Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 25, Problem 102A
Interpretation Introduction

Interpretation: The question is to describe Pauli’s exclusion principle and Hund’s rule.

Concept Introduction: Pauli's exclusion principle and Hund's rule are primarily employed in chemistry to clarify or ascertain the electron shell structure of atoms and to foretell which atoms are most likely to donate electrons.

Expert Solution & Answer
Check Mark

Answer to Problem 102A

According to Hund's principle, electrons should first fill lower energy levels in the atomic orbitals before moving up to higher states.

No two electrons may have the same four quantum numbers, according to Pauli's Exclusion Principle.

Explanation of Solution

Given information:

Pauli’s exclusion principle and Hund’s rule.

According to Pauli's Exclusion Principle, no two electrons in the same atom can have values for all four of their quantum numbers that are exactly the same.

In other words,

  1. Only two electrons may share an orbital.
  2. The spins of any two electrons sharing an orbital must be opposing.

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 25, Problem 102A , additional homework tip  1

According to Hund's rule, all electrons in singly occupied orbitals have the same spin since every orbital in a subshell is singly occupied with one electron before any one orbital is doubly filled.

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 25, Problem 102A , additional homework tip  2

Conclusion

Hence, Pauli’s exclusion principle and Hund’s rule are stated above.

Chapter 25 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 25.2 - Prob. 11LCCh. 25.2 - Prob. 12LCCh. 25.2 - Prob. 13LCCh. 25.2 - Prob. 14LCCh. 25.2 - Prob. 15LCCh. 25.2 - Prob. 16LCCh. 25.3 - Prob. 18LCCh. 25.3 - Prob. 19LCCh. 25.3 - Prob. 20LCCh. 25.3 - Prob. 21LCCh. 25.3 - Prob. 22LCCh. 25.3 - Prob. 23LCCh. 25.3 - Prob. 25LCCh. 25.4 - Prob. 26LCCh. 25.4 - Prob. 27LCCh. 25.4 - Prob. 28LCCh. 25.4 - Prob. 29LCCh. 25.4 - Prob. 30LCCh. 25.4 - Prob. 31LCCh. 25.4 - Prob. 32LCCh. 25.4 - Prob. 33LCCh. 25 - Prob. 34ACh. 25 - Prob. 35ACh. 25 - Prob. 36ACh. 25 - Prob. 37ACh. 25 - Prob. 38ACh. 25 - Prob. 39ACh. 25 - Prob. 40ACh. 25 - Prob. 41ACh. 25 - Prob. 42ACh. 25 - Prob. 43ACh. 25 - Prob. 44ACh. 25 - Prob. 45ACh. 25 - Prob. 46ACh. 25 - Prob. 47ACh. 25 - Prob. 48ACh. 25 - Prob. 49ACh. 25 - Prob. 50ACh. 25 - Prob. 51ACh. 25 - Prob. 52ACh. 25 - Prob. 53ACh. 25 - Prob. 54ACh. 25 - Prob. 55ACh. 25 - Prob. 56ACh. 25 - Prob. 57ACh. 25 - Prob. 58ACh. 25 - Prob. 59ACh. 25 - Prob. 60ACh. 25 - Prob. 61ACh. 25 - Prob. 62ACh. 25 - Prob. 63ACh. 25 - Prob. 64ACh. 25 - Prob. 65ACh. 25 - Prob. 66ACh. 25 - Prob. 67ACh. 25 - Prob. 68ACh. 25 - Prob. 69ACh. 25 - Prob. 70ACh. 25 - Prob. 71ACh. 25 - Prob. 72ACh. 25 - Prob. 73ACh. 25 - Prob. 74ACh. 25 - Prob. 75ACh. 25 - Prob. 76ACh. 25 - Prob. 77ACh. 25 - Prob. 78ACh. 25 - Prob. 79ACh. 25 - Prob. 80ACh. 25 - Prob. 81ACh. 25 - Prob. 82ACh. 25 - Prob. 83ACh. 25 - Prob. 84ACh. 25 - Prob. 85ACh. 25 - Prob. 86ACh. 25 - Prob. 87ACh. 25 - Prob. 88ACh. 25 - Prob. 89ACh. 25 - Prob. 90ACh. 25 - Prob. 91ACh. 25 - Prob. 92ACh. 25 - Prob. 93ACh. 25 - Prob. 94ACh. 25 - Prob. 95ACh. 25 - Prob. 96ACh. 25 - Prob. 97ACh. 25 - Prob. 98ACh. 25 - Prob. 99ACh. 25 - Prob. 100ACh. 25 - Prob. 101ACh. 25 - Prob. 102ACh. 25 - Prob. 103ACh. 25 - Prob. 104ACh. 25 - Prob. 105ACh. 25 - Prob. 106ACh. 25 - Prob. 107ACh. 25 - Prob. 108ACh. 25 - Prob. 109ACh. 25 - Prob. 110ACh. 25 - Prob. 111ACh. 25 - Prob. 112ACh. 25 - Prob. 113ACh. 25 - Prob. 1STPCh. 25 - Prob. 2STPCh. 25 - Prob. 3STPCh. 25 - Prob. 4STPCh. 25 - Prob. 5STPCh. 25 - Prob. 6STPCh. 25 - Prob. 7STPCh. 25 - Prob. 8STPCh. 25 - Prob. 9STPCh. 25 - Prob. 10STPCh. 25 - Prob. 11STPCh. 25 - Prob. 12STPCh. 25 - Prob. 13STPCh. 25 - Prob. 14STPCh. 25 - Prob. 15STPCh. 25 - Prob. 16STPCh. 25 - Prob. 17STP
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