You will need to refer to question 2 in More Genetic TIPS to answer this question. The gene for coat color in rabbits can exist in four alleles termed C (full coat color), c c h (chinchilla), c h (Himalayan), and c (albino). In a population of rabbits in Hardy-Weinberg equilibrium, the allele frequencies are C = 0.34 c c h = 0.17 c h = 0.44 c = 0.05 Assume that C is dominant to the other three alleles, c c h is dominant to c h and c , and c h is dominant to c . A. What is the frequency of albino rabbits? B. Among 1000 rabbits, how many would you expect to have a Himalayan coat color? C. Among 1000 rabbits, how many would be heterozygotes with a chinchilla coat color?

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Answer 1

Textbook Question

Chapter 27, Problem 2EQ

You will need to refer to question 2 in More Genetic TIPS to answer this question. The gene for coat color in rabbits can exist in four alleles termed C(full coat color), $c c h$ (chinchilla), $c h$ (Himalayan), and c (albino). In a population of rabbits in Hardy-Weinberg equilibrium, the allele frequencies are

$C = 0.34$

$c c h = 0.17$

$c h = 0.44$

$c = 0.05$

Assume that C is dominant to the other three alleles, $c c h$ is dominant to $c h$ and c, and $c h$ is dominant to c.

A. What is the frequency of albino rabbits?

B. Among 1000 rabbits, how many would you expect to have a Himalayan coat color?

C. Among 1000 rabbits, how many would be heterozygotes with a chinchilla coat color?

Expert Solution & Answer

Summary Introduction

To review:

In a population of rabbits in Hardy-Weinberg equilibrium, determinethe:

Frequency of albino rabbits

Number of rabbits to have a Himalayan coat color

Number of rabbits to be heterozygous with a chinchilla coat color

Introduction:

The Hardy-Weinberg equilibrium is a principle, which states that in a given population, the frequency of occurrence of alleles of a gene or a locus can be determined. The frequency is supposed to remain fixed and even remain the same throughout the generation. In other words, the principle says that allele frequency in a population is stable and is constant from generation to generation.

Explanation of Solution

The Hardy- Weinberg equation in its standard form (two-allele) indicates that each individual inherits two copies of each gene, one from each parent. For a two-allele condition, it can also be expressed as $(p+q)2=1$ .

This equation can be expanded to include three or more than three alleles. For the given situation in the question, there a gene exists as four alleles: C(full coat color), c^ch (chinchilla), c^h (Himalayan), and c (albino). The allele frequency of C is designated by the letter p, c^ch by the letter q, c^h by the letter r, and c by the letter s.The allele frequencies are listed below:

$C=0.34cch=0.17ch=0.44c=0.05$

Under these conditions, the Hardy- Weinberg equation can be written as follows:

$(p+q+r+s)2=1p2+q2+r2+s2+2pq+2qr+2pr+2ps+2rs+2qs=1$ .

where,

p² is the genotype of the frequency of CC

q² is the genotype frequency of c^chc^ch

r² is the genotype frequency of c^hc^h

s² is the genotype frequency of cc

2pq is the genotype frequency of Cc^ch

2qr is the genotype frequency of c^chc^h

2pr is the genotype frequency of Cc^h

2ps is the genotype frequency of Cc

2rs is the genotype frequency of c^hc

2qs is the genotype frequency of c^chc

Now,

$p2(the genotype frequency of CC, which produces full coat color)=(0.34)2p2=0.1156$

$q2(the genotype frequency of cchcch, which produces chinchilla coat color)=(0.17)2q2=0.0289$ $r2(the genotype frequency of chch, which produces Himalayan coat color)=(0.44)2r2=0.1936$ $s2 is the genotype frequency of cc, which produces albino coat color)=(0.05)2s2=0.0025$ $2pq (the genotype frequency of Ccch, which produces full coat color)=2(0.34)(0.17)2pq=0.1156$ $2qr (the genotype frequency of cchch, which produces chinchilla coat color)=2(0.17)(0.44) 2qr=0.1496$ $2pr (the genotype frequency of Cch, which produces full coat color)=2(0.34)(0.44) 2pr=0.2992$ $2ps (the genotype frequency of Cc, which produces full coat color)=2(0.34)(0.05) 2ps =0.034$

