Organic Chemistry
Organic Chemistry
6th Edition
ISBN: 9781936221349
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
bartleby

Concept explainers

bartleby

Videos

Question
100%
Book Icon
Chapter 27, Problem 27.75AP
Interpretation Introduction

(a)

Interpretation:

The structure of the major organic product formed in the reaction of ethylamine and phenyl isothiocyanate with complete reaction is to be stated.

Concept introduction:

The nucleophilic addition reaction is a common reaction of amines. In this reaction nitrogen of amino group share its lone pair of electron with a carbon attached to electronegative atoms. Such a carbon has low electron density and therefore easily undergoes nucleophilic addition reaction.

Expert Solution
Check Mark

Answer to Problem 27.75AP

The compound 1-ethyl-3-phenylthiourea is formed as a result of the reaction of ethylamine and phenyl isothiocyanate. The structure of the compound is shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  1

Explanation of Solution

The given incomplete reaction is shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  2

Figure 1

The carbon in phenyl isothiocyanate is electron deficient, because it is attached to nitrogen and sulfur atoms with double bonds. It easily accepts lone pair of electron present at nitrogen of ethylamine and undergoes nucleophilic addition reaction and as the result 1-ethyl-3-phenylthiourea is obtained. The reaction with major product is shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  3

Figure 2

Conclusion

The major organic compound obtained, by the reaction of ethylamine and phenyl isothiocyanate, is 1-ethyl-3-phenylthiourea. The structure is illustrated in Figure 2.

Interpretation Introduction

(b)

Interpretation:

The structure of the major organic product formed by the reaction of methylamine with benzaldehyde in presence of potassium cyanide, and afterwards hydrolyzing it and treating it with dilute base is to be drawn. The complete reaction is to be stated.

Concept introduction:

Under nucleophilic addition reaction of aldehyde, amines and cyanide, amino nitriles are obtained. Amino nitriles are compounds having NH2 and NC bonds together. These can be hydrolyzed to get amino carboxylic acids.

Expert Solution
Check Mark

Answer to Problem 27.75AP

The structure of the major organic product formed by the reaction of methylamine with benzaldehyde in presence of potassium cyanide, and afterwards hydrolyzing it and treating it with dilute base along with complete reaction is shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  4

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  5

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  6

Explanation of Solution

The given incomplete reaction is shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  7

Figure 3

The reaction is a good example of Strecker synthesis. This is again a nucleophilic addition reaction. The compound formed is α amino nitrile.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  8

Figure 4

This nitrile group of α amino nitrile gets hydrolysed under acidic condition. As a result amino carboxylic acid is obtained.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  9

Figure 5

This amino acid is treated with base to neutralize it. Finally, the sodium salt of the acid is obtained as shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  10

Figure 6

Conclusion

The products of the reaction are α amino nitrile, amino carboxylic acid and sodium salt of the acid in respective steps. This is shown in the Figures 4, 5 and 6.

Interpretation Introduction

(c)

Interpretation:

The complete reactions and structures of the major organic products formed by the reaction sequence given for amine carboxylate ion are to be stated.

Concept introduction:

Amine being acidic can be neutralized with base. The salts thus formed easily undergo addition reactions to form a compound known as imine. This imine can be again reduced to higher amines. This is a method for alkylation of amines.

Expert Solution
Check Mark

Answer to Problem 27.75AP

The amine is first neutralised to form corresponding salt. This salt gives addition product with given aldehyde, known as imine which is again reduced to corresponding amine. The reaction sequence and structure of the compounds is shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  11

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  12

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  13

Explanation of Solution

The given incomplete reaction is shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  14

Figure 7

The amine group gets neutralized by 1equivalentNaOH to give the sodium salts shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  15

Figure 8

The carbonyl carbon of the dimethylacetaldehyde will be added to amino group of the above formed salt to give an imine product as shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  16

Figure 9

The mild reducing agent NaCNBH3 reduces this imine to corresponding amine. Here mono alkylation of amine group is taking place. Thus, the higher amines are obtained by this reaction.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  17

Figure 10

Conclusion

The amines easily undergo addition reaction. These addition reactions are useful to alkylate the amines to get higher amines as shown in Figures 8 to 10.

Interpretation Introduction

(d)

Interpretation:

The structure of the major organic product formed by the neutralization of given amino diester with 1equiv.NaOH and complete reaction is to be stated.

