Chapter 2, Problem 52R

To determine

To Find:The average speed of the cyclist in each direction.

Answer to Problem 52R

The time taken by the cyclist in east trip is $1.5\text{h}$ and returning trip is $\text{2}\text{.5}\text{h}$

Explanation of Solution

Given:

Distance travel by the cyclist is $45\text{km}$

Entire tripe time is $\text{4}\text{h}$

  $\text{30 min}$ In return time

Formula:

Average speed of an object is given by

  $s\text{=}\frac{d}{t}$

Here, $s$ is speed, $d$ is distance and $t$ is time.

Calculation:

The cyclist travel distance at $\text{4}\text{h}$ is $45\text{km+45}\text{km}\text{=}\text{90}\text{km}$

Science it take $\text{30 min}$ more in returning trip so total time taken by the cyclist in east trip is

  $\begin{array}{l}=\left(\frac{4\text{h}}{2}\right)-30\min \\ =1.5\text{h}\end{array}$

Again time taken by the cyclist to returning trip is

  $\begin{array}{l}=4\text{h}-1.5\text{h}\\ \text{=}\text{2}\text{.5}\text{h}\end{array}$

Conclusion:

Hence, the time taken by the cyclist in east trip is $1.5\text{h}$ and returning trip is $\text{2}\text{.5}\text{h}$