Concepts of Genetics (12th Edition)
12th Edition
ISBN: 9780134604718
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino, Darrell Killian
Publisher: PEARSON
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Chapter 26, Problem 5PDQ
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The use of nucleotide sequence data to measure genetic variabilityis complicated by the fact that the genes of many eukaryotesare complex in organization and contain 5' and 3' flankingregions as well as introns. Researchers have compared thenucleotide sequence of two cloned alleles of the y-globin gene from asingle individual and found a variation of 1 percent. Those differencesinclude 13 substitutions of one nucleotide for anotherand three short DNA segments that have been inserted in oneallele or deleted in the other. None of the changes takes placein the gene’s exons (coding regions). Why do you think this isso, and should it change our concept of genetic variation?
The genome of Drosophila has been studied extensively
using the technique of gene mapping.
In Drosophila, pink eyes (P), curled wings (C), hairy body
(H), and ebony body (E) are determined by alleles of
genes located on the same chromosome.
Gene Combination
E/H
C/H
E/P
H/P
Frequency of
Recombination
44%
23%
23%
21%
Draw a gene map showing the correct order these
genes appear on the chromosome.
How frequently are the genes for pink eyes and
curled wings expected to separate during crossing
over?
Recombination frequencies between four genetically-linked loci in corn are shown in the following table:
Loci Recombination Frequency (%)
R and Q 45
W and Q 60
R and W 15
Q and L 10
L and R 35
What is the order of the genes on the chromosome?
(note: The same answer can be represented forward or backwards. e.g. A B C D = D C B A)
RQWL
LQWR
QWLR
QRLW
WRLQ
Chapter 26 Solutions
Concepts of Genetics (12th Edition)
Ch. 26 - The ability to taste the compound...Ch. 26 - Determine whether the following two sets of data...Ch. 26 - If the albino phenotype occurs in 1/10,000...Ch. 26 - A prospective groom, who is unaffected, has a...Ch. 26 - In a region of Quebec, Canada, 1 in 22 people are...Ch. 26 - Critics argue that a uniform panel of disorders...Ch. 26 - Others argue that the current testing system...Ch. 26 - HOW DO WE KNOW? Population geneticists study...Ch. 26 - CONCEPT QUESTION Read the Chapter Concepts list on...Ch. 26 - Price et al. [(1999).J. Bacteriol181:2358-2362)...
Ch. 26 - The genetic difference between two Drosophila...Ch. 26 - The use of nucleotide sequence data to measure...Ch. 26 - Prob. 6PDQCh. 26 - What must be assumed in order to validate the...Ch. 26 - In a population where only the total number of...Ch. 26 - If 4 percent of a population in equilibrium...Ch. 26 - Consider a population in which the frequency of...Ch. 26 - If the initial allele frequencies are p = 0.5 and...Ch. 26 - Under what circumstances might a lethal dominant...Ch. 26 - Assume that a recessive autosomal disorder occurs...Ch. 26 - One of the first Mendelian traits identified in...Ch. 26 - Describe how populations with substantial genetic...Ch. 26 - Achondroplasia is a dominant trait that causes a...Ch. 26 - Prob. 17PDQCh. 26 - Prob. 18PDQCh. 26 - A botanist studying water lilies in an isolated...Ch. 26 - A farmer plants transgenic Bt corn that is...Ch. 26 - In an isolated population of 50 desert bighorn...Ch. 26 - To increase genetic diversity in the bighorn sheep...Ch. 26 - What genetic changes take place during speciation?Ch. 26 - Some critics have warned that the use of gene...Ch. 26 - Prob. 25PDQCh. 26 - What are the two groups of reproductive isolating...Ch. 26 - A form of dwarfism known as Ellisvan Creveld...Ch. 26 - The original source of new alleles, upon which...Ch. 26 - A number of comparisons of nucleotide sequences...Ch. 26 - Shown below are two homologous lengths of the...Ch. 26 - Recent reconstructions of evolutionary history are...
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- You are studying four linked genes located on chromosome 2 in the fruit fly Drosophila melanogaster: adp (which contributes to obesity), b (which contributes to body color), pr (which contributes to metabolism), and vg (which contributes to wing formation). A series of crosses between pair-wise combinations of these mutations yielded the following recombination frequencies between the indicated loci: pr and adp 9% adp and b 6% pr and b 3% vg and b 10% vg and pr 7% What is the genetic distance in map units (cM) between the adp and vg loci? 16 9 6 4arrow_forwardUsing the figure and the following background information answer the following questions about the figure Background: Identification of the genetic cause of hornlessness in cattle has been the subject of intensive genetic and genomic research, culminating in the nomination of two different candidate neomutations on cattle chromosome 1 that are predicted to have arisen 500-1,000 years ago: a complex allele of Friesian origin (PF), an 80,128 base pair (bp) duplication (1909352-1989480 bp), and a second, simple allele of Celtic origin (PC) corresponding to a duplication of 212 bp (chromosome 1 positions 1705834-1706045) in place of a 10-bp deletion (1706051-1706060)We report the use of genome editing using transcription activator-like effector nucleases (TALENs) to introgress the putative PC POLLED allele into the genome of bovine embryo fibroblasts to try and produce a genotype identical to what is achievable using natural mating, but without the attendant genetic drag and admixture. In…arrow_forwardDeletions in bacterial chromosomes give the following data: Region of deletion Al Gene A activity +++ A2 АЗ A4 AS +++ (i) Where is the gene located? Explain your answer. Name the scientific term that describes the appearance of a recessive phenotype due to deletion of dominant gene. (ii) (iii) The phenotypic consequences of deletion depend on two factors. What are they? Give one example of human genetic disorder caused by chromosomal deletion by indicating the region of deletion in chromosome. (iv)arrow_forward
