Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 19, Problem 62A
Interpretation Introduction

Interpretation : The pH of pure water at room temperature is equal to 7.0 is to be explained.

Concept Introduction : The negative logarithm of the concentration of hydrogen ions is the pH of a solution. The values from 0 to 14 are the range of a pH scale.

Expert Solution & Answer
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Answer to Problem 62A

The pH of pure water at room temperature is equal to 7.0 due to the neutral nature of the solution and the concentration of hydrogen ion is 1.0×107M .

Explanation of Solution

The formula to calculate pH is given as

  pH=log[H+]

Here, H+ denotes the concentration of hydrogen ion.

The concentration of hydrogen ions in pure water at room temperature is 1.0×107M .

To calculate the pH, substitute the values in the above formula:

  pH=log[H+]=log1.0×107M=7.00

A pH of 7.0 indicates a neutral solution.

Chapter 19 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 19.2 - Prob. 11SPCh. 19.2 - Prob. 12SPCh. 19.2 - Prob. 13SPCh. 19.2 - Prob. 14SPCh. 19.2 - Prob. 15SPCh. 19.2 - Prob. 16SPCh. 19.2 - Prob. 17SPCh. 19.2 - Prob. 18LCCh. 19.2 - Prob. 19LCCh. 19.2 - Prob. 20LCCh. 19.2 - Prob. 21LCCh. 19.2 - Prob. 22LCCh. 19.2 - Prob. 23LCCh. 19.2 - Prob. 24LCCh. 19.3 - Prob. 25SPCh. 19.3 - Prob. 26SPCh. 19.3 - Prob. 27LCCh. 19.3 - Prob. 28LCCh. 19.3 - Prob. 29LCCh. 19.3 - Prob. 30LCCh. 19.3 - Prob. 31LCCh. 19.3 - Prob. 32LCCh. 19.3 - Prob. 33LCCh. 19.3 - Prob. 34LCCh. 19.4 - Prob. 35SPCh. 19.4 - Prob. 36SPCh. 19.4 - Prob. 37SPCh. 19.4 - Prob. 38SPCh. 19.4 - Prob. 39LCCh. 19.4 - Prob. 40LCCh. 19.4 - Prob. 41LCCh. 19.4 - Prob. 42LCCh. 19.4 - Prob. 43LCCh. 19.5 - Prob. 44SPCh. 19.5 - Prob. 45SPCh. 19.5 - Prob. 46LCCh. 19.5 - Prob. 47LCCh. 19.5 - Prob. 48LCCh. 19.5 - Prob. 49LCCh. 19.5 - Prob. 50LCCh. 19.5 - Prob. 51LCCh. 19 - Prob. 52ACh. 19 - Prob. 53ACh. 19 - Prob. 54ACh. 19 - Prob. 55ACh. 19 - Prob. 56ACh. 19 - Prob. 57ACh. 19 - Prob. 58ACh. 19 - Prob. 59ACh. 19 - Prob. 60ACh. 19 - Prob. 61ACh. 19 - Prob. 62ACh. 19 - Prob. 63ACh. 19 - Prob. 64ACh. 19 - Prob. 65ACh. 19 - Prob. 66ACh. 19 - Prob. 67ACh. 19 - Prob. 68ACh. 19 - Prob. 69ACh. 19 - Prob. 70ACh. 19 - Prob. 71ACh. 19 - Prob. 72ACh. 19 - Prob. 73ACh. 19 - Prob. 74ACh. 19 - Prob. 75ACh. 19 - Prob. 76ACh. 19 - Prob. 77ACh. 19 - Prob. 78ACh. 19 - Prob. 79ACh. 19 - Prob. 80ACh. 19 - Prob. 81ACh. 19 - Prob. 82ACh. 19 - Prob. 83ACh. 19 - Prob. 84ACh. 19 - Prob. 85ACh. 19 - Prob. 86ACh. 19 - Prob. 87ACh. 19 - Prob. 88ACh. 19 - Prob. 89ACh. 19 - Prob. 90ACh. 19 - Prob. 91ACh. 19 - Prob. 92ACh. 19 - Prob. 93ACh. 19 - Prob. 94ACh. 19 - Prob. 95ACh. 19 - Prob. 96ACh. 19 - Prob. 97ACh. 19 - Prob. 98ACh. 19 - Prob. 99ACh. 19 - Prob. 100ACh. 19 - Prob. 101ACh. 19 - Prob. 102ACh. 19 - Prob. 103ACh. 19 - Prob. 104ACh. 19 - Prob. 105ACh. 19 - Prob. 106ACh. 19 - Prob. 107ACh. 19 - Prob. 108ACh. 19 - Prob. 109ACh. 19 - Prob. 110ACh. 19 - Prob. 111ACh. 19 - Prob. 112ACh. 19 - Prob. 113ACh. 19 - Prob. 114ACh. 19 - Prob. 117ACh. 19 - Prob. 118ACh. 19 - Prob. 119ACh. 19 - Prob. 120ACh. 19 - Prob. 121ACh. 19 - Prob. 122ACh. 19 - Prob. 123ACh. 19 - Prob. 124ACh. 19 - Prob. 125ACh. 19 - Prob. 126ACh. 19 - Prob. 127ACh. 19 - Prob. 128ACh. 19 - Prob. 129ACh. 19 - Prob. 130ACh. 19 - Prob. 131ACh. 19 - Prob. 132ACh. 19 - Prob. 133ACh. 19 - Prob. 134ACh. 19 - Prob. 135ACh. 19 - Prob. 136ACh. 19 - Prob. 137ACh. 19 - Prob. 138ACh. 19 - Prob. 139ACh. 19 - Prob. 1STPCh. 19 - Prob. 2STPCh. 19 - Prob. 3STPCh. 19 - Prob. 4STPCh. 19 - Prob. 5STPCh. 19 - Prob. 6STPCh. 19 - Prob. 7STPCh. 19 - Prob. 8STPCh. 19 - Prob. 9STPCh. 19 - Prob. 10STPCh. 19 - Prob. 11STPCh. 19 - Prob. 12STPCh. 19 - Prob. 13STP
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