Organic Chemistry - Standalone book
10th Edition
ISBN: 9780073511214
Author: Francis A Carey Dr., Robert M. Giuliano
Publisher: McGraw-Hill Education
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Chapter 24.17, Problem 21P
Interpretation Introduction
Interpretation:
The structure of the
Concept introduction:
Hydrogenolysis is a
Hydrogenolysis is conducted catalytically using hydrogen gas.
Hydrogenolysis reaction is the one in which catalytic hydrogenation cleaves the
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What is the product of the starting material D-glyceraldehyde which will
(1) produce aldaric acid upon reacting with HNO3 + H2O, NaOCH2, NH2OH, and (CH3CO)2O + NaOCOCH3
(2) produce tartaric acid upon reacting with HNO3 + H2O, NaOCH3, NH2OH, and (CH3CO)2O + NaOCOCH3
Quinapril (trade name Accupril) is used to treat high blood pressure and congestive heart failure. One step in the synthesis of quinapril involves reaction of the racemic alkyl bromide A with a single enantiomer of the amino ester B. (a) What two products are formed in this reaction? (b) Given the structure of quinapril, which one of these two products is needed to synthesize the drug?
Ribose, a carbohydrate with the formula shown, forms a cyclic hemiacetal, which, in
principle, could contain either a four-membered, five-membered, or six-membered ring.
When D-ribose is treated with methanol in the presence of an acid catalyst, two cyclic
acetals, A and B, are formed, both with molecular formula C,H,0, These are separated,
and each is treated with sodium periodate (Section 10.8C) followed by dilute aqueous
acid. Both A and B yield the same three products in the same ratios.
он о
CHO
СНО
H+ CH,OH A +B
ÕH
1. NalO,
2. H,0*
НО
CHO + CHOH + CH,OH
ÕH
CH,OH
Isomeric cyclic
acetals with molecular
formula CH12O,
D-Ribose
(C;H1605)
From this information, deduce whether the cyclic hemiacetal formed by D-ribose is four-
membered, five-membered, or six-membered.
Chapter 24 Solutions
Organic Chemistry - Standalone book
Ch. 24.2 - Prob. 1PCh. 24.3 - Problem 24.2 Which aldotetrose in the structure...Ch. 24.4 - Prob. 3PCh. 24.4 - Prob. 4PCh. 24.6 - Prob. 5PCh. 24.6 - Prob. 6PCh. 24.7 - Prob. 7PCh. 24.8 - Prob. 8PCh. 24.8 - Prob. 9PCh. 24.9 - Prob. 10P
Ch. 24.10 - Prob. 11PCh. 24.10 - Prob. 12PCh. 24.11 - Prob. 13PCh. 24.12 - Prob. 14PCh. 24.14 - Prob. 15PCh. 24.14 - Prob. 16PCh. 24.14 - Prob. 17PCh. 24.14 - Using Mechanism 24.2 as a guide, write a stepwise...Ch. 24.15 - Prob. 19PCh. 24.17 - Prob. 20PCh. 24.17 - Prob. 21PCh. 24.18 - Prob. 22PCh. 24.18 - Prob. 23PCh. 24.18 - Prob. 24PCh. 24.20 - Prob. 25PCh. 24 - Prob. 26PCh. 24 - Prob. 27PCh. 24 - Prob. 28PCh. 24 - Prob. 29PCh. 24 - Prob. 30PCh. 24 - Prob. 31PCh. 24 - Prob. 32PCh. 24 - Prob. 33PCh. 24 - Prob. 34PCh. 24 - Prob. 35PCh. 24 - Methyl glycosides of 2-deoxy sugars have been...Ch. 24 - Prob. 37PCh. 24 - Prob. 38PCh. 24 - Prob. 39PCh. 24 - Prob. 40PCh. 24 - Treatment of d-mannose with methanol in the...Ch. 24 - Prob. 42PCh. 24 - Prob. 43PCh. 24 - Prob. 44PCh. 24 - Prob. 45DSPCh. 24 - Prob. 46DSPCh. 24 - Prob. 47DSPCh. 24 - Prob. 48DSPCh. 24 - Prob. 49DSP
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