$2rs (the genotype frequency of chc, which produces Himalayan coat color)=2(0.44)(0.05) 2rs=0.044$ $2qs (the genotype frequency of cchc, which produces chinchilla coat color)=2(0.17)(0.05)2qs=0.017$

The frequency of albino rabbits is s², which is equal to 0.0025 or 0.25%.\

$Frequency of rabbits with Himalayan coat color=0.1936+0.044 Frequency of rabbits with Himalayan coat color=0.2376 or 23.76%.$

$Among 1000 rabbits, the number of rabbits with Himalayan coat color=23.76% of 1000Thus, the number of rabbits with Himalayan coat color=237.6 or 237 (approx.)$

C.

$Frequency of rabbits that are heterozygotes with chinchilla coat color=0.1496+0.017 frequency of rabbits that are heterozygotes with chinchilla coat color=0.1666 or 16.66%$

The number of rabbits that are heterozygotes with chinchilla coat color among 1000 rabbits can be calculated as follows:

$The number of rabbits that are heterozygotes with chinchilla coat color=16.66% of 1000The number of rabbits that are heterozygotes with chinchilla coat color=166.6 or 166(approx.)$

Conclusion

Therefore, it can be concluded that the frequency of the albino rabbits is 0.0025 or 0.25%.The number of rabbits with a Himalayan coat color would be 237 (approx.).The number of rabbits that are heterozygotes with chinchilla coat color would be 166 (approx.).

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Answer 2

Textbook Question

Chapter 27, Problem 2EQ

You will need to refer to question 2 in More Genetic TIPS to answer this question. The gene for coat color in rabbits can exist in four alleles termed C(full coat color), $c c h$ (chinchilla), $c h$ (Himalayan), and c (albino). In a population of rabbits in Hardy-Weinberg equilibrium, the allele frequencies are

$C = 0.34$

$c c h = 0.17$

$c h = 0.44$

$c = 0.05$

Assume that C is dominant to the other three alleles, $c c h$ is dominant to $c h$ and c, and $c h$ is dominant to c.

A. What is the frequency of albino rabbits?

B. Among 1000 rabbits, how many would you expect to have a Himalayan coat color?

C. Among 1000 rabbits, how many would be heterozygotes with a chinchilla coat color?

Expert Solution & Answer

Summary Introduction

To review:

In a population of rabbits in Hardy-Weinberg equilibrium, determinethe:

Frequency of albino rabbits

Number of rabbits to have a Himalayan coat color

Number of rabbits to be heterozygous with a chinchilla coat color

Introduction:

The Hardy-Weinberg equilibrium is a principle, which states that in a given population, the frequency of occurrence of alleles of a gene or a locus can be determined. The frequency is supposed to remain fixed and even remain the same throughout the generation. In other words, the principle says that allele frequency in a population is stable and is constant from generation to generation.

Explanation of Solution

The Hardy- Weinberg equation in its standard form (two-allele) indicates that each individual inherits two copies of each gene, one from each parent. For a two-allele condition, it can also be expressed as $(p+q)2=1$ .

This equation can be expanded to include three or more than three alleles. For the given situation in the question, there a gene exists as four alleles: C(full coat color), c^ch (chinchilla), c^h (Himalayan), and c (albino). The allele frequency of C is designated by the letter p, c^ch by the letter q, c^h by the letter r, and c by the letter s.The allele frequencies are listed below:

$C=0.34cch=0.17ch=0.44c=0.05$

Under these conditions, the Hardy- Weinberg equation can be written as follows:

$(p+q+r+s)2=1p2+q2+r2+s2+2pq+2qr+2pr+2ps+2rs+2qs=1$ .

where,

p² is the genotype of the frequency of CC

q² is the genotype frequency of c^chc^ch

r² is the genotype frequency of c^hc^h

s² is the genotype frequency of cc

2pq is the genotype frequency of Cc^ch

2qr is the genotype frequency of c^chc^h

2pr is the genotype frequency of Cc^h

2ps is the genotype frequency of Cc

2rs is the genotype frequency of c^hc

2qs is the genotype frequency of c^chc

Now,

$p2(the genotype frequency of CC, which produces full coat color)=(0.34)2p2=0.1156$

