Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Chapter 22, Problem 159CP
Interpretation Introduction

Interpretation: The pH or isoelectric point of glycine at which the given equation is true is to be calculated.

Concept introduction: Amino acids are defined as organic compounds which contain amine (-NH2) and carboxyl (-COOH) functional groups, along with a side chain (R group) attached to each amino acid. The isoelectric point is defined as the pH of the molecule at which the molecule has no net electrical charge in statistical mean.

To determine: The pH or isoelectric point of glycine at which the given equation is true.

Expert Solution & Answer
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Answer to Problem 159CP

Answer

The pH or isoelectric point of glycine is (6.08)_ .

Explanation of Solution

Explanation

The equilibrium constant for the given reaction is 6.88×1013_ .

The equilibrium constant (Keq) of the reaction is given from the part (c) of Exercise 136. According to the part (c) of exercise 136, the equilibrium constant (Keq) of the reaction is Keq=6.88×1013 which is calculated as,

Given

The value of Ka(COOH) is 4.3×103 .

The value of Ka(NH3+) is 1.6×103 .

The equilibrium constant is calculated by using the expression,

Keq=Ka(COOH)×Ka(NH3+)

Substitute the value of Ka(COOH) and Ka(NH3+) in the above expression,

Keq=Ka(COOH)×Ka(NH3+)=4.3×103×1.6×1010=6.88×10-13_

Hence, Keq=6.88×1013_ .

By using equilibrium equation, the concentration of hydrogen ion at its isoelectric point is 8.3×107 M_ .

The equilibrium constant for the given reaction is 6.88×1013 .

The concentration of hydrogen ion at its isoelectric point is calculated by the equilibrium equation as follows,

Keq=[H+]2[H2NCH2CO2][+H2NCH2CO2H]

Substitute the value of Keq in the above expression, the concentration of hydrogen ion at its isoelectric point is calculated.

Keq=[H+]2[H2NCH2CO2-][+H2NCH2CO2H]6.88×1013=[H+]2[H+]=6.88×1013=8.3×107M_

Therefore, concentration of hydrogen ion is 8.5×107M_ .

The pH or isoelectric point of glycine is 6.08_ .

Finally, the pH of glycine or isoelectric point of glycine is calculated by using the value of the hydrogen ion concentration using an expression,

pH=log[H+]

Substitute the value of hydrogen ion concentration [H+] in the above expression.

pH=log[H+]=log(8.3×107)=6.08_

Therefore, the pH of glycine is (6.08)_ .

Conclusion

Conclusion

The pH or isoelectric point of glycine at which the given equation is true is (6.08)_ .

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Chapter 22 Solutions

Chemistry

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CH2 = CH ...Ch. 22 - Name each of the following alkenes or alkynes. a....Ch. 22 - Prob. 29ECh. 22 - Give the structure for each of the following. a....Ch. 22 - Prob. 31ECh. 22 - Cumene is the starting material for the industrial...Ch. 22 - Name each of the following. a. b. CH3CH2CH2CCl3 c....Ch. 22 - Prob. 34ECh. 22 - There is only one compound that is named...Ch. 22 - Prob. 36ECh. 22 - Prob. 37ECh. 22 - Prob. 38ECh. 22 - Draw all the structural isomers of C5H10. 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Name...Ch. 22 - Prob. 154CWPCh. 22 - Prob. 155CWPCh. 22 - Prob. 156CWPCh. 22 - Prob. 157CPCh. 22 - Estimate H for the following reactions using bond...Ch. 22 - Prob. 159CPCh. 22 - Prob. 160CPCh. 22 - Prob. 161CPCh. 22 - Consider a sample of a hydrocarbon at 0.959 atm...Ch. 22 - Prob. 163CPCh. 22 - Prob. 164CPCh. 22 - Prob. 165CPCh. 22 - Prob. 166CPCh. 22 - Prob. 167CPCh. 22 - Prob. 168CPCh. 22 - Prob. 169CPCh. 22 - Alcohols are very useful starting materials for...Ch. 22 - A chemical breathalyzer test works because ethanol...Ch. 22 - Estradiol is a female hormone with the following...Ch. 22 - Prob. 173IPCh. 22 - Prob. 174IPCh. 22 - Prob. 175MPCh. 22 - Prob. 176MP
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