Genetics: Analysis and Principles
6th Edition
ISBN: 9781259616020
Author: Robert J. Brooker Professor Dr.
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 20, Problem 23CONQ
This chapter describes different types of TEs, including insertion elements, simple transposons, LTR retrotransposons, and non-LTR retrotransposons. Which of these four types of TEs have the following features?
A. Require reverse transcriptase to transpose
B. Require transposase to transpose
C. Are flanked by direct repeats
D. Have inverted repeats
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
a. Some antibiotics, such as rifampin, interfere with the function of RNA polymerase. What biological process is rifampin disrupting?
b. Some antibiotic-resistant M. tuberculosis bacteria have a single point mutation (CàT) in the rpoB gene that causes an amino acid change from serine (a polar amino acid) to leucine (a non-polar amino acid). What type of mutation is this? Do you expect this to have no effect, a small effect, or a large effect on the polypeptide produced? Explain your reasoning.
c. The rpoB gene encodes a subunit of the bacterial RNA polymerase protein. The point mutation described in Question 2 causes a change in protein folding, which leads to the inability of the rifampin antibiotic to bind to the RNA polymerase. Which level(s) of protein structure is/are affected by this change?
4) The fact that splicing is a strategy to optimize the use of the genome in eukaryotes is evidenced in C. elegans, which with 20,000 genes can synthesize more than 20,000 proteins. True or false
7) The mutation in the myostatin protein that results in mice with hypertrophied muscles results from a premature stop codon that results in a truncated (shorter than necessary) protein that loses its function of stopping cell division of muscle cells. What post-transcriptional quality control mechanisms fail here? (two apply)
a) polyadenylation b) NMD c) splicing d) capping e) methylation
10) The nuclear transplant experiment results in:
a) KO or knockout b) transgenic organisms c) RNAi (interference) d) animal cloning
Using the transcription unit diagrammed below, in which exons are represented by blue boxes and introns are represented by the connecting lines.
You discover a single base deletion in region E of this DNA sequence. Regarding transcription, this mutation will likely:
1.) Result in an alteration to the mRNA sequence.
2.)Have no effect on transcription or the mRNA sequence
3.)Prevent transcription at the TATAA box
4.) Result in an increase or decrease in the amount of mRNA transcribed
Chapter 20 Solutions
Genetics: Analysis and Principles
Ch. 20.1 - 1. Homologous recombination refers to the exchange...Ch. 20.1 - During the molecular process of homologous...Ch. 20.1 - 3. A key difference between the original Holliday...Ch. 20.1 - Which of the following mechanisms can cause gene...Ch. 20.2 - 1. During site-specific recombination that occurs...Ch. 20.2 - Prob. 2COMQCh. 20.3 - Which of the following types of transposable...Ch. 20.3 - Prob. 2COMQCh. 20.3 - Prob. 3COMQCh. 20 - 1. Describe the similarities and differences...
Ch. 20 - Prob. 2CONQCh. 20 - 3. Which steps in the double-strand break model...Ch. 20 - Prob. 4CONQCh. 20 - Prob. 5CONQCh. 20 - Prob. 6CONQCh. 20 - Prob. 7CONQCh. 20 - 8. What is gene conversion?
Ch. 20 - Make a list of the differences between the...Ch. 20 - Prob. 10CONQCh. 20 - Prob. 11CONQCh. 20 - 12. According to the double-strand break model,...Ch. 20 - What type of DNA structure is recognized by RecG...Ch. 20 - Briefly describe three ways that antibody...Ch. 20 - 15. Describe the functions of the RAG1 and RAG2...Ch. 20 - According to the scenario shown in Figure 20.7,...Ch. 20 - Prob. 17CONQCh. 20 - Prob. 18CONQCh. 20 - 19. Why does transposition always produce direct...Ch. 20 - 20. Which types of TEs have the greatest potential...Ch. 20 - Prob. 21CONQCh. 20 - 22. Let’s suppose that a species of mosquito has...Ch. 20 - This chapter describes different types of TEs,...Ch. 20 - Prob. 24CONQCh. 20 - Prob. 25CONQCh. 20 - 26. What is the difference between an autonomous...Ch. 20 - 1. Briefly explain how McClintock determined that...Ch. 20 - The work of McClintock showed that the presence of...Ch. 20 - 3. In your own words, explain the term transposon...Ch. 20 - Prob. 4EQCh. 20 - 5. Gerald Rubin and Allan Spradling devised a...Ch. 20 - Make a list of the similarities and differences...Ch. 20 - Prob. 2QSDCCh. 20 - Prob. 3QSDC
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- A molecular geneticist hopes to find a gene in human liver cells that codes for an important blood-clotting. He knows that the nucleotide sequence of a small part of the gene is GTGGACTGACA. Briefly explain how to obtain the desired gene.arrow_forwardWhich of the following statements is true regarding the lys2-128d reporter? Select all that apply. a.) Mutants that activate this reporter are likely to have mutations in PIC components. b.) This reporter is sensitive to changes in chromatin maintenance because the start site is located within the ORF. c.) Mutants that activate this reporter cause downstream shifts in transcription start site selection. d.) This reporter is being used to help us rule out mutations that are likely impacting chromatin structure.arrow_forwardTay Sachs disease is an autosomal recessive disease in which a protein – Hex A - is abnormal. To make the Hex A protein: The promoter and transcription termination sites are 33,000 base pairs apart. The Hex A protein has 600 amino acids 5’ and 3’ UTR’s are each 500 bp long. a)How many base pairs would you expect in the final mRNA? Show your work b)How many bases were spliced out? Show your workarrow_forward
