Campbell Biology
12th Edition
ISBN: 9780135188743
Author: Urry
Publisher: PEARSON
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Chapter 15.4, Problem 2CC
Summary Introduction
To determine: In which parent the non-disjunction of chromosome 9 has occurred based on the information that the father is of blood type AB and mother is of blood type O, and their child is of the blood type A with trisomy in chromosome 9
Concept introduction:
The term non-disjunction means that the chromosomes that appeared together in the cell did not separate during the gamete formation and were carried together into the gamete formed. The non-disjunction of the paired chromosome leads to the chromosomal aberration called trisomy in the offspring.
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Chapter 15 Solutions
Campbell Biology
Ch. 15.1 - MAKE CONNECTIONS Review the description of...Ch. 15.1 - WHAT IF? Propose a possible reason that the first...Ch. 15.1 - Which one of Mendel's laws describes the...Ch. 15.2 - A white-eyed female Drosophila is mated with a...Ch. 15.2 - Neither Tim nor Rhoda has Duchenne muscular...Ch. 15.2 - MAKE CONNECTIONS Consider what you learned about...Ch. 15.3 - When two genes are located on the same chromosome,...Ch. 15.3 - VISUAL SKILLS For each type of offspring of the...Ch. 15.3 - Prob. 3CCCh. 15.4 - Prob. 1CC
Ch. 15.4 - Prob. 2CCCh. 15.4 - Prob. 3CCCh. 15.5 - Gene dosagethe number of copies of a gene that are...Ch. 15.5 - Reciprocal crosses between two primrose varieties,...Ch. 15.5 - WHAT IF? Mitochondrial genes are critical to the...Ch. 15 - What characteristic of the sex chromosomes allowed...Ch. 15 - Why are males affected by X-Iinked disorders much...Ch. 15 - Why are specific alleles of two distant genes more...Ch. 15 - Prob. 15.4CRCh. 15 - Explain how genomic imprinting and inheritance of...Ch. 15 - A man with hemophilia (a recessive, sex-linked...Ch. 15 - Pseudohypertrophic muscular dystrophy is an...Ch. 15 - Prob. 3TYUCh. 15 - A planet is inhabited by creatures that reproduce...Ch. 15 - Prob. 5TYUCh. 15 - A wild-type fruit fly (heterozygous for gray body...Ch. 15 - Assume that genes, A and B are on the same...Ch. 15 - Two genes of a flower, one Controlling blue (B)...Ch. 15 - Prob. 9TYUCh. 15 - Banana plants, which are triploid, are seedless...Ch. 15 - Prob. 11TYUCh. 15 - SCIENTIFIC INQUIRY DRAW IT Assume you are mapping...Ch. 15 - WRITE ABOUT A THEME: INFORMATION The continuity of...Ch. 15 - SYNTHESIZE YOUR KNOWLEDGE Butter flies have an X-Y...
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- Human females have two X chromosomes XX; males have one X and one Y chromosome XY. a. With respect to X-linked alleles, how many different types of gametes can a male produce? b. A female homozygous for an X-linked allele can produce how many types of gametes with respect to that allele? c. A female heterozygous for an X-linked allele can produce how many types of gametes with respect to that allele?arrow_forwardHuman females have two X chromosomes (XX); males have one X and one Y chromosome (XY). a. With respect to X-linked alleles, how many different types of gametes can a male produce? b. If a female is homozygous for an X-linked allele, how many types of gametes can she produce with respect to that allele? c. If a female is heterozygous for an X-linked allele, how many types of gametes can she produce with respect to that allele?arrow_forwardDiscuss Concepts One of the human chromosome pairs carries a gene that influences eye color. In an individual human, one chromosome of this pair has an allele of this gene that contributes to the formation of blue eyes. The other chromosome of the pair has an allele that contributes to brown eye color (other genes also influence eye color in humans). After meiosis in the cells of this individual, what fraction of the nuclei will carry the allele that contributes to blue eyes? To brown eyes?arrow_forward