$q2(the genotype frequency of cchcch, which produces chinchilla coat color)=(0.17)2q2=0.0289$ $r2(the genotype frequency of chch, which produces Himalayan coat color)=(0.44)2r2=0.1936$ $s2 is the genotype frequency of cc, which produces albino coat color)=(0.05)2s2=0.0025$ $2pq (the genotype frequency of Ccch, which produces full coat color)=2(0.34)(0.17)2pq=0.1156$ $2qr (the genotype frequency of cchch, which produces chinchilla coat color)=2(0.17)(0.44) 2qr=0.1496$ $2pr (the genotype frequency of Cch, which produces full coat color)=2(0.34)(0.44) 2pr=0.2992$ $2ps (the genotype frequency of Cc, which produces full coat color)=2(0.34)(0.05) 2ps =0.034$

$2rs (the genotype frequency of chc, which produces Himalayan coat color)=2(0.44)(0.05) 2rs=0.044$ $2qs (the genotype frequency of cchc, which produces chinchilla coat color)=2(0.17)(0.05)2qs=0.017$

The frequency of albino rabbits is s², which is equal to 0.0025 or 0.25%.\

$Frequency of rabbits with Himalayan coat color=0.1936+0.044 Frequency of rabbits with Himalayan coat color=0.2376 or 23.76%.$

$Among 1000 rabbits, the number of rabbits with Himalayan coat color=23.76% of 1000Thus, the number of rabbits with Himalayan coat color=237.6 or 237 (approx.)$

C.

$Frequency of rabbits that are heterozygotes with chinchilla coat color=0.1496+0.017 frequency of rabbits that are heterozygotes with chinchilla coat color=0.1666 or 16.66%$

The number of rabbits that are heterozygotes with chinchilla coat color among 1000 rabbits can be calculated as follows:

$The number of rabbits that are heterozygotes with chinchilla coat color=16.66% of 1000The number of rabbits that are heterozygotes with chinchilla coat color=166.6 or 166(approx.)$

Conclusion

Therefore, it can be concluded that the frequency of the albino rabbits is 0.0025 or 0.25%.The number of rabbits with a Himalayan coat color would be 237 (approx.).The number of rabbits that are heterozygotes with chinchilla coat color would be 166 (approx.).

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Answer 3

Textbook Question

Chapter 27, Problem 2EQ

You will need to refer to question 2 in More Genetic TIPS to answer this question. The gene for coat color in rabbits can exist in four alleles termed C(full coat color), $c c h$ (chinchilla), $c h$ (Himalayan), and c (albino). In a population of rabbits in Hardy-Weinberg equilibrium, the allele frequencies are

$C = 0.34$

$c c h = 0.17$

$c h = 0.44$

$c = 0.05$

Assume that C is dominant to the other three alleles, $c c h$ is dominant to $c h$ and c, and $c h$ is dominant to c.

A. What is the frequency of albino rabbits?

B. Among 1000 rabbits, how many would you expect to have a Himalayan coat color?

C. Among 1000 rabbits, how many would be heterozygotes with a chinchilla coat color?

Expert Solution & Answer

Summary Introduction

To review:

In a population of rabbits in Hardy-Weinberg equilibrium, determinethe:

Frequency of albino rabbits

Number of rabbits to have a Himalayan coat color

Number of rabbits to be heterozygous with a chinchilla coat color

Introduction:

The Hardy-Weinberg equilibrium is a principle, which states that in a given population, the frequency of occurrence of alleles of a gene or a locus can be determined. The frequency is supposed to remain fixed and even remain the same throughout the generation. In other words, the principle says that allele frequency in a population is stable and is constant from generation to generation.

Explanation of Solution

The Hardy- Weinberg equation in its standard form (two-allele) indicates that each individual inherits two copies of each gene, one from each parent. For a two-allele condition, it can also be expressed as $(p+q)2=1$ .

