Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
1st Edition
ISBN: 9780078945830
Author: Charles William McLaughlin, Marilyn Thompson, Dinah Zike
Publisher: Glencoe Mcgraw-Hill
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Chapter 2, Problem 11STP
To determine

To identify: the swimmer that had the highest average speed over the time interval of 30 min.

To explain: above the phenomenon.

Expert Solution & Answer
Check Mark

Answer to Problem 11STP

Swimmer C has the greatest average speed over the given time interval.

Explanation of Solution

Given:

The given distance vs. time graph is shown below

  Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education), Chapter 2, Problem 11STP

Formula used:

The average speed is

  s=dt  ...... (1)

Here, d and t are distance and time taken to travel.

Calculation:

The slop of the distance-time graph is the speed of the runner. From the graph, it is found that the slope of swimmer C is greater than other swimmers. This represents that the average speed of swimmer C is greatest over the time interval of 30 min.

Conclusion:

Hence, swimmer C has the greatest average speed over the given time interval.

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