To calculate enthalpy change ( Δ r H ∘ ) of the given reaction. Concept introduction: The change of enthalpy to form one mole of a substance from its constituent elements when all the substances in the standard form is known as standard enthalpy of formation. The standard enthalpy of reaction ( Δ r H ∘ ) in terms of standard enthalpy of formation ( Δ f H ∘ ) is written as, Δ r H ∘ = ∑ Δ f H ∘ products − ∑ Δ f H ∘ reactants (1) The change of Gibbs free energy to form one mole of a substance from its constituent elements when all the substances in the standard form is known as standard Gibbs free energy of formation ( Δ f G ° ) . If the value of standard Gibbs free energy of reaction ( Δ r G ∘ ) is positive then the reaction is reactant favored. If the value of standard Gibbs free energy of reaction ( Δ r G ∘ ) is negative then the reaction is product favoured and spontaneous.
To calculate enthalpy change ( Δ r H ∘ ) of the given reaction. Concept introduction: The change of enthalpy to form one mole of a substance from its constituent elements when all the substances in the standard form is known as standard enthalpy of formation. The standard enthalpy of reaction ( Δ r H ∘ ) in terms of standard enthalpy of formation ( Δ f H ∘ ) is written as, Δ r H ∘ = ∑ Δ f H ∘ products − ∑ Δ f H ∘ reactants (1) The change of Gibbs free energy to form one mole of a substance from its constituent elements when all the substances in the standard form is known as standard Gibbs free energy of formation ( Δ f G ° ) . If the value of standard Gibbs free energy of reaction ( Δ r G ∘ ) is positive then the reaction is reactant favored. If the value of standard Gibbs free energy of reaction ( Δ r G ∘ ) is negative then the reaction is product favoured and spontaneous.
Solution Summary: The author explains the enthalpy change of Gibbs free energy to form one mole of a substance from its constituent elements when all the substances in the standard form.
To calculate enthalpy change (ΔrH∘) of the given reaction.
Concept introduction:
The change of enthalpy to form one mole of a substance from its constituent elements when all the substances in the standard form is known as standard enthalpy of formation.
The standard enthalpy of reaction (ΔrH∘) in terms of standard enthalpy of formation (ΔfH∘) is written as,
ΔrH∘=∑ΔfH∘products−∑ΔfH∘reactants (1)
The change of Gibbs free energy to form one mole of a substance from its constituent elements when all the substances in the standard form is known as standard Gibbs free energy of formation (ΔfG°).
If the value of standard Gibbs free energy of reaction (ΔrG∘) is positive then the reaction is reactant favored. If the value of standard Gibbs free energy of reaction (ΔrG∘) is negative then the reaction is product favoured and spontaneous.
Last Name, Firs
Statifically more chances to abstract one of these 6H
11. (10pts total) Consider the radical chlorination of 1,3-diethylcyclohexane depicted below. 4
• 6H total $ 4th total
21 total
4H total
ZH
2H
Statistical
H < 3°C-H werkst
-
product
bund abstraction here
leads to the mo favored
a) (6pts) How many unique mono-chlorinated products can be formed and what are the
structures for the thermodynamically and statistically favored products?
Proclict
6
Number of Unique
Mono-Chlorinated Products
f
Thermodynamically
Favored Product
Statistically
Favored Product
b) (4pts) Draw the arrow pushing mechanism for the FIRST propagation step (p-1) for the
formation of the thermodynamically favored product. Only draw the p-1 step. You do
not need to include lone pairs of electrons. No enthalpy calculation necessary
'H
H-Cl
Waterfox
2. (a) Many main group oxides form acidic solutions when added to water. For example solid
tetraphosphorous decaoxide reacts with water to produce phosphoric acid. Write a balanced
chemical equation for this reaction.
(b) Calcium phosphate reacts with silicon dioxide and carbon graphite at elevated temperatures
to produce white phosphorous (P4) as a gas along with calcium silicate (Silcate ion is SiO3²-)
and carbon monoxide. Write a balanced chemical equation for this reaction.
I find the solution way too brief and unsatisfactory as it does not clearly explain the solution provided in the problem.
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