- The majority of GWAS associated variants exist in non-coding regions. This has led to additional challenges in understanding the biological mechanisms behind the trait, as the associated variants may not have a clear impact on gene function. Explain two non-coding mechanisms and how they contribute to genetic variation. In your answer, mention what types of sequencing data would assist in determining whether a non-coding GWAS locus may operate under these mechanisms.arrow_forwardAliens with orang eye color allele (o) is recessive to the dominant black eye color allele (O). The locus of the orange gene from 10 pure breed orange eyes aliens and 10 pure breed black eyes aliens. You notice a difference in the DNA sequence linked to each allele of the orange gene and you decide to use it as a physical marker to follow recombination between this sequence linked to the orange gene. These sequences consist of short tandem repeat (STR) with two different number of repeats, each associated with one of the two orange gene alleles. a PCR test distinguishes the 10 repeat STR and the 6 repeat STR associated with the O and o alleles respectively. Using primers on each side of the STRs you can amplify by PCR this sequence and visualizing the size of the 10 repeat and 6 repeat STRs in an electrophoresis gel. You can follow the two STR sequences (10 and 6 repeats) linkage and recombination frequencies with the orange gene locus. The black eye aliens yield a PCR fragment that is…arrow_forwarddescribe two blotting methods (i.e., Northern blottingand Western blotting) used to detect gene products. Northern blotting detects RNA and Western blotting detects proteins. Supposethat a female fruit fly is heterozygous for a maternal effect gene,which we will call gene B. The female is Bb. The normal allele, B,encodes a functional mRNA that is 550 nucleotides long. A recessive allele, b, encodes a shorter mRNA that is 375 nucleotideslong. (Allele b is due to a deletion within this gene.) How couldyou use one or more of these techniques to show that nurse cellstransfer gene products from gene B to developing oocytes? Youmay assume that you can dissect the ovaries of fruit flies and isolate oocytes separately from nurse cells. In your answer, describeyour expected results.arrow_forward
- Tick all the essential steps to demonstrate a genetic linkage between a disease and a molecular marker in humans. identify the alleles of the genetic marker only for diseased individuals in the pedigree enumerate parental type individuals sequence the wild-type and mutant alleles to find the mutation no correct answer calculate a Lod score calculate the recombination frequency between the mutation and the molecular marker identify the alleles of the genetic marker for each individual in the pedigree pedigree analysis cloning the defective gene enumerate recombinant individualsarrow_forwardA pair of paralogous repeats, A and B, have 96% sequence similarity and therefore can promote non-allelic homologous recombination (NAHR). They exist in four possible arrangements in a genome, illustrated below as arrangements 1 – 4. What is the result of NAHR between repeats A and B in arrangement 1? A.Translocation between chromosomes 1 and 2 resulting in monocentric chromosomes B.Deletion or duplication of the region between A and B C.Translocation between chromosomes 1 and 2 resulting in acentric and dicentric chromosomes D.Inversion of the region between A and Barrow_forwardThe period gene of Drosophila melanogaster encodes for a stretch of Thr-Gly repeated in tandem. In natural populations, the three most common alleles encode for 17, 20 and 23 Thr-Gly repeats. The amplification by PCR of the allele encoding for 20 Thr-Gly repeats produces a fragment of 320 bp. Using the same set of primers, what is the size expected when amplifying the 17 Thr-Gly allele? 317 303 314 302 In a certain species of plant loci A, B and C have an additive effect on the colour of the flower. Alleles A, B, and C are dominant and alleles a, b and c are recessive. Knowing that a plant with genotype AAbbCc has a pink flower, which genotype, among the ones listed below, will produce the same phenotype? Aabbcc. aabbcc. AaBbCc. AABBCc. In pea plants, tall (T) is dominant to dwarf (t) and yellow (Y) is dominant to green (y). In a cross of true-breeding tall yellow peas x dwarf green…arrow_forward
- The fruit fly Drosophila melanogaster has about 2 x 10^8 base pairs of DNA per haploid genome, of which about 75% in nonrepeated DNA. The DNA is distributed among four pairs of homologous chromosomes, which have a total of about 5,000 visible bands when in polytene forms in the salivary gland. The number of genes initially estimated from mutational studies was also about 5,000 but recent DNA sequencing studies suggest that the gene number may be somewhat higher. a. Why was it tempting to speculate that each band corresponds to a single gene? What does this suggest about the number of different proteins Drosophila can make? Does that seem like a reasonable number to you? b. Assuming all the nonrepeated DNA is uniformly distributed in the chromosomes, how much nonrepeated DNA (in base pairs) is there in average band?arrow_forwardIf you compare the frequency of the sixteen possible dinucleotide sequences in the E. coli and human genomes, there are no striking differences except for one dinucleotide, 5ʹ-CG-3ʹ. The frequency of CG dinucleotides in the human genome is significantly lower than in E. coli and significantly lower than expected by chance. Why do you suppose that CG dinucleotides are underrepresented in the human genome? (hint: The C in the CG pair is often methylated). Explain how this observation has an impact on the cells immune response.arrow_forwardResearchers in search of loci in the human genome that arelikely to contribute to the constellation of factors leading tohypertension have compared candidate loci in humans and rats[Stoll, M., et al. (2000). New Target Regions for Human Hypertensionvia Comparative Genomics. Genome Res. 10:473–482].Through this research, they identified 26 chromosomal regionsthat they consider likely to contain hypertension genes. Howcan comparative genomics aid in the identification of genesresponsible for such a complex human disease? The researchersstate that comparisons of rat and human candidate loci tothose in the mouse may help validate their studies. Why mightthis be so?arrow_forward
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