- A molecular geneticist hopes to find a gene in human liver cells that codes for an important blood-clotting protein. He knows that the nucleotife sequence of a small part of the gene is GTGGACTGACA. Briefly explain how to obtain the desired gene.arrow_forwardRetrotransposons are a class of mobile elements that transpose via an RNA intermediate. Contrast the mechanism of transposition between retrotransposons that contain long terminal repeats (LTRs) and those that lack LTRs.arrow_forwardSome organisms have mechanisms in place that will override transcription termination. One such mechanism using the Tat protein is employed by the HIV retrovirus. Explain why Tat is therefore a good target for HIV vaccination.arrow_forward
- Huntington’s disease is a hereditary central nervous system disorder characterized by tandem repeats of the sequence 5'-CAG-3' in the gene that encodes a protein called huntingtin. The disease is progressive from generation to generation, meaning that in later generations the number of CAG repeats increases and the age of onset of symptoms decreases. Refer to Figure 21.4 and describe the sort of evidence supporting the generational increase in the number of CAG repeats.arrow_forwardIn the treatment of acquired immunodeficiency syndrome (AIDS), a possible mode of therapy is to inhibit the reverse transcriptase (RT) of the human immunodeficiency virus (HIV), whcih is required for the retrovirus to be propogated by RNA-directed DNA synthesis. In the figure below, one of the substrates for RT is thymidine; and two drugs, AZT and HBY097 are known to inhibit HIV RT> (a) Thymidine; (b) AZT; (c) HBY097 Look at the structures and predict the type of inhibition (i.e. competitive or non-competitive) likely to be shown by each drug. By using knowledge on enzyme, plan an experiment that would enable you to confirm the type of inhibition by investigating enzyme kinetics and explain how you would interpret the results.Remarks: Not more than 250 words.arrow_forwardSpeculate as to why eukaryotes have either a) much more complex promoter and enhancer regions than prokaryotes or b) intron exon structure while prokaryotes do not.arrow_forward
- A newly identified protein from the cells of the Panopyra plant on Pandora was shown to inhibit translation of its target genes by binding to the 5’ UTR of the mRNA and preventing ribosome binding. A possible way this inhibition may be relieved by an sRNA would be: Group of answer choices a)The sRNA acts as a silencer, suppressing the inhibitory protein and allowing translation to take place. b)The sRNA acts as a decoy, sequestering the inhibitory protein and allowing translation to take place. c)The sRNA acts as a marker, flagging the inhibitory protein for ubiquitination and allowing translation to take place.arrow_forwardWhich of the following statements concerning the sequence of events involved in the initiation of transcription by E. coli RNA polymerase are correct? ( can bemore than one) A.)Initiation starts with a pyrimidine nucleotide triphosphate. B.)The sigma factor (σ) functions during initiation of transcription. C.)Initiation starts with a purine nucleotide triphosphate, which is destined to become the 5'-end of RNA. D.)Initiation starts with a purine nucleotide triphosphate, which is destined to become the 3'-end of RNA. E.)RNA polymerase binds to the DNA at a point approximately 35 bp upstream of the start of transcription, at a sequence TTGACA. F.)The sigma factor does not dissociate until RNA elongation is complete.arrow_forwardMatch the following terms related to transcription in eukaryotes (you may use terms more than once or not at all) A) RNA Polymerase I, B) RNA Polymerase II, C) RNA Polymerase III, D) All 3 RNA Polymerases E) None of the above 1. Driven only by downstream promoter elements __________ 2. Promoter contains TATA box __________ 3. rRNA __________ 4. tRNA __________ 5. mRNA __________ 6. snRNA __________ 7. A second class of promoters contains CAAT box 100-200 nucleotides from the start site of transcription __________ 8. Synthesize RNA 5’ to 3’ __________ 9. Synthesizes RNA 3’ to 5’ __________ 10. Very sensitive to α-amanitin __________arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Human Anatomy & Physiology (11th Edition)BiologyISBN:9780134580999Author:Elaine N. Marieb, Katja N. HoehnPublisher:PEARSON
Biology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStax
Anatomy & PhysiologyBiologyISBN:9781259398629Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa StouterPublisher:Mcgraw Hill Education,
Molecular Biology of the Cell (Sixth Edition)BiologyISBN:9780815344322Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter WalterPublisher:W. W. Norton & Company
Laboratory Manual For Human Anatomy & PhysiologyBiologyISBN:9781260159363Author:Martin, Terry R., Prentice-craver, CynthiaPublisher:McGraw-Hill Publishing Co.
Inquiry Into Life (16th Edition)BiologyISBN:9781260231700Author:Sylvia S. Mader, Michael WindelspechtPublisher:McGraw Hill Education
Human Anatomy & Physiology (11th Edition)
Biology
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:PEARSON
Biology 2e
Biology
ISBN:9781947172517
Author:Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher:OpenStax
Anatomy & Physiology
Biology
ISBN:9781259398629
Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa Stouter
Publisher:Mcgraw Hill Education,
Molecular Biology of the Cell (Sixth Edition)
Biology
ISBN:9780815344322
Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter Walter
Publisher:W. W. Norton & Company
Laboratory Manual For Human Anatomy & Physiology
Biology
ISBN:9781260159363
Author:Martin, Terry R., Prentice-craver, Cynthia
Publisher:McGraw-Hill Publishing Co.
Inquiry Into Life (16th Edition)
Biology
ISBN:9781260231700
Author:Sylvia S. Mader, Michael Windelspecht
Publisher:McGraw Hill Education
QCE Biology: Introduction to Gene Expression; Author: Atomi;https://www.youtube.com/watch?v=a7hydUtCIJk;License: Standard YouTube License, CC-BY