECh. 2.6 - Prob. 6ECh. 2.6 - Prob. 7ECh. 2.6 - Prob. 8ECh. 2.6 - Prob. 9ECh. 2.6 - Prob. 10ECh. 2.6 - Prob. 11ECh. 2.6 - Prob. 12ECh. 2.6 - Prob. 13ECh. 2.6 - Prob. 14ECh. 2.6 - Prob. 15ECh. 2.6 - Prob. 16ECh. 2.6 - Prob. 17ECh. 2.6 - Prob. 18ECh. 2.6 - Prob. 19ECh. 2.6 - Prob. 20ECh. 2.6 - Prob. 21ECh. 2.6 - Prob. 22ECh. 2.6 - Prob. 23ECh. 2.6 - Prob. 24ECh. 2.6 - Prob. 25ECh. 2.6 - Prob. 26ECh. 2.6 - Prob. 27ECh. 2.6 - Prob. 28ECh. 2.6 - Prob. 29ECh. 2.6 - Prob. 30ECh. 2.6 - Prob. 31ECh. 2.6 - Prob. 32ECh. 2.6 - Prob. 33ECh. 2.6 - Prob. 34ECh. 2.6 - Prob. 35ECh. 2.6 - Prob. 36ECh. 2.6 - Prob. 37ECh. 2.6 - Prob. 38ECh. 2.6 - Prob. 39ECh. 2.6 - Prob. 40ECh. 2.6 - Prob. 41ECh. 2.6 - Prob. 42ECh. 2.6 - Prob. 43ECh. 2.6 - Prob. 44ECh. 2.6 - Prob. 45PSCh. 2.6 - Prob. 46PSCh. 2.6 - Prob. 47PSCh. 2.6 - Prob. 48PSCh. 2.6 - Prob. 49PSCh. 2.6 - Prob. 50PSCh. 2.6 - Prob. 51PSCh. 2.6 - Prob. 1QCh. 2.6 - Prob. 2QCh. 2.6 - Prob. 3QCh. 2.6 - Prob. 4QCh. 2.6 - Prob. 5QCh. 2.6 - Prob. 6QCh. 2.6 - Prob. 7QCh. 2.6 - Prob. 8QCh. 2.6 - Prob. 9QCh. 2.6 - Prob. 10QCh. 2.6 - Prob. 11QCh. 2.6 - Prob. 12QCh. 2.6 - Prob. 13QCh. 2.6 - Prob. 1PCh. 2.6 - Prob. 2PCh. 2.6 - Prob. 3PCh. 2.6 - Prob. 4PCh. 2.7 - Prob. 1GPCh. 2.7 - Prob. 2GPCh. 2.7 - Prob. 3GPCh. 2.7 - Prob. 4GPCh. 2.7 - Prob. 5GPCh. 2.7 - Prob. 6GPCh. 2.7 - Prob. 7GPCh. 2.7 - Prob. 8GPCh. 2.7 - Prob. 9GPCh. 2.7 - Prob. 10GPCh. 2.7 - Prob. 11GPCh. 2.7 - Prob. 12GPCh. 2.7 - Prob. 1ECh. 2.7 - Prob. 2ECh. 2.7 - Prob. 3ECh. 2.7 - Prob. 4ECh. 2.7 - Prob. 5ECh. 2.7 - Prob. 6ECh. 2.7 - Prob. 7ECh. 2.7 - Prob. 8ECh. 2.7 - Prob. 9ECh. 2.7 - Prob. 10ECh. 2.7 - Prob. 11ECh. 2.7 - Prob. 12ECh. 2.7 - Prob. 13ECh. 2.7 - Prob. 14ECh. 2.7 - Prob. 15ECh. 2.7 - Prob. 16ECh. 2.7 - Prob. 17ECh. 2.7 - Prob. 18ECh. 2.7 - Prob. 19ECh. 2.7 - Prob. 20ECh. 2.7 - Prob. 21ECh. 2.7 - Prob. 22ECh. 2.7 - Prob. 23ECh. 2.7 - Prob. 24ECh. 2.7 - Prob. 25ECh. 2.7 - Prob. 26ECh. 2.7 - Prob. 27ECh. 2.7 - Prob. 28ECh. 2.7 - Prob. 29ECh. 2.7 - Prob. 30ECh. 2.7 - Prob. 31ECh. 2.7 - Prob. 32ECh. 2.7 - Prob. 33ECh. 2.7 - Prob. 34ECh. 2.7 - Prob. 35ECh. 2.7 - Prob. 36ECh. 2.7 - Prob. 37ECh. 2.7 - Prob. 38ECh. 