Organic Chemistry
6th Edition
ISBN: 9781936221349
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
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Question
Chapter 27, Problem 27.36P
Interpretation Introduction
Interpretation:
The mechanism of imine formation is to be used to explain the given observation.
Concept Introduction:
Amadori rearrangement is the isomerization or rearrangement reaction of
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Chapter 27 Solutions
Organic Chemistry
Ch. 27 - Prob. 27.1PCh. 27 - Prob. 27.2PCh. 27 - Prob. 27.3PCh. 27 - Prob. 27.4PCh. 27 - Prob. 27.5PCh. 27 - Prob. 27.6PCh. 27 - Prob. 27.8PCh. 27 - Prob. 27.9PCh. 27 - Prob. 27.10PCh. 27 - Prob. 27.11P
Ch. 27 - Prob. 27.12PCh. 27 - Prob. 27.13PCh. 27 - Prob. 27.14PCh. 27 - Prob. 27.15PCh. 27 - Prob. 27.16PCh. 27 - Prob. 27.17PCh. 27 - Prob. 27.18PCh. 27 - Prob. 27.19PCh. 27 - Prob. 27.20PCh. 27 - Prob. 27.21PCh. 27 - Prob. 27.22PCh. 27 - Prob. 27.23PCh. 27 - Prob. 27.24PCh. 27 - Prob. 27.25PCh. 27 - Prob. 27.26PCh. 27 - Prob. 27.27PCh. 27 - Prob. 27.28PCh. 27 - Prob. 27.29PCh. 27 - Prob. 27.30PCh. 27 - Prob. 27.31PCh. 27 - Prob. 27.32PCh. 27 - Prob. 27.33PCh. 27 - Prob. 27.34PCh. 27 - Prob. 27.35PCh. 27 - Prob. 27.36PCh. 27 - Prob. 27.37PCh. 27 - Prob. 27.38PCh. 27 - Prob. 27.39PCh. 27 - Prob. 27.40PCh. 27 - Prob. 27.41PCh. 27 - Prob. 27.42PCh. 27 - Prob. 27.43APCh. 27 - Prob. 27.44APCh. 27 - Prob. 27.45APCh. 27 - Prob. 27.46APCh. 27 - Prob. 27.47APCh. 27 - Prob. 27.48APCh. 27 - Prob. 27.49APCh. 27 - Prob. 27.50APCh. 27 - Prob. 27.51APCh. 27 - Prob. 27.52APCh. 27 - Prob. 27.53APCh. 27 - Prob. 27.54APCh. 27 - Prob. 27.55APCh. 27 - Prob. 27.56APCh. 27 - Prob. 27.57APCh. 27 - Prob. 27.58APCh. 27 - Prob. 27.59APCh. 27 - Prob. 27.60APCh. 27 - Prob. 27.61APCh. 27 - Prob. 27.62APCh. 27 - Prob. 27.63APCh. 27 - Prob. 27.64APCh. 27 - Prob. 27.65APCh. 27 - Prob. 27.66APCh. 27 - Prob. 27.67APCh. 27 - Prob. 27.68APCh. 27 - Prob. 27.69APCh. 27 - Prob. 27.70APCh. 27 - Prob. 27.71APCh. 27 - Prob. 27.72APCh. 27 - Prob. 27.73APCh. 27 - Prob. 27.74APCh. 27 - Prob. 27.75APCh. 27 - Prob. 27.76APCh. 27 - Prob. 27.77APCh. 27 - Prob. 27.78APCh. 27 - Prob. 27.79APCh. 27 - Prob. 27.80APCh. 27 - Prob. 27.81APCh. 27 - Prob. 27.82APCh. 27 - Prob. 27.83AP
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- The reaction of an ester with an amine is not as slow as the reaction of an ester with water or an alcohol. Explain with reason. Explain why the rate of aminolysis of an ester cannot be increased by H+, OH- or OR-. How can you activate the carboxylic acid? Is acid catalyzed hydrolysis of acetamide a reversible or an irreversible reaction. Explain.arrow_forwardSeveral compounds have been found to inhibit -lactamase, and drugs based on these compounds can be taken in combination with penicillins and cephalosporins to restore their effectiveness when resistance is known to be a problem. The commonly prescribed formulation called Augmentin is a combination of the -lactamase inhibitor shown below with amoxicillin (shown above). It is used to treat childhood ear infections when resistance is suspected, and many kids know it as the white liquid that tastes like bananas. Which of the statements below are true statements? 1. The stereochemistry of the fusion between the four-and five-membered rings in the inhibitor and amoxicillin are different. 2. The inhibitor possesses enol ether and allylic alcohol functional groups while the antibiotic possesses a phenol and a secondary amide functional group. 3. Neither the inhibitor nor the antibiotic contains strained rings. 4. Both 1 and 2 are true.arrow_forwardNaturally occurring compounds called cyanogenic glycosides, such as lotaustralin, release hydrogen cyanide, HCN, when treated with aqueous acid. The reaction occurs by hydrolysis of the acetal linkage to form a cyanohydrin, which then expels HCN and gives a carbonyl compound. (a) Show the mechanism of the acetal hydrolysis and the structure of the cyanohydrin that results. (b) Propose a mechanism for the loss of HCN, and show the structure of the carbonyl compound that forms.arrow_forward
- Which of the following substituent is a meta-directing deactivator? a amino group b halogenation group c phenyl group d carboxyl grouparrow_forwardAnalyze the mechanism of each rearrangement and list their similarities.arrow_forwardA) Imine and Enamine Formation CH3 N-N S. B) Imine Formation (Ignore chiral centers) Racemicarrow_forward
- Bradykinin is a linear nonapeptide released by blood plasma globulin in response to a wasp sting. It is a very potent pain-causing agent. Its constituent amino acids are 2R, G, 2F, 3P, S. The sue of 2,4-dinitrofluorobenzene and carboxypeptidase shows that both terminal residues are arginine. Partial hydrolysis of bradykinin gives the following di- and tripeptides: FS + PGF +PP + SPF + FR + RParrow_forwardWhich of the following amino acid side chains can form an imine with a substrate?arrow_forwardWhich of the following substituent is an ortho/para-directing activator and an ortho/para-directing deactivator? a amino group b halogen group c nitro group d carboxyl grouparrow_forward
- Provide a step-wise mechanism for the hydrolysis of N,N-dimethyl formamide under basic conditionsarrow_forwardChlorophyll, heme, vitamin B12, and a host of other substances are synthesized from porphobilinogen, which is itself formed from the condensation of two molecules of 5-aminolevulinate. The two 5-aminolevulinates are bound to lysine (Lys) residues in the enzyme, one in the enamine form and the other in the imine form. Condensation is thought to occur via a several step process, one of which is shown below. ÇO2 ÇO2 CO2 + NH3 NH3 H H3N 5-aminolevulinate (enamine form) 5-aminolevulinate (imine form) Porphobilinogen Draw curved arrows to illustrate the movement of electrons in this step of the reaction. Arrow-pushing Instructions CO2 CO2 CO2 CO2 :B BH* H-A H3N H3Ņarrow_forwardTreatment of pentanedioic (glutaric) anhydride with ammonia at elevated temperature leads to a compound of molecular formula C5H7NO2. What is the structure of this product? [Hint: You need to think about the reactivity not only of acid anhydrides but also of amides and carboxylic acids]arrow_forward
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