Concept introduction:

Tertiary butyl groups are better leaving group than methyl group. Tertiary groups are highly substituted so they have more +I effect of alkyl groups. In addition the big size of butyl group also plays the role in steric hindrance.

Expert Solution
Check Mark

Answer to Problem 27.75AP

The tertiary butyl group of the diester leaves the molecule giving the corresponding alcohol and the rest of the cleaved molecule gets neutralized with 1equiv.NaOH. The result of the reaction is butyl alcohol and sodium salt of carboxylate ion. This is shown in the Figure below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  18

Explanation of Solution

The given incomplete reaction is shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  19

Figure 11

As the diester is treated with 1equiv.NaOH only one carboxylate ion can be neutralised and the molecule will be cleaved. The tertiary butyl group will leave easily the cleaved molecule. The tertiary butyl group is a better leaving group because it is highly substituted and a bulky group.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  20

Figure 12

Conclusion

The diester molecule cleaves to give alcohol and corresponding sodium salt of carboxylate ion as shown in Figure 12.

Interpretation Introduction

(e)

Interpretation:

The structure of the major organic product, formed by treating given acyl hydrazide with sodium nitrite and hydrochloric acid, and complete reaction is to be stated.

Concept introduction:

The primary aromatic amines can be converted to diazonium salts. The reaction is known as diazotisation reaction. These diazo salts are important intermediates in synthesis of azo dyes. Functional groups can be introduced by these intermediates through electrophilic substitution reactions.

Expert Solution
Check Mark

Answer to Problem 27.75AP

The given acyl hydrazide gets diazotized with reagents NaNO2+HCl to give acyl azide as shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  21

Explanation of Solution

The given incomplete reaction is shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  22

Figure 13

The acyl hydrazide being an aromatic amine easily undergoes diazotization reaction. As a result acyl azide is formed which is useful intermediate for formation of azo dyes and coupling reaction. The reaction is shown in the Figure below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  23

Figure 14

Conclusion

The given acyl hydrazide is converted to a compound acyl azide by the diazotization reaction of amines as shown in Figure 14.

Interpretation Introduction

(f)

Interpretation:

The structure of the major organic product, formed by heating acyl azide (formed as in Figure 9) with benzene, and complete reaction are to be stated.

Concept introduction:

The curtius rearrangement is the rearrangement of azide molecule to isocyanate. When azide molecules are heated, they undergo thermal decomposition to form isocyanate. A molecule of nitrogen is lost in this rearrangement. These isocyanates can easily be attacked by nucleophiles to give primary amines.

Answer:

The acyl azide (formed in Figure 9) upon heating with benzene gives isocyanate as shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  24

Explanation:

The given incomplete reaction is shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  25

Figure 15

In the above reaction, the acyl azide molecule undergoes curtius rearrangement upon heating with benzene. It forms isocyanate and a molecule of nitrogen is lost.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  26

Figure 16

The lone pair electron of nitrogen is shared with carbonyl carbon. Simultaneously the terminal nitrogens are lost away as a nitrogen molecule. Now the alkyl carbon bonds with nitrogen, to form isocyanate. The rearrangement is depicted in the Figure below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  27

Figure 17

Conclusion:

The acyl azide by curtius rearrangement forms an isocyanate as shown in Figure 17. This can easily get attacked by nucleophiles. This method can be used to prepare primary amines.

Expert Solution
Check Mark

Answer to Problem 27.75AP

The acyl azide (formed in Figure 9) upon heating with benzene gives isocyanate as shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  28

Explanation of Solution

The given incomplete reaction is shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  29

Figure 15

In the above reaction, the acyl azide molecule undergoes curtius rearrangement upon heating with benzene. It forms isocyanate and a molecule of nitrogen is lost.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  30

Figure 16

The lone pair electron of nitrogen is shared with carbonyl carbon. Simultaneously the terminal nitrogens are lost away as a nitrogen molecule. Now the alkyl carbon bonds with nitrogen, to form isocyanate. The rearrangement is depicted in the Figure below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  31

Figure 17

Conclusion

The acyl azide by curtius rearrangement forms an isocyanate as shown in Figure 17. This can easily get attacked by nucleophiles. This method can be used to prepare primary amines.

