Interpretation:
Percentages of each component should be calculated.
Concept introduction:
Area normalization method is used in quantitative analysis of compounds in chromatography. In this method of quantification, complete elution of all analytes in the sample is required. Following formulas are required for the calculation.
Answer to Problem 27.26QAP
Explanation of Solution
Given information:
Compound | Relative peak area | Relative detector response |
A | 32.5 | 0.70 |
B | 20.7 | 0.72 |
C | 60.1 | 0.75 |
D | 30.2 | 0.73 |
E | 18.3 | 0.78 |
Corrected areas of compound can be calculated as follows.
Now, the percentage of compound can be calculated as follows:
Or,
Also,
Thus,
Want to see more full solutions like this?
Chapter 27 Solutions
Principles of Instrumental Analysis
- Which of the following statements about a gas chromatogram is correct? O The height of the peak in the gas chromatogram is proportional to the amount of the compound present in the sample. Tailing indicates that the gas chromatograph has been overloaded. O If the peaks are broad this could indicate that the sample is too polar. O If the peaks overlap, the temperature can be increased at a slower rate to improve resolution. O The retention time can be used to identify a compound by comparison with literature values, regardless of the conditions used.arrow_forwardFor quantitative analysis with gas chromatography: O the area of a peak reported by the instrument for a compound is proportional to the quantity of that compound. O the calculated response factor value for a compound is proportional to the quantity of that compound. O the retention time reported by the instrument for a compound is proportional to the quantity of that compound. O the peak height reported by the instrument for a compound is inversely proportional to the quantity of that compound. O the peak shape reported by the instrument for a compound is proportional to the quantity of that compound.arrow_forwardAnalysis of an unknown plant extract yield two peaks X and Y in a chromatogram, 15.65 and 17.03 min respectively in a 30.0 cm column. The peak base width for X is 1.06 and 1.15 for Y. The average number of plates in the column isarrow_forward
- Which statements are true for molecular exclusion chromatography?I Molecular exclusion chromatography separates on the basis of size.II Small molecules that freely pass through the stationary phase, Kav = 0.III Small molecules can fit in the pores of the stationary phase and effectively pass through a larger volume, and elute last.IV The pores in the stationary phase are too small for large molecules to pass through, so large molecules elute last.V Molecular exclusion chromatography with a hydrophilic stationary phase and an aqueous solvent is called gel permeation chromatography. A. II and V B. I, II, and IV C. III, IV, and V D. No correct combinations given above E. I, III, and IV F. I, II, III, and Varrow_forwardYou have obtained a gas chromatogram of a two component mixture of compounds A and B. The height of peak A is 3.84 cm. and the width at half height is 1 cm. The height of peak B is 3.49 cm. and the width at half height is 1.36 cm. The percentage of a component in the mixture is proportional to peak area. Estimate peak areas by multiplying height by width at half height. What was the percentage of compound B in the mixture? (Enter your answer as a number without any percent symbol or the word percent.)arrow_forwardWhat are the mechanisms of samples separation work in Thin layer Chromatography? Please shortly answer at your own words. Answer should be to the point (specific 4-5 lines).arrow_forward
- Can paper chromatography be used to separate and identify very volatile substances? How do I prove this.arrow_forwardIn stationary chromatography, the distribution (K) is the main criterion for the division of species in the sample between the two functions of the system, which factors depend onarrow_forwardAn internal standard is incorporated into an analysis method when systematic sources of variation (i.e., variation not under statistical control) exist that cannot be eliminated. A sample must be injected into the chromatographic system in order for it to be analyzed using HPLC. Which type of injection mode would create the largest source of systematic variation? automated sample injector manual sample injectorarrow_forward
- A standard sample contains 15.0 mM of analyte and 25.0 mM of internal standard. The analysis of the standard sample gives peak areas for the analyte and internal standard of 1.782 and 3.539, respectively, in a chromatography analysis. Then sufficient internal standard is added to a sample to make its concentration 10.0 mM. The analysis of this new sample yields peak areas for the analyte and internal standard of 0.894 and 2.981, respectively. Name the calibration method and report the analyte's concentration in the new sample. (e)arrow_forwardThe solid material in column chromatography is typically referred to as: O 1) the stationary phase 2) the mobile phasearrow_forwardWhich statement(s) are correct for gas chromatography? A) the components in a mixture can be identified from their retention time. B) the relative peak areas give the proportions of components in a mixture. C) Calibration curves are used to confirms the concentrations of components in a mixture.arrow_forward
- Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Macroscale and Microscale Organic ExperimentsChemistryISBN:9781305577190Author:Kenneth L. Williamson, Katherine M. MastersPublisher:Brooks ColeEBK A SMALL SCALE APPROACH TO ORGANIC LChemistryISBN:9781305446021Author:LampmanPublisher:CENGAGE LEARNING - CONSIGNMENT