Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 2, Problem 42P
In chickens, the presence of feathers on the legs is due to a dominant allele (F), and the absence of leg feath-ers is due to a recessive allele (f). The comb on the top of the head can be either pea-shaped, a
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In a species of plant, two genes control flower color. The redallele (R) is dominant to the white allele (r); the color-producingallele (C) is dominant to the non-color-producing allele (c). Yoususpect that either an rr homozygote or a cc homozygote willproduce white flowers. In other words, rr is epistatic to C, andcc is epistatic to R. To test your hypothesis, you allowed heterozygousplants (RrCc) to self-fertilize and counted the phenotypesof the offspring. You obtained the following data: 201 plantswith red flowers and 144 with white flowers. Conduct a chisquare test to see if your observed data are consistent with yourhypothesis.
In chickens, comb shape is determined by genes at two loci (R, r and P, p). A walnut comb is produced when at least one dominant gene R is present
at one locus and at least one dominant gene P is present at a second locus (genotype R_ P_). A rose comb is produced when at least one dominant
gene is present at the first locus and two recessive genes are present at the second locus (genotype R_ pp). A pea comb is produced when two
recessive genes are present at the first locus and at least one dominant gene is present at the second (genotype rr P_). If two recessive genes are
present at the first and the second locus (rr pp), a single comb is produced. Give genotypes for comb shape of the parents in the following cross:
Rose crossed with pea produces 20 walnut offspring.
O A. Rr pp x Rr Pp
B. Rr pp x rr PP
C. Rr pp x rr Pp
D. RR pp x rr PP
O E. RR pp x rr Pp
Reset Selection
Mark for Douiouu
In chickens, a dominant hereditary abnormality (e.g., creepers) causes death when the genotype is homozygous (CC). The recessive condition (cc) at this locus produces a normal phenotype. Another gene locus with co dominant alleles is known to govern feather color such that the
genotype FF = black, ff = splashed white, and Ff = blue. Also, a completely dominant gene W produces white skin. Yellow skin is produced by the homozygous genotype ww.
QUESTIONS:
In CcFfWw x ccffWw, what proportion of the offspring is:
b.2 normal, white feathered, white skinned
b.3 yellow skinned
Chapter 2 Solutions
Genetic Analysis: An Integrated Approach (3rd Edition)
Ch. 2 -
1. Compare and contrast the following terms:
a....Ch. 2 - For the cross , what is the expected genotype...Ch. 2 - 37. Galactosemia is an autosomal recessive...Ch. 2 - In mice, black coat color is dominant to white...Ch. 2 - Two parents plan to have three children. What is...Ch. 2 - Consider the cross AaBbCCAABbCc. a. How many...Ch. 2 - If a chi-square test produces a chi-square value...Ch. 2 -
8. Determine whether the statements below are...Ch. 2 - In the datura plant, purple flower color is...Ch. 2 - 10. The dorsal pigment pattern of frogs can be...
Ch. 2 - 11. Black skin color is dominant to pink skin...Ch. 2 - A male mouse with brown fur color is mated to two...Ch. 2 - 13. Figure 2.12 shows the results of Mendel’s...Ch. 2 - 14. An experienced goldfish breeder receives two...Ch. 2 -
15. The accompanying pedigree shows the...Ch. 2 -
16. A geneticist crosses a pure-breeding strain...Ch. 2 - Suppose an F1 plant from Problem 16 is crossed to...Ch. 2 - 18. In pea plants, the appearance of flowers along...Ch. 2 - 19. If two six-sided dice are rolled, what is the...Ch. 2 - Experimental Insight 2.1 describes data, collected...Ch. 2 -
21. The accompanying pedigree shows the...Ch. 2 - 22. The seeds in bush bean pods are each the...Ch. 2 - List all the different gametes that are possible...Ch. 2 - Organisms with the genotypes AABbCcDd and AaBbCcDd...Ch. 2 - 25. Blue moon beans produce beans that are either...Ch. 2 - In the fruit fly Drosophila, a rudimentary wing...Ch. 2 - In pea plants, plant height, seed shape, and seed...Ch. 2 - A variety of pea plant called Blue Persian...Ch. 2 - 29. In tomato plants, the production of red fruit...Ch. 2 - A male and a female are each heterozygous for both...Ch. 2 - A woman expressing a dominant phenotype is...Ch. 2 - Two parents who are each known to be carriers of...Ch. 2 - 33. An organism having the genotype AaBbCcDdEe is...Ch. 2 - 34. A man and a woman are each heterozygous...Ch. 2 - For a single dice roll, there is a 16 chance that...Ch. 2 - You have four guinea pigs for a genetic study. One...Ch. 2 - 37. Galactosemia is an autosomal recessive...Ch. 2 - Sweet yellow tomatoes with a pear shape bring a...Ch. 2 - A cross between a spicy variety of Capsicum annum...Ch. 2 - Alkaptonuria is an infrequent autosomal recessive...Ch. 2 - 41. Humans vary in many ways from one another....Ch. 2 - 42. In chickens, the presence of feathers on the...Ch. 2 -
43. A pure-breeding fruit fly with the...Ch. 2 - 44. Situs inversus is a congenital condition in...Ch. 2 - 45. Domestic dogs evolved from ancestral grey...Ch. 2 - Alleles of the IGF-1 gene in dogs, encoding...Ch. 2 - 47. The accompanying pedigree shows a family in...Ch. 2 -
48. A pea plant that has the genotype RrGgwwdd is...Ch. 2 - Go to the OMIM website...Ch. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 -