Interpretation Introduction

(g)

Interpretation:

The structure of the major organic product, formed by heating isocyanate (formed as in Figure 10) with valine methyl ester, and complete reaction are to be stated.

Concept introduction:

The isocyanate molecules have high electron density. They are prone to nucleophilic attack. Nucleophile like alcohols and amines attacks the isocyanate to give corresponding amines, carbamates and urea derivatives.

Answer:

The isocyanate reacts with valine methyl ester to give urethane derivative. The reaction and structure of the product is shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  32

Explanation:

The given incomplete reaction is shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  33

Figure 18

Phenyl isocyanate formed as in Figure 10 reacts with valine methyl ester. This is nucleophilic addition reaction. The lone pair of amino nitrogen attacks the isocyanate carbon. The molecule adds up and a urea derivative is the product of the reaction. The reaction is shown as below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  34

Figure 19

Conclusion:

Isocyanates are good intermediates to get higher amines and their derivatives as shown in Figure 19. They easily undergo nucleophilic addition reaction to forms new compounds as carbamates and urea derivatives.

Expert Solution
Check Mark

Answer to Problem 27.75AP

The isocyanate reacts with valine methyl ester to give urethane derivative. The reaction and structure of the product is shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  35

Explanation of Solution

The given incomplete reaction is shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  36

Figure 18

Phenyl isocyanate formed as in Figure 10 reacts with valine methyl ester. This is nucleophilic addition reaction. The lone pair of amino nitrogen attacks the isocyanate carbon. The molecule adds up and a urea derivative is the product of the reaction. The reaction is shown as below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  37

Figure 19

Conclusion

Isocyanates are good intermediates to get higher amines and their derivatives as shown in Figure 19. They easily undergo nucleophilic addition reaction to forms new compounds as carbamates and urea derivatives.

Interpretation Introduction

(h)

Interpretation:

The structure of the major organic product, formed by treating given compound with sodium ethoxide in ethanol, and complete reaction are to be stated.

Concept introduction:

As the electrons of carbonyl carbon are more attracted to the oxygen. The carbon has low electron density. When two carboxylate groups are attached to same carbon it becomes very reactive as the electron density is even less. They become prone to nucleophilic attack.

Expert Solution
Check Mark

Answer to Problem 27.75AP

The given compound being an active methylene compound gets deprotonated when reacts with sodium ethoxide in ethanol. The produced anion gives addition product with the given alkene. This product upon hydrolysis produces primary amine. The main product and reactions are given below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  38

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  39

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  40

Explanation of Solution

The given incomplete reaction is shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  41

Figure 20

The sodium ethoxide in ethanol is a strong nucleophile. Having high electron density the oxygen of ethoxide attracts the proton of the given compound. The given compound is a very reactive methylene compound. Having two ester groups on the same carbon makes it electron deficient and it is easily attacked by the nucleophile like ethoxide. In this reaction, ethanol facilitates the reaction as a base. The anion formed undergoes addition reaction with the given alkene. Addition product formed under goes hydrolysis and gives the primary amine as the final product. The complete reaction is shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  42

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  43

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  44

Figure 21

Conclusion

An anion is formed as the reaction product of the reaction between the given compound with ethoxide in ethanol. This anion forms addition product with the alkene given in which upon hydrolysis produces primary amine. This is a very good method to obtain higher amines.

Interpretation Introduction

(i)

Interpretation:

The structure of the major organic product, formed by treating given cyanoester with hydrazine in sodium nitrite and hydrochloric acid and the reaction sequences followed, with complete reactions is to be stated.

Concept introduction:

The compounds having amino and carboxylic group are very reactive. They form nucleophilic addition reaction products to give intermediates like hydrazide, azide, isocyanate, which are very useful in synthesis of higher amines, azo dyes, urea derivatives and other products.

Expert Solution
Check Mark

Answer to Problem 27.75AP

The ester group reacts with hdrazine to produce acyl hydrazide. This acyl hydrazide gets diazodized with NaNO2+HCl and gives acyl azide. Formed acyl azide undergoes curtius rearrangement when heated to give isocyanate. Isocynate reacts with ethanol and urethane is formed. Nitrile group of this urethane gets hydrolyzed. The reaction sequence is given below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  45

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  46

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  47

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  48

Explanation of Solution

The given incomplete reaction is shown below.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  49

Figure 22

In the first step the ester by nucleophilic addition with hydrazin, give acyl hydrazide. This acyl hydrazide undergoes diazodization reaction with NaNO2+HCl to give acyl azide. As acyl azide has a group, N3 which is unstable, it undergoes curtius rearrangement and corresponding isocyanate is obtained. Isocynate reacts with alcohol to give urea derivative urethane. This urethane does not get hydrolyzed easily. Under acidic conditions only nitrile group of urethane gets hydrolyzed.