2.7 - Prob. 39ECh. 2.7 - Prob. 40ECh. 2.7 - Prob. 41ECh. 2.7 - Prob. 42ECh. 2.7 - Prob. 43ECh. 2.7 - Prob. 44ECh. 2.7 - Prob. 45ECh. 2.7 - Prob. 46ECh. 2.7 - Prob. 47ECh. 2.7 - Prob. 48ECh. 2.7 - Prob. 49ECh. 2.7 - Prob. 50ECh. 2.7 - Prob. 51ECh. 2.7 - Prob. 52ECh. 2.7 - Prob. 53ECh. 2.7 - Prob. 54ECh. 2.7 - Prob. 55ECh. 2.7 - Prob. 56ECh. 2.7 - Prob. 57ECh. 2.7 - Prob. 58ECh. 2.7 - Prob. 59PSCh. 2.7 - Prob. 60PSCh. 2.7 - Prob. 61PSCh. 2.7 - Prob. 62PSCh. 2.7 - Prob. 63PSCh. 2.7 - Prob. 64PSCh. 2.7 - Prob. 65PSCh. 2.8 - Prob. 1GPCh. 2.8 - Prob. 2GPCh. 2.8 - Prob. 3GPCh. 2.8 - Prob. 4GPCh. 2.8 - Prob. 5GPCh. 2.8 - Prob. 1ECh. 2.8 - Prob. 2ECh. 2.8 - Prob. 3ECh. 2.8 - Prob. 4ECh. 2.8 - Prob. 5ECh. 2.8 - Prob. 6ECh. 2.8 - Prob. 7ECh. 2.8 - Prob. 8ECh. 2.8 - Prob. 9ECh. 2.8 - Prob. 10ECh. 2.8 - Prob. 11ECh. 2.8 - Prob. 12ECh. 2.8 - Prob. 13ECh. 2.8 - Prob. 14ECh. 2.8 - Prob. 15ECh. 2.8 - Prob. 16ECh. 2.8 - Prob. 17ECh. 2.8 - Prob. 18ECh. 2.8 - Prob. 19ECh. 2.8 - Prob. 20ECh. 2.8 - Prob. 21ECh. 2.8 - Prob. 22ECh. 2.8 - Prob. 23ECh. 2.8 - Prob. 24ECh. 2.8 - Prob. 25ECh. 2.8 - Prob. 26ECh. 2.8 - Prob. 27ECh. 2.8 - Prob. 28ECh. 2.8 - Prob. 29ECh. 2.8 - Prob. 30ECh. 2.8 - Prob. 31ECh. 2.8 - Prob. 32ECh. 2.8 - Prob. 33ECh. 2.8 - Prob. 34ECh. 2.8 - Prob. 35ECh. 2.8 - Prob. 36ECh. 2.8 - Prob. 37ECh. 2.8 - Prob. 38ECh. 2.8 - Prob. 39PSCh. 2.8 - Prob. 40PSCh. 2.8 - Prob. 41PSCh. 2.8 - Prob. 42PSCh. 2.8 - Prob. 43PSCh. 2.8 - Prob. 44PSCh. 2.8 - Prob. 1QCh. 2.8 - Prob. 2QCh. 2.8 - Prob. 3QCh. 2.8 - Prob. 4QCh. 2.8 - Prob. 5QCh. 2.8 - Prob. 6QCh. 2.8 - Prob. 7QCh. 2.8 - Prob. 8QCh. 2.8 - Prob. 9QCh. 2.8 - Prob. 10QCh. 2.8 - Prob. 1MRPSCh. 2.8 - Prob. 2MRPSCh. 2.8 - Prob. 3MRPSCh. 2.8 - Prob. 4MRPSCh. 2.8 - Prob. 5MRPSCh. 2.8 - Prob. 6MRPSCh. 2.8 - Prob. 7MRPSCh. 2 - Prob. 1VECh. 2 - Prob. 2VECh. 2 - Prob. 3VECh. 2 - Prob. 4VECh. 2 - Prob. 5REAECh. 2 - Prob. 6REAECh. 2 - Prob. 7REAECh. 2 - Prob. 8REAECh. 2 - Prob. 9REAECh. 2 - Prob. 10REAECh. 2 - Prob. 11REAECh. 2 - Prob. 12REAECh. 2 - Prob. 13REAECh. 2 - Prob. 14REAECh. 2 - Prob. 15REAECh. 2 - Prob. 16REAECh. 2 - Prob. 17REAECh. 2 - Prob. 18REAECh. 2 - Prob. 19REAECh. 