Principles of General Chemistry
Principles of General Chemistry
3rd Edition
ISBN: 9780073402697
Author: SILBERBERG, Martin S.
Publisher: McGraw-Hill College
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Chapter 2, Problem 2.29P

a)

Interpretation Introduction

Interpretation:Whether the pair H13 and H23e have same number of protons, neutrons and electrons should be determined.Also,whether the pair H13 and 23He have same mass number (A) , numbers of neutrons (N) and numbers of protons (Z) should be determined.

Concept introduction:The nuclide symbol of an atom is represented as follows:

  XZA

Where,

  • Z is an atomic number.
  • A is the mass number.
  • Xis the isotope of any element.

Mass number of a nucleus is the total number of neutrons and protons. The number of protons and electrons are same in neutral species.

Isotopes are species that have same atomic number but different mass number.The number of protonsis determined by the atomic number (Z) .

Mass number (A) of any isotope of an element is total number of neutrons (N) and total number of protons (Z) .The numbers of neutronsare determined by difference between mass number and number of protons.

a)

Expert Solution
Check Mark

Explanation of Solution

Number of protons (Z) in the pair H13 and H23e is 1 and 2 respectively.

Number of electrons in the pair H13 and H23e is 1 and 2 respectively.As to maintain neutrality, number of electrons will be the same as number of protons (Z) .

The number of neutrons in H13 is calculated as follows:

  Number of neutron(N)= Mass Number(A)Number of protons(Z)=(31)=2

The number of neutrons in H23e is calculated as follows:

  Number of neutron(N)= Mass Number(A)Number of protons(Z)=(32)=1

Therefore, H13 and H23e has same mass value (A) .

b)

Interpretation Introduction

Interpretation:Whether the pair C614 and 715N have same number of protons, neutrons and electrons should be determined.Also,whether the pair C614 and 715N have same mass number (A) , numbers of neutrons (N) and numbers of protons (Z) should be determined.

Concept introduction:The nuclide symbol of an atom is represented as follows:

  XZA

Where,

  • Z is an atomic number.
  • A is the mass number.
  • Xis the isotope of any element.

The mass number of a nucleus is the total number of neutrons and protons. The number of protons and electrons are same in neutral species.

Isotopes are species that have same atomic number but different mass number. The number of protons is determined by the atomic number (Z) .

Mass number (A) of any isotope of an element is total number of neutrons (N) and total number of protons (Z) . The numbers of neutrons are determined by difference between mass number and number of protons.

b)

Expert Solution
Check Mark

Explanation of Solution

Number of protons (Z) in the pair C614 and 715N are 6 and 7 respectively.

Number of electrons in the pair C614 and 715N are are 6 and 7 respectively.As to maintain neutrality, the numbers of electrons will be the same as number of protons (Z) .

The number of neutrons in C614 is calculated as follows:

  Number of neutron(N)= Mass Number(A)Number of protons(Z)=(146)=8

The number of neutrons in 715N is calculated as follows:

  Number of neutron(N)= Mass Number(A)Number of protons(Z)=(157)=8

Therefore, C614 and 715N pair has same N value.

c)

Interpretation Introduction

Interpretation:Whether the pair F919 and 918F have same number of protons, neutrons and electrons should be determined. Also, whether the pair F919 and 918F have same mass number (A) , numbers of neutrons (N) and numbers of protons (Z) should be determined.

Concept introduction:The nuclide symbol of an atom is represented as follows:

  XZA

Where,

  • Z is an atomic number.
  • A is the mass number.
  • Xis the isotope of any element.

The mass number of a nucleus is the total number of neutrons and protons. The number of protons and electrons are same in neutral species.

Isotopes are species that have same atomic number but different mass number. The number of protons is determined by the atomic number (Z) .

Mass number (A) of any isotope of an element is total number of neutrons (N) and total number of protons (Z) . The numbers of neutrons are determined by difference between mass number and number of protons.

c)

Expert Solution
Check Mark

Explanation of Solution

Number of protons (Z) in the pair F919 and 918F are 9 and 9 respectively.

