HUMAN BIOLOGY
16th Edition
ISBN: 9781260233032
Author: Mader
Publisher: RENT MCG
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Chapter 21.2, Problem 2CYP
Summary Introduction
To analyze:
The genotype of children in the given case.
Introduction:
The genotype of the parents can be used to determine the genotype of the offspring.
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A genotypic ratio of 2:4:2:2:4:2 is possible between a male who is heterozygous free earlobes and heterozygous freckles, and a
female who is homozygous free earlobes and heterozygous. Free earlobes is a dominant trait.
Key:
E = free earlobes
e = attached earlobes
F = freckles
f = no freckles
○ If the first statement is FALSE and the second statement is TRUE
O If both statements are TRUE
If the first statement is TRUE and the second statement is FALSE
O If both statements are FALSE
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Having freckles is dominant (F) and
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What is the probability they will have
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FF
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Chapter 21 Solutions
HUMAN BIOLOGY
Ch. 21.1 - Distinguish between a genotype and a phenotype.Ch. 21.1 - Define allele, gene, dominant, and recessive as...Ch. 21.1 - Prob. 3LOCh. 21.1 - Define the following terms:Â gene, allele, locus,...Ch. 21.1 - Prob. 2CYPCh. 21.1 - Prob. 3CYPCh. 21.2 - Prob. 1LOCh. 21.2 - Calculate the probability of a specific genotype...Ch. 21.2 - Prob. 1CYPCh. 21.2 - Prob. 2CYP
Ch. 21.2 - Using a dihybrid cross as an example (see Fig....Ch. 21.3 - Interpret a human pedigree to identify the pattern...Ch. 21.3 - Prob. 2LOCh. 21.3 - Solve the following: In a pedigree, all the...Ch. 21.3 - Prob. 2CYPCh. 21.3 - Explain why some incidences of autosomal recessive...Ch. 21.4 - Prob. 1LOCh. 21.4 - Prob. 2LOCh. 21.4 - Prob. 3LOCh. 21.4 - Prob. 1BTSCh. 21.4 - Prob. 2BTSCh. 21.4 - Prob. 1CYPCh. 21.4 - Prob. 2CYPCh. 21.4 - Discuss the potential evolutionary advantages of...Ch. 21.5 - Prob. 1LOCh. 21.5 - Prob. 2LOCh. 21.5 - Prob. 1CYPCh. 21.5 - Prob. 2CYPCh. 21.5 - Discuss why X-linked disorders are more common...Ch. 21.5 - Prob. 1BTSCh. 21.5 - Prob. 2BTSCh. 21 - Prob. 1ACh. 21 - 2. Which of the toll awing terms refers to...Ch. 21 - Prob. 3ACh. 21 - Prob. 4ACh. 21 - 5. The genotype of an individual with the dominant...Ch. 21 - Prob. 6ACh. 21 - Prob. 7ACh. 21 - Prob. 8ACh. 21 - Which of the following disorders is caused by a...Ch. 21 - Prob. 10ACh. 21 - Prob. 11ACh. 21 - Prob. 12ACh. 21 - Which of the following terms may be used to...Ch. 21 - Prob. 14ACh. 21 - Prob. 15ACh. 21 - Prob. 1TCCh. 21 - Prob. 2TCCh. 21 - Prob. 3TC
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- Imagine that a couple is planning to have children. The male is heterozygous for Huntington’s disease and homozygous dominant for Tay-Sachs. The female is homozygous recessive for Huntington’s disease and heterozygous for Tay-Sachs. The couple is curious about the possibility and probability of their offspring inheriting Tay-Sachs and/or Huntington’s. For humans, Huntington’s disease is dominant (H) over the “normal” condition (h), and the “normal” condition is dominant (T) over Tay-Sachs (t). Complete a Punnett square for this cross and record the probabilities for genotypes and phenotypes of the offspring as ratios.arrow_forwardIncomplete dominance is characterized by a cross between homozygous dominant and recessive genes that will result in an intermediate trait assume the following sets of genes is a human being: BB – black-colored pupil HH – straight hair Bb – blue-colored pupil Hh – wavy hair hh – curly hair A husband and wife, BBHH x bbHh, want to know the probability of having a child with a blue-colored pupil and wavy hair. What will you tell them? O There is a ¼ chance that the offspring will have blue-colored pupils and wavy hair. O There is a ½ chance that the offspring will have blue-colored pupils and wavy hair. O There is no chance that the offspring will have blue-colored pupils and wavy hair. O Impossible to determine.arrow_forwardComplete a Punnett Square for a male who is heterozygous for the polydactyly, and a female who is homozygous recessive. Polydactyly (having more than 5 fingers) is a dominant trait. Use the letter F and f to fill in the square. a) What is the male's phenotypes? b) What is the female's phenotype? c) What is the percent chance that an offspring will have more than 5 fingers? You must show your work. d) Polydactyly is very rare, yet it is a dominant trait. Explain how it is possible for a dominant trait to be rare. (Make sure to use the term "allele" in your answer).arrow_forward
- Demonstrate how males are at an increased risk of sex-linked recessive traits by crossing a female who is a carrier for Hunter syndrome with a normal male. The genotypes involved are XH, Xh, and Y. State the genotypes and phenotypes of the offspring.arrow_forwardA woman homozygous dominant for albinism marries a man who is homozygous recessive for albinism. What are the possible genotypes and phenotypes percentages for their offspring?arrow_forwardIn humans, brown eyes are dominant to blue eyes, and the ability to roll your tongue is dominant to not being able to roll your tongue. If a mother who was heterozygous for eye colour and homozygous recessive for tongue rolling had a baby with a father that was heterozygous for both traits, what is the probability that their child would have blue eyes and could roll their tongue?arrow_forward
- a couple whose genotype for eye color is bb plans to have a child. What are the possible genotypes and phenotypes of the child in terms of eye color? Note that brown eyes (B) are dominant over blue eyes(b).arrow_forwardPlease define the following terms: Gene Allele Dominant Recessive Homozygous Heterozygousarrow_forwarda. The ability to taste the chemical phenylthiocarbamideis an autosomal dominant phenotype, and the inabilityto taste it is recessive. If a taster woman with a nontasterfather marries a taster man who in a previous marriagehad a nontaster daughter, what is the probability thattheir first child will be(1) A nontaster girl(2) A taster girl(3) A taster boyb. What is the probability that their first two childrenwill be tasters of either sex?arrow_forward
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