Organic Chemistry - Standalone book
10th Edition
ISBN: 9780073511214
Author: Francis A Carey Dr., Robert M. Giuliano
Publisher: McGraw-Hill Education
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Chapter 24, Problem 33P
Interpretation Introduction
Interpretation:
The preferred form of
Concept Introduction:
The name of the cyclic form depends upon the position of the substituents present at anomeric centre. Both the cyclic forms are stable.
The anomers are cyclic monosaccharides which are differ in configuration at
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Compound A is a D-aldopentose that can be oxidized to an optically inactive aldaric acid B. On Kiliani-Fischer chain extension, A is
converted into C and D; C can be oxidized to an optically active aldaric acid E, but D is oxidized to an optically inactive aldaric acid
F.
What is the structure of compound F?
• Use the wedge/hash bond tools to indicate stereochemistry where it exists.
You do not have to explicitly draw H atoms.
If a group is achiral, do not use wedged or hashed bonds on it.
• Show stereochemistry in a meso compound.
• Do not include lone pairs in your answer. They will not be considered in the grading.
Coibacin B (shown below) is a natural product that exhibits potent anti-inflammatory activity and potential activity in the treatment of leishmaniasis, a disease caused by certain
parasites
(Org. Lett. 2012, 14, 3878-3881):
(a) Assign the configuration (R or S) of each chirality center (labeled A to C) in coibacin B.
(b) Identify the number of possible stereoisomers for this compound, assuming that the geometry of the alkenes are fixed. Choices are given below and write the CAPITAL
LETTER of your choice.
A. 2
В. 4
С. 8
D.
16
ANSWERS:
(a) A.
В.
C.
(b)
(a) Distinguish between:(i) C6H5— COCH3 and C6H5— CHO(ii) CH3COOH and HCOOH(b) Arrange the following in the increasing order of their boiling points:CH3CHO, CH3COOH, CH3CH2OH
Chapter 24 Solutions
Organic Chemistry - Standalone book
Ch. 24.2 - Prob. 1PCh. 24.3 - Problem 24.2 Which aldotetrose in the structure...Ch. 24.4 - Prob. 3PCh. 24.4 - Prob. 4PCh. 24.6 - Prob. 5PCh. 24.6 - Prob. 6PCh. 24.7 - Prob. 7PCh. 24.8 - Prob. 8PCh. 24.8 - Prob. 9PCh. 24.9 - Prob. 10P
Ch. 24.10 - Prob. 11PCh. 24.10 - Prob. 12PCh. 24.11 - Prob. 13PCh. 24.12 - Prob. 14PCh. 24.14 - Prob. 15PCh. 24.14 - Prob. 16PCh. 24.14 - Prob. 17PCh. 24.14 - Using Mechanism 24.2 as a guide, write a stepwise...Ch. 24.15 - Prob. 19PCh. 24.17 - Prob. 20PCh. 24.17 - Prob. 21PCh. 24.18 - Prob. 22PCh. 24.18 - Prob. 23PCh. 24.18 - Prob. 24PCh. 24.20 - Prob. 25PCh. 24 - Prob. 26PCh. 24 - Prob. 27PCh. 24 - Prob. 28PCh. 24 - Prob. 29PCh. 24 - Prob. 30PCh. 24 - Prob. 31PCh. 24 - Prob. 32PCh. 24 - Prob. 33PCh. 24 - Prob. 34PCh. 24 - Prob. 35PCh. 24 - Methyl glycosides of 2-deoxy sugars have been...Ch. 24 - Prob. 37PCh. 24 - Prob. 38PCh. 24 - Prob. 39PCh. 24 - Prob. 40PCh. 24 - Treatment of d-mannose with methanol in the...Ch. 24 - Prob. 42PCh. 24 - Prob. 43PCh. 24 - Prob. 44PCh. 24 - Prob. 45DSPCh. 24 - Prob. 46DSPCh. 24 - Prob. 47DSPCh. 24 - Prob. 48DSPCh. 24 - Prob. 49DSP
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- How many chirality centers are contained in (a) the aldotetrose and (b) the ketopentose just given below? How many stereoisomers would you expect from each general structure?arrow_forwardAldohexoses A and B both undergo Ruff degradation to give aldopentose C. On treatment with warm nitric acid, aldopentose C gives an optically active aldaric acid. B alsoreacts with warm nitric acid to give an optically active aldaric acid, but A reacts to givean optically inactive aldaric acid. Aldopentose C is degraded to aldotetrose D, whichgives optically active tartaric acid when it is treated with nitric acid. Aldotetrose D isdegraded to (+)@glyceraldehyde. Deduce the structures of sugars A, B, C, and D, and useFigure 23-3 to determine the correct names of these sugars.arrow_forward(S)-Lactic acid has a specific rotation of +3.8. (a) If the ee of a solution of lactic acid is 60%, what is [α] for this solution? (b) How much of the dextrorotatory and levorotatory isomers does the solution contain?arrow_forward