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  50

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  51

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  52

Organic Chemistry, Chapter 27, Problem 27.75AP , additional homework tip  53

Figure 23

Conclusion

The cyanoester undergoes series of reaction to give different products like acyl hydrazide, acyl azide isocyanate, urea derivative. These reaction sequences are used for industrial preparations to get various useful compounds.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
22.64
23.14
Thoroughly explain why (a)malthose is a reducing sugar while trehalose is not based on their structures. (b)Why is trehalose very resistant to acid hydrolysis while maltose can be acid-hydrolyzed with ease. Give clear explanations.

Chapter 27 Solutions

Organic Chemistry

Ch. 27 - Prob. 27.12PCh. 27 - Prob. 27.13PCh. 27 - Prob. 27.14PCh. 27 - Prob. 27.15PCh. 27 - Prob. 27.16PCh. 27 - Prob. 27.17PCh. 27 - Prob. 27.18PCh. 27 - Prob. 27.19PCh. 27 - Prob. 27.20PCh. 27 - Prob. 27.21PCh. 27 - Prob. 27.22PCh. 27 - Prob. 27.23PCh. 27 - Prob. 27.24PCh. 27 - Prob. 27.25PCh. 27 - Prob. 27.26PCh. 27 - Prob. 27.27PCh. 27 - Prob. 27.28PCh. 27 - Prob. 27.29PCh. 27 - Prob. 27.30PCh. 27 - Prob. 27.31PCh. 27 - Prob. 27.32PCh. 27 - Prob. 27.33PCh. 27 - Prob. 27.34PCh. 27 - Prob. 27.35PCh. 27 - Prob. 27.36PCh. 27 - Prob. 27.37PCh. 27 - Prob. 27.38PCh. 27 - Prob. 27.39PCh. 27 - Prob. 27.40PCh. 27 - Prob. 27.41PCh. 27 - Prob. 27.42PCh. 27 - Prob. 27.43APCh. 27 - Prob. 27.44APCh. 27 - Prob. 27.45APCh. 27 - Prob. 27.46APCh. 27 - Prob. 27.47APCh. 27 - Prob. 27.48APCh. 27 - Prob. 27.49APCh. 27 - Prob. 27.50APCh. 27 - Prob. 27.51APCh. 27 - Prob. 27.52APCh. 27 - Prob. 27.53APCh. 27 - Prob. 27.54APCh. 27 - Prob. 27.55APCh. 27 - Prob. 27.56APCh. 27 - Prob. 27.57APCh. 27 - Prob. 27.58APCh. 27 - Prob. 27.59APCh. 27 - Prob. 27.60APCh. 27 - Prob. 27.61APCh. 27 - Prob. 27.62APCh. 27 - Prob. 27.63APCh. 27 - Prob. 27.64APCh. 27 - Prob. 27.65APCh. 27 - Prob. 27.66APCh. 27 - Prob. 27.67APCh. 27 - Prob. 27.68APCh. 27 - Prob. 27.69APCh. 27 - Prob. 27.70APCh. 27 - Prob. 27.71APCh. 27 - Prob. 27.72APCh. 27 - Prob. 27.73APCh. 27 - Prob. 27.74APCh. 27 - Prob. 27.75APCh. 27 - Prob. 27.76APCh. 27 - Prob. 27.77APCh. 27 - Prob. 27.78APCh. 27 - Prob. 27.79APCh. 27 - Prob. 27.80APCh. 27 - Prob. 27.81APCh. 27 - Prob. 27.82APCh. 27 - Prob. 27.83AP
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning
Characteristic Reactions of Benzene and Phenols; Author: Linda Hanson;https://www.youtube.com/watch?v=tjEqEjDd87E;License: Standard YouTube License, CC-BY
An Overview of Aldehydes and Ketones: Crash Course Organic Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=-fBPX-4kFlw;License: Standard Youtube License