Organic Chemistry - Standalone book
10th Edition
ISBN: 9780073511214
Author: Francis A Carey Dr., Robert M. Giuliano
Publisher: McGraw-Hill Education
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Chapter 24.4, Problem 4P
Interpretation Introduction
Interpretation:
The D, L configuration, the R, S configuration at the chirality center with the highest number of the given aldose are to be determined. The sign of rotation of the aldose is also to be predicted.
Concept introduction:
A carbon atom that has four non-equivalent atoms or groups attached to it is known as a chiral carbon atom (or asymmetric or stereogenic centers).
The naming of a chiral center and geometric isomers are based on Cahn-Ingold-Prelog priority rules.
The D and L configuration are the spatial arrangement of the molecules about the chirality center of the carbohydrates.
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A D-aldopentose A is reduced to an optically active alditol. Upon Kiliani–Fischer synthesis, A is converted to two D-aldohexoses, B and C. B is oxidized to an optically inactive aldaric acid. C is oxidized to an optically active aldaric acid. What are the structures of A–C?
D-Aldopentose A is oxidized to an optically inactive aldaric acid. On Wohl degradation, A forms an aldotetrose B that is oxidized to an optically active aldaric acid. What are the structures of A and B?
Monosaccharide A is a diastereomer of d-lyxose. Treatment of A with nitric acid forms an optically inactive aldaric acid. A undergoes a Kiliani-Fischer synthesis to form B and C. B is oxidized by nitric acid to an optically active aldaric acid, and C is oxidized to an optically inactive aldaric acid. Wohl degradation of A forms D, which is oxidized by nitric acid to an optically inactive aldaric acid. Wohl degradation of D forms a d-aldotriose. Identify A, B, C, and D.
Chapter 24 Solutions
Organic Chemistry - Standalone book
Ch. 24.2 - Prob. 1PCh. 24.3 - Problem 24.2 Which aldotetrose in the structure...Ch. 24.4 - Prob. 3PCh. 24.4 - Prob. 4PCh. 24.6 - Prob. 5PCh. 24.6 - Prob. 6PCh. 24.7 - Prob. 7PCh. 24.8 - Prob. 8PCh. 24.8 - Prob. 9PCh. 24.9 - Prob. 10P
Ch. 24.10 - Prob. 11PCh. 24.10 - Prob. 12PCh. 24.11 - Prob. 13PCh. 24.12 - Prob. 14PCh. 24.14 - Prob. 15PCh. 24.14 - Prob. 16PCh. 24.14 - Prob. 17PCh. 24.14 - Using Mechanism 24.2 as a guide, write a stepwise...Ch. 24.15 - Prob. 19PCh. 24.17 - Prob. 20PCh. 24.17 - Prob. 21PCh. 24.18 - Prob. 22PCh. 24.18 - Prob. 23PCh. 24.18 - Prob. 24PCh. 24.20 - Prob. 25PCh. 24 - Prob. 26PCh. 24 - Prob. 27PCh. 24 - Prob. 28PCh. 24 - Prob. 29PCh. 24 - Prob. 30PCh. 24 - Prob. 31PCh. 24 - Prob. 32PCh. 24 - Prob. 33PCh. 24 - Prob. 34PCh. 24 - Prob. 35PCh. 24 - Methyl glycosides of 2-deoxy sugars have been...Ch. 24 - Prob. 37PCh. 24 - Prob. 38PCh. 24 - Prob. 39PCh. 24 - Prob. 40PCh. 24 - Treatment of d-mannose with methanol in the...Ch. 24 - Prob. 42PCh. 24 - Prob. 43PCh. 24 - Prob. 44PCh. 24 - Prob. 45DSPCh. 24 - Prob. 46DSPCh. 24 - Prob. 47DSPCh. 24 - Prob. 48DSPCh. 24 - Prob. 49DSP
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