- (a) Write the structures of the following compounds and mark them as chiral or achiral. 4 (i) 2-Bromopentane (ii) 3-Bromopentane (iii) 1-Bromo-2-methylbutane (iv) 2-Chloro-3-methylbutane (b) Identify the asymmetric carbon in the chiral compounds. (c) Write the structure of the other enantiomer of the chiral compounds.arrow_forwardStereochemistry in biological molecules is often denoted by the D- and L- convention, instead of the R- and S- configurations determined by the Cahn-Ingold-Prelog methodology. Historically, the glyceraldehyde enantiomer that rotated plane polarized light clockwise was arbitrarily designated as D and the other enantiomer was designated as the L configuration. The D-glyceraldehyde Fischer projection is shown. D-glyceraldehyde H H- -OH CH₂OH Identify which structures are equivalent to the D-configuration. H CH₂OH 76. OH CH₂OH H- -OH ☐ O H ОН -CH₂OH K H H Incorrect HOCH2 H OH t H OH CH₂OH K.arrow_forwardCalculate the degree of unsaturation in each of the following formulas (a) Cholesterol, C27H46o (b) DDT, C14HgC15 (c) Prostaglandin E1, C2oH3405 (d) Caffeine, C8H10N402 (e) Cortisone, C21H28O5 (f) Atropine, C17H23NO3arrow_forward
- Ribose, a carbohydrate with the formula shown, forms a cyclic hemiacetal, which, in principle, could contain either a four-membered, five-membered, or six-membered ring. When D-ribose is treated with methanol in the presence of an acid catalyst, two cyclic acetals, A and B, are formed, both with molecular formula C,H,0, These are separated, and each is treated with sodium periodate (Section 10.8C) followed by dilute aqueous acid. Both A and B yield the same three products in the same ratios. он о CHO СНО H+ CH,OH A +B ÕH 1. NalO, 2. H,0* НО CHO + CHOH + CH,OH ÕH CH,OH Isomeric cyclic acetals with molecular formula CH12O, D-Ribose (C;H1605) From this information, deduce whether the cyclic hemiacetal formed by D-ribose is four- membered, five-membered, or six-membered.arrow_forwardWhen the gum of the shrub Sterculia setigera is subjected to acidic hydrolysis, one of the water-soluble components of thehydrolysate is found to be tagatose. The following information is known about tagatose:(1) Molecular formula C6H12O6(2) Undergoes mutarotation.(3) Does not react with bromine water.(4) Reduces Tollens reagent to give d-galactonic acid and d-talonic acid.(5) Methylation of tagatose (using excess CH3 I and Ag2O) followed by acidic hydrolysis gives1,3,4,5-tetra-O-methyltagatose.(a) Draw a Fischer projection structure for the open-chain form of tagatose.(b) Draw the most stable conformation of the most stable cyclic hemiacetal form of tagatosearrow_forward(v) Identify every chiral center in cholesterol (below) with an asterisk. HO (vi) Draw an energy vs. dihedral angle diagram that represents all the conformations of butane starting from the anti-conformation. (vii) Draw both chair conformations for the compound shown below using the templates provided. Circle the chair conformation that is lowest in energy. Br (viii) Draw a chair conformation that meets the following criteria. Axial chlorine at C5 Equatorial methyl at C4 Bromine on C2 that is cis to the chlorine 6 2 5 3 4arrow_forward
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