Chapter 19.4, Problem 36SP

Interpretation Introduction

Interpretation: The number of moles of sodium hydroxide required to neutralize 0.20 mol of nitric acid needs to be determined.

Concept Introduction: A reaction between an acid and a base is known as a neutralization reaction. Here, the acid reacts with the base to form salt and water. The general neutralization reaction is represented as follows:

  $\text{HA}+\text{BOH}\to \text{BA}+{\text{H}}_{\text{2}}\text{O}$

Here, HA is an acid, BOH is a base, and BA is salt.

Answer to Problem 36SP

The moles of sodium hydroxide are 0.2 mol.

Explanation of Solution

The number of moles of nitric acid is 0.20 mol.

Here, nitric acid is a strong acid, and sodium hydroxide is a strong base.

The reaction is represented as follows:

  ${\text{HNO}}_{\text{3}}+\text{NaOH}\to {\text{H}}_3{\text{O}}^{+}+{\text{NaNO}}_{\text{3}}$

Here, 1 mol of nitric acid reacts with 1 mol of NaOH thus, the number of moles of NaOH required to neutralize 0.2 mol of nitric acid will be 0.2 mol.