Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 19, Problem 105A

a)

Interpretation Introduction

Interpretation : The resulting solution is to be predicted when hydrochloric acid is titrated with sodium hydroxide.

Concept Introduction : Acids are substances that contain hydrogen and ionize to produce hydrogen ions H+ in an aqueous solution. Bases are substances that ionize in aqueous solutions to produce hydroxide ions OH .

a)

Expert Solution
Check Mark

Answer to Problem 105A

The resulting solution will be neutral in nature.

Explanation of Solution

Salt and water are created when bases and acids react.

A strong acid and strong base react completely to form a neutral solution. A neutralization reaction is a name for this kind of reaction.

The nature of the solution at the equivalent point depends upon the nature of acids and bases that reacts.

  HCl is titrated with NaOH , there is formation of salt NaCl and water.

  HCl+NaOHNaCl+H2O

Since the titration takes place between strong acid and strong base, the resulting solution will be neutral.

b)

Interpretation Introduction

Interpretation : The resulting solution is to be predicted when sodium hydroxide is titrated with hydrochloric acid.

Concept Introduction : Acids are substances that contain hydrogen and ionize to produce hydrogen ions H+ in an aqueous solution. Bases are substances that ionize in aqueous solutions to produce hydroxide ions OH .

b)

Expert Solution
Check Mark

Answer to Problem 105A

The resulting solution is neutral in nature.

Explanation of Solution

Salt and water are created when bases and acids react.

A strong acid and strong base react completely to form a neutral solution. A neutralization reaction is a name for this kind of reaction.

The nature of the solution at the equivalent point depends upon the nature of acids and bases that reacts.

  NaOH is titrated with HCl , there is formation of salt NaCl and water.

  HCl+NaOHNaCl+H2O

Since the titration takes place between strong acid and strong base, the resulting solution will be neutral.

c)

Interpretation Introduction

Interpretation : The resulting solution is to be predicted when acetic acid is titrated with sodium hydroxide.

Concept Introduction : Acids are substances that contain hydrogen and ionize to produce hydrogen ions H+ in an aqueous solution. Bases are substances that ionize in aqueous solutions to produce hydroxide ions OH .

c)

Expert Solution
Check Mark

Answer to Problem 105A

The resulting solution is basic in nature.

Explanation of Solution

Salt and water are created when bases and acids react.

A strong acid and strong base react completely to form a neutral solution. A neutralization reaction is a name for this kind of reaction.

The nature of the solution at the equivalent point depends upon the nature of acids and bases that reacts.

  CH3COOH is titrated with NaOH , there is formation of salt CH3COONa and water.

  CH3COOH+NaOHCH3COONa+H2O

Since the titration takes place between weak acid and strong base, the resulting solution will be basic.

d)

Interpretation Introduction

Interpretation : The resulting solution is to be predicted when ammonia is titrated with hydrochloric acid.

Concept Introduction : Acids are substances that contain hydrogen and ionize to produce hydrogen ions H+ in an aqueous solution. Bases are substances that ionize in aqueous solutions to produce hydroxide ions OH .

d)

Expert Solution
Check Mark

Answer to Problem 105A

The resulting solution is acidic in nature.

Explanation of Solution

Salt and water are created when bases and acids react.

A strong acid and strong base react completely to form a neutral solution. A neutralization reaction is a name for this kind of reaction.

The nature of the solution at the equivalent point depends upon the nature of acids and bases that reacts.

  NH3 is titrated with HCl , there is formation of salt NH4Cl .

  NH3+HClNH4Cl

Since the titration takes place between strong acid and weak base, the resulting solution will be acidic.

e)

Interpretation Introduction

Interpretation : The resulting solution is to be predicted when acetic acid is titrated with ammonia.

Concept Introduction : Acids are substances that contain hydrogen and ionize to produce hydrogen ions H+ in an aqueous solution. Bases are substances that ionize in aqueous solutions to produce hydroxide ions OH .

e)

Expert Solution
Check Mark

Answer to Problem 105A

The resulting solution is basic in nature.

Explanation of Solution

Salt and water are created when bases and acids react.

A strong acid and strong base react completely to form a neutral solution. A neutralization reaction is a name for this kind of reaction.

The nature of the solution at the equivalent point depends upon the nature of acids and bases that reacts.

  CH3COOH is titrated with NH3 , there is formation of acetate ion and ammonium ion.

  NH3+CH3COOHCH3COO+NH4+

Since the titration takes place between weak acid and weak base, the resulting solution will be basic.

