Concept explainers
The period gene of Drosophila melanogaster encodes for a stretch of Thr-Gly repeated in tandem. In natural populations, the three most common alleles encode for 17, 20 and 23 Thr-Gly repeats. The amplification by PCR of the allele encoding for 20 Thr-Gly repeats produces a fragment of 320 bp. Using the same set of primers, what is the size expected when amplifying the 17 Thr-Gly allele?
317 |
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303 |
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314 |
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302 |
In a certain species of plant loci A, B and C have an additive effect on the colour of the flower. Alleles A, B, and C are dominant and alleles a, b and c are recessive. Knowing that a plant with genotype AAbbCc has a pink flower, which genotype, among the ones listed below, will produce the same
Aabbcc. |
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aabbcc. |
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AaBbCc. |
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AABBCc. |
In pea plants, tall (T) is dominant to dwarf (t) and yellow (Y) is dominant to green (y). In a cross of true-breeding tall yellow peas x dwarf green peas, what proportion of the progeny are tall with yellow peas?
100% |
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50% |
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25% |
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75% |
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- Based on the question,give an asnwer Question : Name the scoring matrix “A”. List the advantage(s) of this scoring matrix.arrow_forwardFriedreich ataxia (FRDA) is an autosomal recessive, neurodegenerative disease that causes a lack of voluntary coordination of muscle movements. Affected individuals are homozygous for an unusually large number (expansion) of repeats of a trinucleotide sequence (GAA) in the first intron of the X25 gene. Unaffected individuals typically have between 7 and 38 repeats of the trinucleotide (GAAGAAGAAGAA…). FRDA patients have anywhere from 66 to over 1,700 repeats. To understand how the GAA trinucleotide expansion leads to FRDA, researchers looked at X25 gene expression by extracting RNA from affected and unaffected patients and doing a northern blot analysis (see the figure below): In panel “a,” the researchers used a probe to detect X25 mRNA. In panel “b,” the researchers used a probe on a duplicate of the original blot to detect human GAPDH mRNA (GAPDH is an enzyme involved in glycolysis). The sample labeled “YR” is mRNA from yeast cells that was used as a control. Explain…arrow_forwardn yeast cells, telomerase remains active and maintains telomeres of about 300 base pairs. Propose what would happen to the telomeres over time in a yeast lineage in which the following mutations were created. The template portion of the telomerase RNA is changed from 5’-ACACCCACA to 5’-ACAUCUACA.arrow_forward
- The restriction digests of the cloned Drosophila gene can provide direct visible evidence of a mutation, as these samples come from a clone of the gene. In order to similarly detect a mutation in the copy of the endogenous gene within the Drosophila genome, a mechanism for specifically detecting restriction fragments from that gene among the complex set of fragments generated in a restriction digest of the entire Drosophila genome. Remember that the Drosophila melanogaster genome consists of ~123,000 kb. For a 10.2 kb Drosophila gene, what fraction of the genome does this gene constitute?arrow_forwardDNA is extracted from the blood cells of two different humans, individuals 1 and 2. In separate experiments, the DNA from each individual is cleaved by restriction endonucleases A, B, and C, and the fragments are separated by electrophoresis. A hypothetical map of a 10,000 bp (base pair) segment of a human chromosome is shown (1 kbp= 1,000 bp). Individual 2 has point mutations that eliminate restriction recognition sites B* and C*. After the 10kbp segment is digested with each restriction endonuclease A, B, and C one by one, samples are loaded onto an agarose gel for electrophoresis for analysis. I would like you to draw the result of gel electrophoresis. To answer the question, first, draw the whole gel image (on the right) on your answer sheet, then indicate where you expect to see the bands on the gel. (Hint1: Same-size bands will appear at the same position. Hint 2: On the gel bands from individuals 1 and 2 might be at different positions.) The left lane (with an M label on the…arrow_forwardA possible forward primer to be designed is a primer that binds to the region of the OXA-M290 gene where the start codon is located, and the reverse primer is the primer that binds to the region of the gene where the stop codon is located. In order to clone the PCR product generated using these primers into pET-28a, extra nucleotides must be added to the 5' ends of the primers. These extra nucleotides will contain the recognition sites for the restriction enzymes that are used for cloning. When the DNA produced by PCR using these primers is treated with the restriction enzymes, this will generate sticky ends at the ends of the PCR product. If pET-28a is digested with the same restriction enzymes, the sticky ends of the PCR product will bind to the sticky ends on the digested pET-28a, allowing the two DNA molecules to be connected together by DNA ligase. Which primer (forward or reverse) should contain the SacI recognition site, and which primer (forward or reverse) should contain the…arrow_forward
- A 2.0kb bacterial plasmid ‘BS1030’ is digested with the restriction endonuclease Sau3A; the plasmid map is depicted in the diagram below and the Sau3A (S) restriction sites are indicated. Which of the following DNA fragments do you expect to see on an agarose gel when you run Sau3A-digested plasmid ‘BS1030’ DNA? a. 250 bp, 450 bp, 550 bp, 1.1 kb, 1.5 kb and 2.0 kb b. 2.0kb c. 250 bp, 400 bp, 450 bp, 500 bp and 550 bp d. 100 bp, 200 bp, 250 bp, 400 bp, 500 bp and 550 bparrow_forwardthis is what i have said about this image so far, what else can be said aswell including the raw count column. " Interpreting the results of an RNA-Seq analysis is pivotal in understanding the underlying genetic mechanisms of diseases such as breast cancer. In this analysis, Figure 1 provides comprehensive data on differentially expressed genes associated with breast cancer. By delving into the provided information, we can gain valuable insights into the molecular landscape of this disease. First focus is on the gene with the highest fold change, EYA4, situated on chromosome 6. With a staggering fold change of 3604.4176, EYA4 exhibits an unprecedented level of overexpression in cancerous cells compared to normal cells. This profound alteration suggests a pivotal role for EYA4 in breast cancer pathogenesis. The log2 fold change of 11.81555 further emphasizes the magnitude of this difference in gene expression. Statistical significance is evident, with an exceptionally low p-value of…arrow_forwardThe following figure shows a screen shot from the UCSC Genome Browser, focusing on a region of the human genome encoding a gene called MFAP3L. (Note hg38 refers to version 38 of the human genome RefSeq)a. Describe in approximate terms the genomic location of MFAP3L.b. Is the gene transcribed in the direction from the centromere-to-telomere or from the telomere-to-centromere?c. How many alternative splice forms of MFAP3L mRNA are indicated by the data?d. How many different promoters for MFAP3L are suggested by the data?arrow_forward
- The genomes of two E. coli strains are compared in Figure14-19. Would you expect any third strain to contain moreof the blue, tan, or red regions shown in Figure 14-19?Explain.arrow_forwardAfter Drosophila DNA has been treated with a restrictionenzyme, the fragments are inserted into plasmids and selected as clones in E. coli. With the use of this “shotgun”technique, every DNA sequence of Drosophila in a librarycan be recovered.a. How would you identify a clone that contains DNAencoding the protein actin, whose amino acid sequenceis known?b. How would you identify a clone encoding a specifictRNAarrow_forwardCan you please answer number 4arrow_forward
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