Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
Glencoe Physical Science 2012 Student Edition (Glencoe Science) (McGraw-Hill Education)
1st Edition
ISBN: 9780078945830
Author: Charles William McLaughlin, Marilyn Thompson, Dinah Zike
Publisher: Glencoe Mcgraw-Hill
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Chapter 2, Problem 51R

(a)

To determine

To Find:The average speed of the cyclist.

(a)

Expert Solution
Check Mark

Answer to Problem 51R

The speed of the cyclist is 22.4km/h

Explanation of Solution

Given:

Distance travel by the cyclist is 45km

Entire tripe time is 4h

Formula:

Average speed of an object is given by

  s=dt

Here, s is speed, d is distance and t is time.

Calculation:

The cyclist travel distance at 4h is 45km+45km=90km

Therefore its speed is

  =90km4h=22.4km/h

Conclusion:

Hence, the speed of the cyclist is 22.4km/h

(b)

To determine

To Find:The displacement travel by the cyclist.

(b)

Expert Solution
Check Mark

Answer to Problem 51R

The displacement of the cyclist is 0km

Explanation of Solution

Given:

Distance travel by the cyclist is 45km

Entire tripe time is 4h

Calculation:

Science the cyclist travel at a point and then return to the initial point so the displacement of the cyclist in 4h is 45km-45km=0km .

Conclusion:

Hence, the displacement of the cyclist is 0km

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Position/Velocity/Acceleration Part 1: Definitions; Author: Professor Dave explains;https://www.youtube.com/watch?v=4dCrkp8qgLU;License: Standard YouTube License, CC-BY