This equation can be expanded to include three or more than three alleles. For the given situation in the question, there a gene exists as four alleles: C(full coat color), c^ch (chinchilla), c^h (Himalayan), and c (albino). The allele frequency of C is designated by the letter p, c^ch by the letter q, c^h by the letter r, and c by the letter s.The allele frequencies are listed below:

$C=0.34cch=0.17ch=0.44c=0.05$

Under these conditions, the Hardy- Weinberg equation can be written as follows:

$(p+q+r+s)2=1p2+q2+r2+s2+2pq+2qr+2pr+2ps+2rs+2qs=1$ .

where,

p² is the genotype of the frequency of CC

q² is the genotype frequency of c^chc^ch

r² is the genotype frequency of c^hc^h

s² is the genotype frequency of cc

2pq is the genotype frequency of Cc^ch

2qr is the genotype frequency of c^chc^h

2pr is the genotype frequency of Cc^h

2ps is the genotype frequency of Cc

2rs is the genotype frequency of c^hc

2qs is the genotype frequency of c^chc

Now,

$p2(the genotype frequency of CC, which produces full coat color)=(0.34)2p2=0.1156$

$q2(the genotype frequency of cchcch, which produces chinchilla coat color)=(0.17)2q2=0.0289$ $r2(the genotype frequency of chch, which produces Himalayan coat color)=(0.44)2r2=0.1936$ $s2 is the genotype frequency of cc, which produces albino coat color)=(0.05)2s2=0.0025$ $2pq (the genotype frequency of Ccch, which produces full coat color)=2(0.34)(0.17)2pq=0.1156$ $2qr (the genotype frequency of cchch, which produces chinchilla coat color)=2(0.17)(0.44) 2qr=0.1496$ $2pr (the genotype frequency of Cch, which produces full coat color)=2(0.34)(0.44) 2pr=0.2992$ $2ps (the genotype frequency of Cc, which produces full coat color)=2(0.34)(0.05) 2ps =0.034$

$2rs (the genotype frequency of chc, which produces Himalayan coat color)=2(0.44)(0.05) 2rs=0.044$ $2qs (the genotype frequency of cchc, which produces chinchilla coat color)=2(0.17)(0.05)2qs=0.017$

The frequency of albino rabbits is s², which is equal to 0.0025 or 0.25%.\

$Frequency of rabbits with Himalayan coat color=0.1936+0.044 Frequency of rabbits with Himalayan coat color=0.2376 or 23.76%.$

$Among 1000 rabbits, the number of rabbits with Himalayan coat color=23.76% of 1000Thus, the number of rabbits with Himalayan coat color=237.6 or 237 (approx.)$

C.

$Frequency of rabbits that are heterozygotes with chinchilla coat color=0.1496+0.017 frequency of rabbits that are heterozygotes with chinchilla coat color=0.1666 or 16.66%$

The number of rabbits that are heterozygotes with chinchilla coat color among 1000 rabbits can be calculated as follows:

$The number of rabbits that are heterozygotes with chinchilla coat color=16.66% of 1000The number of rabbits that are heterozygotes with chinchilla coat color=166.6 or 166(approx.)$

Conclusion

Therefore, it can be concluded that the frequency of the albino rabbits is 0.0025 or 0.25%.The number of rabbits with a Himalayan coat color would be 237 (approx.).The number of rabbits that are heterozygotes with chinchilla coat color would be 166 (approx.).

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Answer 4

Textbook Question

Chapter 27, Problem 2EQ

You will need to refer to question 2 in More Genetic TIPS to answer this question. The gene for coat color in rabbits can exist in four alleles termed C(full coat color), $c c h$ (chinchilla), $c h$ (Himalayan), and c (albino). In a population of rabbits in Hardy-Weinberg equilibrium, the allele frequencies are

$C = 0.34$

$c c h = 0.17$

$c h = 0.44$

$c = 0.05$

Assume that C is dominant to the other three alleles, $c c h$ is dominant to $c h$ and c, and $c h$ is dominant to c.

A. What is the frequency of albino rabbits?

B. Among 1000 rabbits, how many would you expect to have a Himalayan coat color?

C. Among 1000 rabbits, how many would be heterozygotes with a chinchilla coat color?

Expert Solution & Answer

Summary Introduction

To review:

In a population of rabbits in Hardy-Weinberg equilibrium, determinethe:

Frequency of albino rabbits

Number of rabbits to have a Himalayan coat color

Number of rabbits to be heterozygous with a chinchilla coat color

Introduction:

The Hardy-Weinberg equilibrium is a principle, which states that in a given population, the frequency of occurrence of alleles of a gene or a locus can be determined. The frequency is supposed to remain fixed and even remain the same throughout the generation. In other words, the principle says that allele frequency in a population is stable and is constant from generation to generation.