Chapter 19 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 19.2 - Prob. 11SPCh. 19.2 - Prob. 12SPCh. 19.2 - Prob. 13SPCh. 19.2 - Prob. 14SPCh. 19.2 - Prob. 15SPCh. 19.2 - Prob. 16SPCh. 19.2 - Prob. 17SPCh. 19.2 - Prob. 18LCCh. 19.2 - Prob. 19LCCh. 19.2 - Prob. 20LCCh. 19.2 - Prob. 21LCCh. 19.2 - Prob. 22LCCh. 19.2 - Prob. 23LCCh. 19.2 - Prob. 24LCCh. 19.3 - Prob. 25SPCh. 19.3 - Prob. 26SPCh. 19.3 - Prob. 27LCCh. 19.3 - Prob. 28LCCh. 19.3 - Prob. 29LCCh. 19.3 - Prob. 30LCCh. 19.3 - Prob. 31LCCh. 19.3 - Prob. 32LCCh. 19.3 - Prob. 33LCCh. 19.3 - Prob. 34LCCh. 19.4 - Prob. 35SPCh. 19.4 - Prob. 36SPCh. 19.4 - Prob. 37SPCh. 19.4 - Prob. 38SPCh. 19.4 - Prob. 39LCCh. 19.4 - Prob. 40LCCh. 19.4 - Prob. 41LCCh. 19.4 - Prob. 42LCCh. 19.4 - Prob. 43LCCh. 19.5 - Prob. 44SPCh. 19.5 - Prob. 45SPCh. 19.5 - Prob. 46LCCh. 19.5 - Prob. 47LCCh. 19.5 - Prob. 48LCCh. 19.5 - Prob. 49LCCh. 19.5 - Prob. 50LCCh. 19.5 - Prob. 51LCCh. 19 - Prob. 52ACh. 19 - Prob. 53ACh. 19 - Prob. 54ACh. 19 - Prob. 55ACh. 19 - Prob. 56ACh. 19 - Prob. 57ACh. 19 - Prob. 58ACh. 19 - Prob. 59ACh. 19 - Prob. 60ACh. 19 - Prob. 61ACh. 19 - Prob. 62ACh. 19 - Prob. 63ACh. 19 - Prob. 64ACh. 19 - Prob. 65ACh. 19 - Prob. 66ACh. 19 - Prob. 67ACh. 19 - Prob. 68ACh. 19 - Prob. 69ACh. 19 - Prob. 70ACh. 19 - Prob. 71ACh. 19 - Prob. 72ACh. 19 - Prob. 73ACh. 19 - Prob. 74ACh. 19 - Prob. 75ACh. 19 - Prob. 76ACh. 19 - Prob. 77ACh. 19 - Prob. 78ACh. 19 - Prob. 79ACh. 19 - Prob. 80ACh. 19 - Prob. 81ACh. 19 - Prob. 82ACh. 19 - Prob. 83ACh. 19 - Prob. 84ACh. 19 - Prob. 85ACh. 19 - Prob. 86ACh. 19 - Prob. 87ACh. 19 - Prob. 88ACh. 19 - Prob. 89ACh. 19 - Prob. 90ACh. 19 - Prob. 91ACh. 19 - Prob. 92ACh. 19 - Prob. 93ACh. 19 - Prob. 94ACh. 19 - Prob. 95ACh. 19 - Prob. 96ACh. 19 - Prob. 97ACh. 19 - Prob. 98ACh. 19 - Prob. 99ACh. 19 - Prob. 100ACh. 19 - Prob. 101ACh. 19 - Prob. 102ACh. 19 - Prob. 103ACh. 19 - Prob. 104ACh. 19 - Prob. 105ACh. 19 - Prob. 106ACh. 19 - Prob. 107ACh. 19 - Prob. 108ACh. 19 - Prob. 109ACh. 19 - Prob. 110ACh. 19 - Prob. 111ACh. 19 - Prob. 112ACh. 19 - Prob. 113ACh. 19 - Prob. 114ACh. 19 - Prob. 117ACh. 19 - Prob. 118ACh. 19 - Prob. 119ACh. 19 - Prob. 120ACh. 19 - Prob. 121ACh. 19 - Prob. 122ACh. 19 - Prob. 123ACh. 19 - Prob. 124ACh. 19 - Prob. 125ACh. 19 - Prob. 126ACh. 19 - Prob. 127ACh. 19 - Prob. 128ACh. 19 - Prob. 129ACh. 19 - Prob. 130ACh. 19 - Prob. 131ACh. 19 - Prob. 132ACh. 19 - Prob. 133ACh. 19 - Prob. 134ACh. 19 - Prob. 135ACh. 19 - Prob. 136ACh. 19 - Prob. 137ACh. 19 - Prob. 138ACh. 19 - Prob. 139ACh. 19 - Prob. 1STPCh. 19 - Prob. 2STPCh. 19 - Prob. 3STPCh. 19 - Prob. 4STPCh. 19 - Prob. 5STPCh. 19 - Prob. 6STPCh. 19 - Prob. 7STPCh. 19 - Prob. 8STPCh. 19 - Prob. 9STPCh. 19 - Prob. 10STPCh. 19 - Prob. 11STPCh. 19 - Prob. 12STPCh. 19 - Prob. 13STP
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