52. In humans, the ability to bend the thumb...
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- In the yawncat (a rare hypothetical animal), the dominant allele R causes solid tail color, and the recessive allele r results in white spots on a colored background. The black coat color allele B is dominant to the brown allele b, but the B and b alleles can only be expressed if the animal has an mm genotype at a third gene locus. Animals that are M_ are yellow regardless of which allele from the B locus is present. A mating between a solid yellow-tailed male yawncat and a solid brown-tailed female yawncat produces 16 offspring with the following tail phenotypes: six solid yellow, two spotted yellow, three solid black, one spotted black, three solid brown, and one spotted brown. What is the probability of the next offspring from these same two parents having a spotted brown tail? O A. 1/16 B. 9/16 С. 3/16 D. 1/2 O E. 1/4arrow_forwardIn chickens, comb shape is determined by genes at two loci (Gene 1 has alleles R, r and Gene 2 has alleles P, p). A walnut comb is produced when at least one dominant gene R is present at one locus and at least one dominant gene P is present at a second locus (genotype R_P). The genotype R_pp gives a rose comb phenotype; rrP_gives a pea comb phenotype; and rrpp gives a single comb phenotype. Based on this information give specific genotypes for comb shape of the parents in the crosses listed below: A) Walnut crossed with single produces 1 walnut, 1 rose, 1 pea and 1 single offspring. B) Rose crossed with pea produces 20 walnut offspring. C) Pea crossed with single produces 1 single offspring.arrow_forwardIn Labrador retriever dogs, two alleles (B and b) determine whether coat colour will be black (B)or brown (b). Black coat colour is dominant. A second pair of alleles, E and e, are on a separatechromosome from B and b. The homozygous recessive condition, ee, prevents the expressionof either allele B or b, and produces a dog with a yellow-coloured coat. Some examples ofgenotypes and phenotypes for Labrador retrievers are shown below.Genotype PhenotypeBBEe blackbbEe brownBbee yellow Two dogs, each with the genotype, BbEe, were crossed. What is the percentageprobability that their offspring will have yellow coat colour? (Record your answer as awhole number percentage)arrow_forward
- In Shorthorn cattle, coat color is controlled by a single gene thatcan exist as a red allele (R) or a white allele (r). The heterozygotes (Rr) have a color called roan that looks less red than theRR homozygotes. However, when examined carefully, the roanphenotype in cattle is actually due to a mixture of completelyred hairs and completely white hairs. Should this be calledincomplete dominance, codominance, or something else?Explain your reasoningarrow_forwardIn onions, presence of gene C causes production of an enzyme which catalyzes theproduction of bulb-color pigment. Gene K prevents this enzyme from functioning, thuspreventing enzyme production. The two genes are inherited independently. A true breedingcolored variety is crossed with a white one of genotype ccKK. (a) what are the expectedphenotypes and ratios in the F1 and F2. (b) Another pair of alleles R and r, independent ofgenes C and K controls the specific color for bulbs, R giving red and r, yellow bulbs. If thetrue-breeding colored variety are homozygous for R and the white ones homozygous for r,what would be the phenotypic ratios in the F1 and F2 of the above cross?arrow_forwardIn a species of plant, two genes control flower color. The red allele(R) is dominant to the white allele (r); the color-producing allele(C) is dominant to the non-color-producing allele (c). You suspectthat either an rr homozygote or a cc homozygote will producewhite flowers. In other words, rr is epistatic to C, and cc is epistatic to R. To test your hypothesis, you allow heterozygous plants(RrCc) to self-fertilize and count the offspring. You obtain the following data: 201 plants with red flowers and 144 with white flowers. Conduct a chi square analysis to see if your observed data areconsistent with your hypothesis.arrow_forward