Explanation of Solution

The Hardy- Weinberg equation in its standard form (two-allele) indicates that each individual inherits two copies of each gene, one from each parent. For a two-allele condition, it can also be expressed as $(p+q)2=1$ .

This equation can be expanded to include three or more than three alleles. For the given situation in the question, there a gene exists as four alleles: C(full coat color), c^ch (chinchilla), c^h (Himalayan), and c (albino). The allele frequency of C is designated by the letter p, c^ch by the letter q, c^h by the letter r, and c by the letter s.The allele frequencies are listed below:

$C=0.34cch=0.17ch=0.44c=0.05$

Under these conditions, the Hardy- Weinberg equation can be written as follows:

$(p+q+r+s)2=1p2+q2+r2+s2+2pq+2qr+2pr+2ps+2rs+2qs=1$ .

where,

p² is the genotype of the frequency of CC

q² is the genotype frequency of c^chc^ch

r² is the genotype frequency of c^hc^h

s² is the genotype frequency of cc

2pq is the genotype frequency of Cc^ch

2qr is the genotype frequency of c^chc^h

2pr is the genotype frequency of Cc^h

2ps is the genotype frequency of Cc

2rs is the genotype frequency of c^hc

2qs is the genotype frequency of c^chc

Now,

$p2(the genotype frequency of CC, which produces full coat color)=(0.34)2p2=0.1156$

$q2(the genotype frequency of cchcch, which produces chinchilla coat color)=(0.17)2q2=0.0289$ $r2(the genotype frequency of chch, which produces Himalayan coat color)=(0.44)2r2=0.1936$ $s2 is the genotype frequency of cc, which produces albino coat color)=(0.05)2s2=0.0025$ $2pq (the genotype frequency of Ccch, which produces full coat color)=2(0.34)(0.17)2pq=0.1156$ $2qr (the genotype frequency of cchch, which produces chinchilla coat color)=2(0.17)(0.44) 2qr=0.1496$ $2pr (the genotype frequency of Cch, which produces full coat color)=2(0.34)(0.44) 2pr=0.2992$ $2ps (the genotype frequency of Cc, which produces full coat color)=2(0.34)(0.05) 2ps =0.034$

$2rs (the genotype frequency of chc, which produces Himalayan coat color)=2(0.44)(0.05) 2rs=0.044$ $2qs (the genotype frequency of cchc, which produces chinchilla coat color)=2(0.17)(0.05)2qs=0.017$

The frequency of albino rabbits is s², which is equal to 0.0025 or 0.25%.\

$Frequency of rabbits with Himalayan coat color=0.1936+0.044 Frequency of rabbits with Himalayan coat color=0.2376 or 23.76%.$

$Among 1000 rabbits, the number of rabbits with Himalayan coat color=23.76% of 1000Thus, the number of rabbits with Himalayan coat color=237.6 or 237 (approx.)$

C.

$Frequency of rabbits that are heterozygotes with chinchilla coat color=0.1496+0.017 frequency of rabbits that are heterozygotes with chinchilla coat color=0.1666 or 16.66%$

The number of rabbits that are heterozygotes with chinchilla coat color among 1000 rabbits can be calculated as follows:

$The number of rabbits that are heterozygotes with chinchilla coat color=16.66% of 1000The number of rabbits that are heterozygotes with chinchilla coat color=166.6 or 166(approx.)$

Conclusion

Therefore, it can be concluded that the frequency of the albino rabbits is 0.0025 or 0.25%.The number of rabbits with a Himalayan coat color would be 237 (approx.).The number of rabbits that are heterozygotes with chinchilla coat color would be 166 (approx.).

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

Summary Introduction

To review:

In a population of rabbits in Hardy-Weinberg equilibrium, determinethe:

Frequency of albino rabbits

Number of rabbits to have a Himalayan coat color

Number of rabbits to be heterozygous with a chinchilla coat color

Introduction:

The Hardy-Weinberg equilibrium is a principle, which states that in a given population, the frequency of occurrence of alleles of a gene or a locus can be determined. The frequency is supposed to remain fixed and even remain the same throughout the generation. In other words, the principle says that allele frequency in a population is stable and is constant from generation to generation.

