Campbell Biology
12th Edition
ISBN: 9780135188743
Author: Urry
Publisher: PEARSON
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Chapter 21.5, Problem 4CC
WHAT IF? Ø In 2005, Icelandic scientists reported finding a large chromosomal inversion present in 20% of north- ern Europeans, and they noted that Icelandic women with this inversion had significantly more children than women without it. What would you expect to happen to the frequency of this inversion in the Icelandic population in future generations?
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in a randomly mating laboratory population of Drosophila, 4% of the flies have black bodies, and 96% have brown bodies. Flies with brown bodies always have at least one parent with a brown body. What is the frequency of heterozygotes in this population?
0.04
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in a certain species of plant loci A, B and C have an additive effect on the colour of the flower. Alleles A, B, and C are dominant and alleles a, b and c are recessive. Knowing that a plant with genotype AAbbCc has a…
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100
80-
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Figure 13-14 Evolutionary Analysis, 4/e
©2007 Pearson Prentice Hall, Inc.
60
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(Adult progeny per female)
80-
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40-
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10-
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0
10
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lengthens lifespan but also reduces fertility
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reduces both lifespan and fertility
cannot be determined from the data provided
lengthens both lifespan and fertility
Chapter 21 Solutions
Campbell Biology
Ch. 21.1 - Describe the whole-genome shotgun approach.Ch. 21.2 - Prob. 1CCCh. 21.2 - Explain the advantage of the systems biology...Ch. 21.2 - Prob. 3CCCh. 21.2 - MAKE CONNECTIONS In Concept 20.2, you learned...Ch. 21.3 - The best estimate is that the human genome...Ch. 21.3 - The Genomes Online Database (GOLD) Website of the...Ch. 21.3 - WHAT IF? What evolutionary processes might...Ch. 21.4 - Discuss the characteristics of mammalian genomes...Ch. 21.4 - VISUAL SKILLS Which of the three mechanisms...
Ch. 21.4 - Contrast the organizations of the rRNA gene family...Ch. 21.4 - MAKE CONNECTIONS Assign each DNA segment at the...Ch. 21.5 - Describe three examples of errors in cellular...Ch. 21.5 - Explain how multiple exons might have arisen in...Ch. 21.5 - What are three ways that transposable elements are...Ch. 21.5 - WHAT IF? In 2005, Icelandic scientists reported...Ch. 21.6 - Prob. 1CCCh. 21.6 - Prob. 2CCCh. 21.6 - Prob. 3CCCh. 21 - How did the Human Genome Project result in more...Ch. 21 - What has been the most significant finding of the...Ch. 21 - Compare genome size, gene number, and gene density...Ch. 21 - Explain how the function of transposable elements...Ch. 21 - How could chromosomal rearrangements lead to the...Ch. 21 - What type of Information can be obtained by...Ch. 21 - Bioinformatics intludes all of the following...Ch. 21 - Homeotic genes (A) encode transcription factors...Ch. 21 - Prob. 3TYUCh. 21 - DRAW IT Below are the amino acid sequences(using...Ch. 21 - EVOLUTION CONNECTION Genes important in the...Ch. 21 - scientific inquiry The scientists mapping the SNPs...Ch. 21 - Prob. 7TYUCh. 21 - SYNTHESIZE YOUR KNOWLEDGE Insects have three...