- As seen in the photo, Labradors come in three colors-- black, brown and yellow. What is the genetic basis for these different coat colors? One gene produces melanin, a pigment which is deposited in the dog's fur and makes the color dark. With this gene, allele B (black) is dominant to allele b. Only in the case of a recessive homozygote (bb) will the dog's phenotype be brown. The regulatory gene is separate from the melanin gene but it acts as a switch, either turning the melanin gene on or turning it off. Allele E is dominant and allows for the melanin to be deposited in the dog's fur ("on" switch), but if the switch gene is a recessive homozygote, the melanin is blocked ("off" switch) and a yellow dog is the result! 1. Two other Labradors mate and produce puppies. Their genotypes are Bbee and BbEe. What color are each parent and what are the phenotypic rations of their offspring in the F1 Generation? Show your work with a Punnett square.arrow_forwardAs seen in the photo, Labradors come in three colors-- black, brown and yellow. What is the genetic basis for these different coat colors? One gene produces melanin, a pigment which is deposited in the dog's fur and makes the color dark. With this gene, allele B (black) is dominant to allele b. Only in the case of a recessive homozygote (bb) will the dog's phenotype be brown. The regulatory gene is separate from the melanin gene but it acts as a switch, either turning the melanin gene on or turning it off. Allele E is dominant and allows for the melanin to be deposited in the dog's fur ("on" switch), but if the switch gene is a recessive homozygote, the melanin is blocked ("off" switch) and a yellow dog is the result! Review the information on Labrador retrievers above. What are the phenotypic ratios of the F1 generation offspring of two dihybrids? Make sure to match the numbers with coat colors (e.g, which number in the ration goes with which color). Use a Punnett square to…arrow_forwardIn chickens, comb shape is determined by alleles at two loci (R, r and P,p). A walnut comb is produced when at least one dominant allele R ispresent at one locus and at least one dominant allele P is present at asecond locus (genotype R_ P_). A rose comb is produced when at leastone dominant allele is present at the first locus and two recessive allelesare present at the second locus (genotype R_ pp). A pea comb isproduced when two recessive alleles are present at the first locus and atleast one dominant allele is present at the second (genotype rr P_). Iftwo recessive alleles are present at the first and at the second locus (rrpp), a single comb is produced. Progeny with what types of combs andin what proportions will result from the following crosses? a. RR PP × rr pp b. Rr Pp × rr pp c. Rr Pp × Rr Pp d. Rr pp × Rr pp e. Rr pp × rr Pp f. Rr pp × rr pparrow_forward
- In peaches fuzzy skin (F) is completely dominant to smooth, nectarine skin (f). The gland at the base of the leaves is controlled by a separate, unlinked locus. The gland in heterozygotes is round, while homozygotes with the Go allele have oval glands, and homozygotes with the the GN allele have no glands. A homozygous fuzzy, no-gland peach variety is bred to a smooth, oval-gland variety. The F1 offspring are interbred to produce the F2 generation. What fraction of the F2 offspring will be smooth with round glands? A) 3/16 B) 7/16 C) 4/16 D) 6/16 E) 9/16 F) 2/16 G) 12/16 H) 1/16arrow_forwardThe white Leghorn breed of chickens is homozygous for the dominant allele C, which produces colored feathers. However, this breed is also homozygous for the dominant allele I of an independently assorting gene that inhibits coloration of the feathers. Consequently, Leghorn chickens have white feathers. The white Wyandotte breed of chickens has neither the allele for color nor the inhibitor of color; it is therefore genotypically cc ii. What are the F2 phenotypes and proportions expected from intercrossing the progeny of a white Leghorn hen and a white Wyandotte rooster?arrow_forwardIn Drosophila, an allele causing vestigial wings is 12.5 mu awayfrom another allele that causes purple eyes. A third gene that affectsbody color has an allele that causes black body color. Thisthird gene is 18.5 mu away from the vestigial wings allele and 6mu away from the allele causing purple eyes. The alleles causingvestigial wings, purple eyes, and black body are all recessive.The dominant (wild-type) traits are long wings, red eyes, and graybody. A researcher crossed wild-type flies to flies with vestigialwings, purple eyes, and black bodies. All F1 flies were wild type.F1 female flies were then crossed to male flies with vestigial wings,purple eyes, and black bodies. If 1000 offspring were observed,what are the expected numbers of the following types of flies? long wings, red eyes, gray bodylong wings, purple eyes, gray bodylong wings, red eyes, black bodylong wings, purple eyes, black bodyshort wings, red eyes, gray bodyshort wings, purple eyes, gray bodyshort wings, red eyes,…arrow_forward
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