Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 2, Problem 36P
You have four guinea pigs for a genetic study. One male and one female are from a strain that is pure-breeding for short brown fur. A second male and female are from a strain that is pure-breeding for long white fur. You are asked to perform two different experiments to test the proposal that short fur is dominant to long fur and that brown is dominant to white. You may use any of the four original pure-breed-ing guinea pigs or any of their offspring in experimental matings. Design two different experiments (crossing dif-ferent animals and using different combinations of pheno-types) to test the dominance relationships of alleles for fur length and color, and make predictions for each cross based on the proposed relationships. Anticipate that the litter size will be 12 for each mating and that female guinea pigs can produce three litters in their lifetime.
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In this program, you are provided with phenotype pair counts of
F2 offspring at two research institutes. The key different between
this work and previous work is that now we consider two genes instead of one.
The phenotype pairs are the (shape, color) of peas from a pea plant. It turns out
that there are two separate genes that code for these phenotypes. We shall call them
Shape and Color. Gregor Mendel originally recorded these experiments in
green peas. Using the notation:
R = Round (dominant) allele at Shape gene;
r = Wrinkled (recessive) allele at Shape gene;
Y = Yellow (dominant) allele at Color gene;
y = Green (recessive) allele at Color gene;
then the shape and color of any pea can be determined
by studying the genotypes at each gene.
It turns out that, when one mates a plant that is homozygous for the dominant
alleles (RRYY) with a plant that is homozygous for the recessive alleles (rryy),
the F1 generation are heterozygous at both genes, as with a single gene disorder.…
You are studying three linked genes in snapdragons. The flower color locus is in the center. There are 8.3 cM between the
flower color locus and the plant height locus. There are 12.4 cM between the flower color locus and the leaf type locus. The
coefficient of coincidence is 0.8. Pure-breeding tall, red-flowered plants with fuzzy leaves were crossed to pure-breeding
dwarf, blue-flowered plants with smooth leaves. The F1 were testcrossed. Calculate the proportion of the testcross progeny
that are expected to have red flowers and fuzzy leaves. Round properly to 4 decimal digits.
Answer:
Below is a partially filled in complementation table. Please answer the following questions.
1
2
3
4
LO
5
6
1
2
I
3 4 5
4
+
+
5 6
a. If you were to perform a complementation test with mutants 1 and 2, what would be the result?
[Select]
b. If you were to perform a complementation test with mutants 5 and 6, what would be the result?
[Select]
c. If you were to perform a complementation test with mutants 3 and 4, what would be the result?
[Select]
d. There is one complementation group that you can determine from the information above. If you
performed a complementation test with mutant 1 and 6 and there was growth, would you say that
the mutants were part of that complementation group? [Select]
e. What is the minimum number of complementation groups that could exist based on the
information above? [Select]
f. What is the maximum number of complementation groups that could exist based on the
information above? [Select]
Chapter 2 Solutions
Genetic Analysis: An Integrated Approach (3rd Edition)
Ch. 2 -
1. Compare and contrast the following terms:
a....Ch. 2 - For the cross , what is the expected genotype...Ch. 2 - 37. Galactosemia is an autosomal recessive...Ch. 2 - In mice, black coat color is dominant to white...Ch. 2 - Two parents plan to have three children. What is...Ch. 2 - Consider the cross AaBbCCAABbCc. a. How many...Ch. 2 - If a chi-square test produces a chi-square value...Ch. 2 -
8. Determine whether the statements below are...Ch. 2 - In the datura plant, purple flower color is...Ch. 2 - 10. The dorsal pigment pattern of frogs can be...
Ch. 2 - 11. Black skin color is dominant to pink skin...Ch. 2 - A male mouse with brown fur color is mated to two...Ch. 2 - 13. Figure 2.12 shows the results of Mendel’s...Ch. 2 - 14. An experienced goldfish breeder receives two...Ch. 2 -
15. The accompanying pedigree shows the...Ch. 2 -
16. A geneticist crosses a pure-breeding strain...Ch. 2 - Suppose an F1 plant from Problem 16 is crossed to...Ch. 2 - 18. In pea plants, the appearance of flowers along...Ch. 2 - 19. If two six-sided dice are rolled, what is the...Ch. 2 - Experimental Insight 2.1 describes data, collected...Ch. 2 -
21. The accompanying pedigree shows the...Ch. 2 - 22. The seeds in bush bean pods are each the...Ch. 2 - List all the different gametes that are possible...Ch. 2 - Organisms with the genotypes AABbCcDd and AaBbCcDd...Ch. 2 - 25. Blue moon beans produce beans that are either...Ch. 2 - In the fruit fly Drosophila, a rudimentary wing...Ch. 2 - In pea plants, plant height, seed shape, and seed...Ch. 2 - A variety of pea plant called Blue Persian...Ch. 2 - 29. In tomato plants, the production of red fruit...Ch. 2 - A male and a female are each heterozygous for both...Ch. 2 - A woman expressing a dominant phenotype is...Ch. 2 - Two parents who are each known to be carriers of...Ch. 2 - 33. An organism having the genotype AaBbCcDdEe is...Ch. 2 - 34. A man and a woman are each heterozygous...Ch. 2 - For a single dice roll, there is a 16 chance that...Ch. 2 - You have four guinea pigs for a genetic study. One...Ch. 2 - 37. Galactosemia is an autosomal recessive...Ch. 2 - Sweet yellow tomatoes with a pear shape bring a...Ch. 2 - A cross between a spicy variety of Capsicum annum...Ch. 2 - Alkaptonuria is an infrequent autosomal recessive...Ch. 2 - 41. Humans vary in many ways from one another....Ch. 2 - 42. In chickens, the presence of feathers on the...Ch. 2 -
43. A pure-breeding fruit fly with the...Ch. 2 - 44. Situs inversus is a congenital condition in...Ch. 2 - 45. Domestic dogs evolved from ancestral grey...Ch. 2 - Alleles of the IGF-1 gene in dogs, encoding...Ch. 2 - 47. The accompanying pedigree shows a family in...Ch. 2 -
48. A pea plant that has the genotype RrGgwwdd is...Ch. 2 - Go to the OMIM website...Ch. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 -
52. In humans, the ability to bend the thumb...
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