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- Calculate the probability a new mutation, with one copy in the population, is lost by random genetic drift in the next generation for the following diploid populations: [a] N=5 [b] N=25 [c] N=1250arrow_forwardAbout 7% of men in a population are red-green colour blind due to a sex-linked recessive gene. Assuming random mating in the population with respect to colour blindness; c) What percentage of men would be colour blind in the next generation?arrow_forwardWhy is genetic drift more significant in small populations? Why does it take longer for genetic drift to cause allele fixation in large populations than in small ones?arrow_forward
- One of the findings from Strickland et al. 2019, was that certain color morphs among Chelymorpha alternans beetles are more common at some field sites than they are at other sites. Strickland and colleagues used cross breeding experiments to investigate these patterns and found evidence that color variation was mainly due to Mendelian inheritance. In other species, geographic variation in coloration might not be due to Mendelian genetics. (a) What is another possible explanation for geographic variation in coloration? (b) What sort of experiment could you use to test this alternative explanation?arrow_forward1.) What happens to the genotypic frequencies from generation 1 to generation 5? 2.) What process is occurring when there is a change in genotypic frequencies over a long period of time? 3.) What would happen if it were more advantageous to be heterozygous (Ff)? Would there still be homozygous fish? Explain. 4.) What happens to the recessive genes over successive generations? Explain. 5.) Why doesn't the recessive gene disappear from the population?arrow_forward180- 170- Figure 1. For each of more than 200 human societies, the average height of the men is plotted against the average height of the women. The diagonal line shows where the points would fall if men and women were of equal height. From Rogers and Mukherjee (1992). 160- 150- 140- 140 150 160 170 180 Female stature (cm) tionry ysin.e 2. Using an evolutionary approach, explain the evolution of sexual dimorphism in height among men and women, Is this difference due to natural or sexual selection? How do know? you Male stature (cm)arrow_forward
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- The average thorax length in a Drosophila population is 1.01 mm.You want to practice selective breeding to make larger Drosophila. Todo so, you choose 10 parents (5 males and 5 females) of the followingsizes: 0.97, 0.99, 1.05, 1.06, 1.03, 1.21, 1.22, 1.17, 1.19, 1.20. Youmate them and then determine the thorax lengths of 30 offspring (halfmale and half female): 0.99, 1.15, 1.20, 1.33, 1.07, 1.11, 1.21, 0.94,1.07, 1.11, 1.20, 1.01, 1.02, 1.05, 1.21, 1.22, 1.03, 0.99, 1.20, 1.10,0.91, 0.94, 1.13, 1.14, 1.20, 0.89, 1.10, 1.04, 1.01, 1.26. Calculate therealized heritability of thorax length in this group of flies.arrow_forward3. 3 I bbtal) Let's take a ślightly different look at the blue-eyed Mary Plants again. To remind you, the populations are dimorphic for dark blotches on the leaves --- some plants have blotches, and others don't. You have already determined earlier in the semester that Blotched is the dominant allele for this trait (use p for the dominant allele), and blotchless (no dark blotches on leaves) is the recessive allele for this trait (use g for the recessive allele). Leaves were sampled from each individual in a population of these plants, representing population in its entirety. The results are shown below: Remember our Hardy-Weinberg formulas: p² + 2pq +q² = 1 and p + q =1. Based solely on the phenotypic information given in the figure above, determine the following information (round to 2 decimal nlaces, please): :de d£h: q = 2pq- 2pqs What percentage of the plants are homozygous for the dominant allele?arrow_forward# 3 e A = all of the dominant alleles for a particular trait in a specific population; a = all of the recessive alleles for a particular trait in a specific population In the following equations "A" is represented by "p"; "a" is represented by "q" Hardy Weinberg equations: Allele distributions in Generation 1: 36 homozygous dominant individuals 13 heterozygous individuals 1 homozygous recessive individual There are 50 individuals in this particular population. We want to see if allele distributions change from generation to generation. We will use the Hardy Weinberg equations to find out. p+q=1.0 (100% of the alleles for this trait in the population) Explanation of terminology: px p=p² 2 xpxq=2pq qxq=q² p² + 2pq+q² = 1.0 (Don't panic! You can do this!) Due to migration and random mating of the parent generation, the percentage of homozygous recessive genotypes in Generation 2 offspring increases, changing "a" to 40%, so a = .40 If "a" = .40, and "a"=q, then q = Remember that p+q=1.0 If…arrow_forward
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