2 - Prob. 20REAECh. 2 - Prob. 21REAECh. 2 - Prob. 22REAECh. 2 - Prob. 23REAECh. 2 - Prob. 24REAECh. 2 - Prob. 25REAECh. 2 - Prob. 26REAECh. 2 - Prob. 27REAECh. 2 - Prob. 28REAECh. 2 - Prob. 29REAECh. 2 - Prob. 30REAECh. 2 - Prob. 31REAECh. 2 - Prob. 32REAECh. 2 - Prob. 33REAECh. 2 - Prob. 34REAECh. 2 - Prob. 35REAECh. 2 - Prob. 36REAECh. 2 - Prob. 37REAECh. 2 - Prob. 38REAECh. 2 - Prob. 39REAECh. 2 - Prob. 40REAECh. 2 - Prob. 1TCh. 2 - Prob. 2TCh. 2 - Prob. 3TCh. 2 - Prob. 4TCh. 2 - Prob. 5TCh. 2 - Prob. 6TCh. 2 - Prob. 7TCh. 2 - Prob. 8TCh. 2 - Prob. 9TCh. 2 - Prob. 10TCh. 2 - Prob. 11TCh. 2 - Prob. 12TCh. 2 - Prob. 13TCh. 2 - Prob. 14TCh. 2 - Prob. 15TCh. 2 - Prob. 16TCh. 2 - Prob. 17TCh. 2 - Prob. 18TCh. 2 - Prob. 19TCh. 2 - Prob. 20TCh. 2 - Prob. 21TCh. 2 - Prob. 22TCh. 2 - Prob. 23TCh. 2 - Prob. 24TCh. 2 - Prob. 25TCh. 2 - Prob. 26TCh. 2 - Prob. 27TCh. 2 - Prob. 28TCh. 2 - Prob. 29TCh. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 1TPCh. 2 - Prob. 2TPCh. 2 - Prob. 3TPCh. 2 - Prob. 4TPCh. 2 - Prob. 5TPCh. 2 - Prob. 6TPCh. 2 - Prob. 7TPCh. 2 - Prob. 8TPCh. 2 - Prob. 9TPCh. 2 - Prob. 10TPCh. 2 - Prob. 11TPCh. 2 - Prob. 12TPCh. 2 - Prob. 13TPCh. 2 - Prob. 14TPCh. 2 - Prob. 15TPCh. 2 - Prob. 16TPCh. 2 - Prob. 17TPCh. 2 - Prob. 18TPCh. 2 - Prob. 19TPCh. 2 - Prob. 20TPCh. 2 - Prob. 21TP
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- Can you help me solve this?arrow_forwardName Assume there is the following simplified grade book: Homework Labs | Final Exam | Project Avery 95 98 90 100 Blake 90 96 Carlos 83 79 Dax 55 30 228 92 95 79 90 65 60 Assume that the weights used to compute the final grades are homework 0.3, labs 0.2, the final 0.35, and the project 0.15. | Write an explicit formula to compute Avery's final grade using a single inner product. Write an explicit formula to compute everyone's final grade simultane- ously using a single matrix-vector product.arrow_forward1. Explicitly compute by hand (with work shown) the following Frobenius inner products 00 4.56 3.12 (a) ((º º º). (156 (b) 10.9 -1 0 2)), Fro 5')) Froarrow_forward
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