Explanation of Solution

The Hardy- Weinberg equation in its standard form (two-allele) indicates that each individual inherits two copies of each gene, one from each parent. For a two-allele condition, it can also be expressed as $(p+q)2=1$ .

This equation can be expanded to include three or more than three alleles. For the given situation in the question, there a gene exists as four alleles: C(full coat color), c^ch (chinchilla), c^h (Himalayan), and c (albino). The allele frequency of C is designated by the letter p, c^ch by the letter q, c^h by the letter r, and c by the letter s.The allele frequencies are listed below:

$C=0.34cch=0.17ch=0.44c=0.05$

Under these conditions, the Hardy- Weinberg equation can be written as follows:

$(p+q+r+s)2=1p2+q2+r2+s2+2pq+2qr+2pr+2ps+2rs+2qs=1$ .

where,

p² is the genotype of the frequency of CC

q² is the genotype frequency of c^chc^ch

r² is the genotype frequency of c^hc^h

s² is the genotype frequency of cc

2pq is the genotype frequency of Cc^ch

2qr is the genotype frequency of c^chc^h

2pr is the genotype frequency of Cc^h

2ps is the genotype frequency of Cc

2rs is the genotype frequency of c^hc

2qs is the genotype frequency of c^chc

Now,

$p2(the genotype frequency of CC, which produces full coat color)=(0.34)2p2=0.1156$

$q2(the genotype frequency of cchcch, which produces chinchilla coat color)=(0.17)2q2=0.0289$ $r2(the genotype frequency of chch, which produces Himalayan coat color)=(0.44)2r2=0.1936$ $s2 is the genotype frequency of cc, which produces albino coat color)=(0.05)2s2=0.0025$ $2pq (the genotype frequency of Ccch, which produces full coat color)=2(0.34)(0.17)2pq=0.1156$ $2qr (the genotype frequency of cchch, which produces chinchilla coat color)=2(0.17)(0.44) 2qr=0.1496$ $2pr (the genotype frequency of Cch, which produces full coat color)=2(0.34)(0.44) 2pr=0.2992$ $2ps (the genotype frequency of Cc, which produces full coat color)=2(0.34)(0.05) 2ps =0.034$

$2rs (the genotype frequency of chc, which produces Himalayan coat color)=2(0.44)(0.05) 2rs=0.044$ $2qs (the genotype frequency of cchc, which produces chinchilla coat color)=2(0.17)(0.05)2qs=0.017$

The frequency of albino rabbits is s², which is equal to 0.0025 or 0.25%.\

$Frequency of rabbits with Himalayan coat color=0.1936+0.044 Frequency of rabbits with Himalayan coat color=0.2376 or 23.76%.$

$Among 1000 rabbits, the number of rabbits with Himalayan coat color=23.76% of 1000Thus, the number of rabbits with Himalayan coat color=237.6 or 237 (approx.)$

C.

$Frequency of rabbits that are heterozygotes with chinchilla coat color=0.1496+0.017 frequency of rabbits that are heterozygotes with chinchilla coat color=0.1666 or 16.66%$

The number of rabbits that are heterozygotes with chinchilla coat color among 1000 rabbits can be calculated as follows:

$The number of rabbits that are heterozygotes with chinchilla coat color=16.66% of 1000The number of rabbits that are heterozygotes with chinchilla coat color=166.6 or 166(approx.)$

Conclusion

Therefore, it can be concluded that the frequency of the albino rabbits is 0.0025 or 0.25%.The number of rabbits with a Himalayan coat color would be 237 (approx.).The number of rabbits that are heterozygotes with chinchilla coat color would be 166 (approx.).

Answer 8

Expert Solution & Answer

Summary Introduction

To review:

In a population of rabbits in Hardy-Weinberg equilibrium, determinethe:

Frequency of albino rabbits

Number of rabbits to have a Himalayan coat color

Number of rabbits to be heterozygous with a chinchilla coat color

Introduction:

The Hardy-Weinberg equilibrium is a principle, which states that in a given population, the frequency of occurrence of alleles of a gene or a locus can be determined. The frequency is supposed to remain fixed and even remain the same throughout the generation. In other words, the principle says that allele frequency in a population is stable and is constant from generation to generation.

