The largest mass lifted through a height h in the expression needs to be determined. Concept Introduction: The change in internal energy is calculated as follows: Δ U = n C V . m ( T f − T i ) Here, n is number of moles, C V , m is molar heat at constant volume and T is temperature. The work done is represented as follows: w = − P external Δ V Here, P is external pressure and Δ V is change in volume. The enthalpy of a reaction is represented as follows: Δ H = Δ U + n R Δ T Here, n is number of moles, R is Universal gas constant and Δ T is change in temperature.

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Answer 1

Question

Chapter 2, Problem 2.39NP

(a)

Interpretation Introduction

Interpretation: The largest mass lifted through a height h in the expression needs to be determined.

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

(b)

Interpretation Introduction

Interpretation: The smallest mass that must fall through the height in order to restore the system needs to be determined.

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

(c)

Interpretation Introduction

Interpretation: The values of masses needs to be calculate in part (a) and (b).

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

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Students have asked these similar questions

Assume N₂ behaves as perfect gas. It expands reversibly and adiabatically from Vi to Vf with the pressure change from pi to pf. (a) Derive the temperature versus volume relationship and the pressure and volume relationship for this expansion. (b) When a sample of N₂ of mass 3.12 g at 23.0 °C is allowed to expand reversibly and adiabatically from 4.00 × 10² cm3 to 2.00 dm3, what is the work done by the gas?

A 1.65 mole sample of an ideal gas for which Cv, m = 3/2 R undergoes the following two-step process: (a) From an initial state of the gas described by T = 14.5 oC and P = 2x104 Pa, the gas undergoes isothermal expansion against a constant external pressure of 1.0x104 Pa until the volume has doubled. (b) Then the gas is cooled to constant volume. The temperature drops to -35.6 oC. Calculate q, w, ΔH, ΔU for each step and for the overall process.

A sample of 2.2 mol CO2(g) is originally confined in 15 dm3 at 280 K and then undergoes adiabatic expansion against a constant pressure of 78.5 kPa until the volume has increased by a factor of 4.0. Calculate ΔT. (The final pressure of the gas is not necessarily 78.5 kPa.)

Answer 2

Question

Chapter 2, Problem 2.39NP

(a)

Interpretation Introduction

Interpretation: The largest mass lifted through a height h in the expression needs to be determined.

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

(b)

Interpretation Introduction

Interpretation: The smallest mass that must fall through the height in order to restore the system needs to be determined.

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

(c)

Interpretation Introduction

Interpretation: The values of masses needs to be calculate in part (a) and (b).

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 2, Problem 2.39NP

(a)

Interpretation Introduction

Interpretation: The largest mass lifted through a height h in the expression needs to be determined.

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

(b)

Interpretation Introduction

Interpretation: The smallest mass that must fall through the height in order to restore the system needs to be determined.

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

(c)

Interpretation Introduction

Interpretation: The values of masses needs to be calculate in part (a) and (b).

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 2, Problem 2.39NP

(a)

Interpretation Introduction

Interpretation: The largest mass lifted through a height h in the expression needs to be determined.

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

(b)

Interpretation Introduction

Interpretation: The smallest mass that must fall through the height in order to restore the system needs to be determined.

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

(c)

Interpretation Introduction

Interpretation: The values of masses needs to be calculate in part (a) and (b).

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 2, Problem 2.39NP

(a)

Interpretation Introduction

Interpretation: The largest mass lifted through a height h in the expression needs to be determined.

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

(b)

Interpretation Introduction

Interpretation: The smallest mass that must fall through the height in order to restore the system needs to be determined.

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

(c)

Interpretation Introduction

Interpretation: The values of masses needs to be calculate in part (a) and (b).

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

Answer 6

Chapter 2, Problem 2.39NP

(a)

Interpretation Introduction

Interpretation: The largest mass lifted through a height h in the expression needs to be determined.

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

Answer 7

Chapter 2, Problem 2.39NP

(a)

Interpretation Introduction

Interpretation: The largest mass lifted through a height h in the expression needs to be determined.

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

Answer 8

(b)

Interpretation Introduction

Interpretation: The smallest mass that must fall through the height in order to restore the system needs to be determined.

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

Answer 9

(b)

Interpretation Introduction

Interpretation: The smallest mass that must fall through the height in order to restore the system needs to be determined.

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

Answer 10

(c)

Interpretation Introduction

Interpretation: The values of masses needs to be calculate in part (a) and (b).

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

Answer 11

(c)

Interpretation Introduction

Interpretation: The values of masses needs to be calculate in part (a) and (b).

Concept Introduction: The change in internal energy is calculated as follows:

ΔU=nCV.m(Tf−Ti)

Here, n is number of moles, CV,m is molar heat at constant volume and T is temperature.

The work done is represented as follows:

w=−PexternalΔV

Here, P is external pressure and ΔV is change in volume.

The enthalpy of a reaction is represented as follows:

ΔH=ΔU+nRΔT

Here, n is number of moles, R is Universal gas constant and ΔT is change in temperature.

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

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Answer 15

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Solution Summary: The author explains that the largest mass lifted through a height h in the expression needs to be determined.

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