Number of electrons in the pair F919 and 918F are 9and 9 respectively.As to maintain neutrality, the numbers of electrons will be the same as the number of protons (Z) .

The number of neutrons in F919 is calculated as follows:

  Number of neutron(N)= Mass Number(A)Number of protons(Z)=(199)=10

The number of neutrons in F919 is calculated as follows:

  Number of neutron(N)= Mass Number(A)Number of protons(Z)=189=9

Therefore, F919 and 918F pair has same Z value.

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Chapter 2 Solutions

Principles of General Chemistry

Ch. 2 - Prob. 2.11PCh. 2 - Prob. 2.12PCh. 2 - Prob. 2.13PCh. 2 - Prob. 2.14PCh. 2 - Prob. 2.15PCh. 2 - Prob. 2.16PCh. 2 - Show, with calculations, how the following data...Ch. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. 2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. 2.26PCh. 2 - Prob. 2.27PCh. 2 - Prob. 2.28PCh. 2 - Prob. 2.29PCh. 2 - Write the ZAX notation for each atomic depiction:Ch. 2 - Write the ZAX notation for each atomic depiction:Ch. 2 - Prob. 2.32PCh. 2 - Draw atomic depictions similar to those in Problem...Ch. 2 - Gallium has two naturally occurring isotopes,...Ch. 2 - Prob. 2.35PCh. 2 - Prob. 2.36PCh. 2 - Prob. 2.37PCh. 2 - Prob. 2.38PCh. 2 - Prob. 2.39PCh. 2 - Prob. 2.40PCh. 2 - Prob. 2.41PCh. 2 - Prob. 2.42PCh. 2 - Fill in the blanks: (a) The symbol and atomic...Ch. 2 - Prob. 2.44PCh. 2 - Prob. 2.45PCh. 2 - Prob. 2.46PCh. 2 - Given that the ions in LiF and in MgO are of...Ch. 2 - Prob. 2.48PCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - An ionic compound forms when calcium (Z=20) reacts...Ch. 2 - Prob. 2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Write a formula for each of the following...Ch. 2 - Prob. 2.62PCh. 2 - Give the name and formula of the compound formed...Ch. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. 2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. 2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. 2.71PCh. 2 - Prob. 2.72PCh. 2 - Prob. 2.73PCh. 2 - Prob. 2.74PCh. 2 - Prob. 2.75PCh. 2 - Prob. 2.76PCh. 2 - Prob. 2.77PCh. 2 - Give the formula, name, and molecular mass of the...Ch. 2 - Prob. 2.79PCh. 2 - Prob. 2.80PCh. 2 - Prob. 2.81PCh. 2 - Prob. 2.82PCh. 2 - Prob. 2.83PCh. 2 - Prob. 2.84PCh. 2 - Prob. 2.85PCh. 2 - Prob. 2.86PCh. 2 - Prob. 2.87PCh. 2 - Prob. 2.88PCh. 2 - Prob. 2.89PCh. 2 - Scenes A— depict various types of matter on the...Ch. 2 - The scvcn most abundant ions in seawater make up...Ch. 2 - Prob. 2.92PCh. 2 - Prob. 2.93PCh. 2 - Prob. 2.94PCh. 2 - Prob. 2.95PCh. 2 - Prob. 2.96PCh. 2 - Dinitrogen monoxide (N2O;nitrousoxide) is a...Ch. 2 - Prob. 2.98PCh. 2 - Prob. 2.99PCh. 2 - Prob. 2.100PCh. 2 - A rock is 5.0% by mass fayalite (Fe2SiO4)7.0% by...Ch. 2 - The two isotopes of potassium with significant...Ch. 2 - Prob. 2.103PCh. 2 - Prob. 2.104PCh. 2 - Prob. 2.105PCh. 2 - Prob. 2.106P
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