Explanation of Solution

The Hardy- Weinberg equation in its standard form (two-allele) indicates that each individual inherits two copies of each gene, one from each parent. For a two-allele condition, it can also be expressed as $(p+q)2=1$ .

This equation can be expanded to include three or more than three alleles. For the given situation in the question, there a gene exists as four alleles: C(full coat color), c^ch (chinchilla), c^h (Himalayan), and c (albino). The allele frequency of C is designated by the letter p, c^ch by the letter q, c^h by the letter r, and c by the letter s.The allele frequencies are listed below:

$C=0.34cch=0.17ch=0.44c=0.05$

Under these conditions, the Hardy- Weinberg equation can be written as follows:

$(p+q+r+s)2=1p2+q2+r2+s2+2pq+2qr+2pr+2ps+2rs+2qs=1$ .

where,

p² is the genotype of the frequency of CC

q² is the genotype frequency of c^chc^ch

r² is the genotype frequency of c^hc^h

s² is the genotype frequency of cc

2pq is the genotype frequency of Cc^ch

2qr is the genotype frequency of c^chc^h

2pr is the genotype frequency of Cc^h

2ps is the genotype frequency of Cc

2rs is the genotype frequency of c^hc

2qs is the genotype frequency of c^chc

Now,

$p2(the genotype frequency of CC, which produces full coat color)=(0.34)2p2=0.1156$

$q2(the genotype frequency of cchcch, which produces chinchilla coat color)=(0.17)2q2=0.0289$ $r2(the genotype frequency of chch, which produces Himalayan coat color)=(0.44)2r2=0.1936$ $s2 is the genotype frequency of cc, which produces albino coat color)=(0.05)2s2=0.0025$ $2pq (the genotype frequency of Ccch, which produces full coat color)=2(0.34)(0.17)2pq=0.1156$ $2qr (the genotype frequency of cchch, which produces chinchilla coat color)=2(0.17)(0.44) 2qr=0.1496$ $2pr (the genotype frequency of Cch, which produces full coat color)=2(0.34)(0.44) 2pr=0.2992$ $2ps (the genotype frequency of Cc, which produces full coat color)=2(0.34)(0.05) 2ps =0.034$

$2rs (the genotype frequency of chc, which produces Himalayan coat color)=2(0.44)(0.05) 2rs=0.044$ $2qs (the genotype frequency of cchc, which produces chinchilla coat color)=2(0.17)(0.05)2qs=0.017$

The frequency of albino rabbits is s², which is equal to 0.0025 or 0.25%.\

$Frequency of rabbits with Himalayan coat color=0.1936+0.044 Frequency of rabbits with Himalayan coat color=0.2376 or 23.76%.$

$Among 1000 rabbits, the number of rabbits with Himalayan coat color=23.76% of 1000Thus, the number of rabbits with Himalayan coat color=237.6 or 237 (approx.)$

C.

$Frequency of rabbits that are heterozygotes with chinchilla coat color=0.1496+0.017 frequency of rabbits that are heterozygotes with chinchilla coat color=0.1666 or 16.66%$

The number of rabbits that are heterozygotes with chinchilla coat color among 1000 rabbits can be calculated as follows:

$The number of rabbits that are heterozygotes with chinchilla coat color=16.66% of 1000The number of rabbits that are heterozygotes with chinchilla coat color=166.6 or 166(approx.)$

Conclusion

Therefore, it can be concluded that the frequency of the albino rabbits is 0.0025 or 0.25%.The number of rabbits with a Himalayan coat color would be 237 (approx.).The number of rabbits that are heterozygotes with chinchilla coat color would be 166 (approx.).

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Summary Introduction

To review:

In a population of rabbits in Hardy-Weinberg equilibrium, determinethe:

Frequency of albino rabbits

Number of rabbits to have a Himalayan coat color

Number of rabbits to be heterozygous with a chinchilla coat color

Introduction:

The Hardy-Weinberg equilibrium is a principle, which states that in a given population, the frequency of occurrence of alleles of a gene or a locus can be determined. The frequency is supposed to remain fixed and even remain the same throughout the generation. In other words, the principle says that allele frequency in a population is stable and is constant from generation to generation.