- In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene at a different locus is epistatic to the gene for fur color. When present in its dominant W form (WW or Ww), this gene blocks the formation of fur color and all the offspring are white; ww individuals develop normal fur color. What fur colors, and in what proportions, would you expect from the cross AaWw Aa Ww?arrow_forwardSET 2: In corn, the following allelic pairs have been identified in chromosome 3: +/b plant color booster vs. non-booster +/lg with ligule vs. without ligule +/v green plant vs. virescent A test cross between triple recessive plants and plants heterozygous for the three pairs gave the following progeny: + v lg 305 b + lg b v lg + + lg b v + 148 58 + + + 62 + y + 152 b + + 275 Total 1000 Calculate the parental and recombinant frequencies, the map distances between genes, and the coefficient of coincidence. Illustrate the gene map or sequence.arrow_forwardEC1. In drosophila the cw (curly wings) gene and eb (ebony body) genes are found on the same chromosome 20 map units apart. A cross was made between an ebony bodied parental strain and a curly winged parental strain and the F1’s were test crossed. a) What are the genotypes of the parental strains? b) What are the genotypes of the F1’s? c) What is the genotype of the tester strain? d) What progeny phenotypes and genotypes do you expect, and in what proportions? For phenotypes use the mutant phenotype for any that the flies have, and wild-type if they have none. EC2. Here is a tetrad produced by mating a H Y strain to an h y strain. a) What is the tetrad type? b) What has recombined with what? EC3. In corn, a dihybrid for the recessive genes a and b is test-crossed. The distribution of the phenotypes is as follows: A B 122A b 118a B 81a b 79 a) Do the genes appear to be sorting independently? Look at map units here. b) Test your hypothesis with a chi-squared test.arrow_forward
- . Chromosome 3 of corn carries three loci (b for plant-color booster, v for virescent, and lg for liguleless). A testcross of triple recessives with F1 plants heterozygous forthe three genes yields progeny having the followinggenotypes: 305 + v lg, 275 b + +, 128 b + lg, 112 + v +,74 + + lg, 66 b v +, 22 + + +, and 18 b v lg. Give the genesequence on the chromosome, the map distances between genes, and the coefficient of coincidence.arrow_forwardSET 2: In corn, the following allelic pairs have been identified in chromosome 3: +/b plant color booster vs. non-booster +/lg with ligule vs. without ligule +/v green plant vs. virescent A test cross between triple recessive plants and plants heterozygous for the three pairs gave the following progeny: + v lg b + lg b v lg + + lg 305 148 58 bv + + + + 62 + v + b + + 152 275 1000 Total Calculate the parental and recombinant frequencies, the map distances between genes, and the coefficient of coincidence. Illustrate the gene map or sequence.arrow_forward5) Cystic fibrosis is caused by a gene on chromosome 7 and results in the build-up of mucus in the lungs. Two parents who do not have cystic fibrosis have three children with the disease. What is the probability that their fourth child will also have cystic fibrosis? Explain.arrow_forward
- n corn, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of the corn plants (i.e the tassel) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male fertile corn plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male sterile lines sing the cardboard chips, simulate the crosses indicated below. Give the genotypes and phenotypes of the offsprings in each cross, and properly label the nucleus and the cytoplasm of each individual in the cross Legend male sterile cytoplasm Male fertile cytoplasm FF nucleus Ff nucleus ff nucleus A. Male sterile female x FF male Explain the phenotype of the offspring B. Male sterile female x Ff male Explain the phenotype of the offspringarrow_forwardSET 2: In corn, the following allelic pairs have been identified in chromosome 3: +/b > plant color booster vs. non-booster +lg → with ligule vs. without ligule +/v > green plant vs. virescent A test cross between triple recessive plants and plants heterozygous for the three pairs gave the following progeny: + v lg b + lg b v lg 305 148 58 + + lg b v + + + + 62 + v + 152 b + + 275 Total 1000 Calculate the parental and recombinant frequencies, the map distances between genes, and the coefficient of coincidence. Illustrate the gene map or sequence.arrow_forwardAn individual comes into your genetics clinic to be tested for any anomalies. When looking at their karyotype, you notice they have three X chromosomes and a Y chromosome. What information would you be able to relay to this individual? O They have Turner syndrome, are genetically female, and have two Barr bodies per cell. O They have Klinefelter syndrome, are genetically female, and have two Barr bodies per cell. O They have Klinefelter syndrome, are genetically male, and have two Barr bodies per cell. O They have Klinefelter syndrome, are genetically male, and have three Barr bodies per cell. O They have Turner syndrome, are genetically male, and have three Barr bodies per cell.arrow_forward
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