Answer 12

Explanation of Solution

The Hardy- Weinberg equation in its standard form (two-allele) indicates that each individual inherits two copies of each gene, one from each parent. For a two-allele condition, it can also be expressed as $(p+q)2=1$ .

This equation can be expanded to include three or more than three alleles. For the given situation in the question, there a gene exists as four alleles: C(full coat color), c^ch (chinchilla), c^h (Himalayan), and c (albino). The allele frequency of C is designated by the letter p, c^ch by the letter q, c^h by the letter r, and c by the letter s.The allele frequencies are listed below:

$C=0.34cch=0.17ch=0.44c=0.05$

Under these conditions, the Hardy- Weinberg equation can be written as follows:

$(p+q+r+s)2=1p2+q2+r2+s2+2pq+2qr+2pr+2ps+2rs+2qs=1$ .

where,

p² is the genotype of the frequency of CC

q² is the genotype frequency of c^chc^ch

r² is the genotype frequency of c^hc^h

s² is the genotype frequency of cc

2pq is the genotype frequency of Cc^ch

2qr is the genotype frequency of c^chc^h

2pr is the genotype frequency of Cc^h

2ps is the genotype frequency of Cc

2rs is the genotype frequency of c^hc

2qs is the genotype frequency of c^chc

Now,

$p2(the genotype frequency of CC, which produces full coat color)=(0.34)2p2=0.1156$

$q2(the genotype frequency of cchcch, which produces chinchilla coat color)=(0.17)2q2=0.0289$ $r2(the genotype frequency of chch, which produces Himalayan coat color)=(0.44)2r2=0.1936$ $s2 is the genotype frequency of cc, which produces albino coat color)=(0.05)2s2=0.0025$ $2pq (the genotype frequency of Ccch, which produces full coat color)=2(0.34)(0.17)2pq=0.1156$ $2qr (the genotype frequency of cchch, which produces chinchilla coat color)=2(0.17)(0.44) 2qr=0.1496$ $2pr (the genotype frequency of Cch, which produces full coat color)=2(0.34)(0.44) 2pr=0.2992$ $2ps (the genotype frequency of Cc, which produces full coat color)=2(0.34)(0.05) 2ps =0.034$

$2rs (the genotype frequency of chc, which produces Himalayan coat color)=2(0.44)(0.05) 2rs=0.044$ $2qs (the genotype frequency of cchc, which produces chinchilla coat color)=2(0.17)(0.05)2qs=0.017$

The frequency of albino rabbits is s², which is equal to 0.0025 or 0.25%.\

$Frequency of rabbits with Himalayan coat color=0.1936+0.044 Frequency of rabbits with Himalayan coat color=0.2376 or 23.76%.$

$Among 1000 rabbits, the number of rabbits with Himalayan coat color=23.76% of 1000Thus, the number of rabbits with Himalayan coat color=237.6 or 237 (approx.)$

C.

$Frequency of rabbits that are heterozygotes with chinchilla coat color=0.1496+0.017 frequency of rabbits that are heterozygotes with chinchilla coat color=0.1666 or 16.66%$

The number of rabbits that are heterozygotes with chinchilla coat color among 1000 rabbits can be calculated as follows:

$The number of rabbits that are heterozygotes with chinchilla coat color=16.66% of 1000The number of rabbits that are heterozygotes with chinchilla coat color=166.6 or 166(approx.)$

Answer 13

Conclusion

Therefore, it can be concluded that the frequency of the albino rabbits is 0.0025 or 0.25%.The number of rabbits with a Himalayan coat color would be 237 (approx.).The number of rabbits that are heterozygotes with chinchilla coat color would be 166 (approx.).

Answer 14

Ch. 27.1 - A gene pool is a. all of the genes in a single...Ch. 27.1 - 2. In natural populations, most genes...Ch. 27.1 - A gene exists in two alleles designatedDandd. If...Ch. 27.1 - Prob. 4COMQ Ch. 27.2 - Which of the following is a factor that, by...Ch. 27.3 - 1. Darwinian fitness is a measure...Ch. 27.3 - 2. Within a particular population, darkly colored...Ch. 27.3 - 3. A population occupies heterogeneous...Ch. 27.3 - Prob. 4COMQ Ch. 27.4 - 1. Genetic drift is a. a change in allele...

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