Biology
5th Edition
ISBN: 9781260487947
Author: BROOKER
Publisher: MCG
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Chapter 15.1, Problem 2CC
Summary Introduction
To describe: Whether the child can able to transmit the trait of white hair streak to the future generation.
Introduction: Somatic cells are those cells which are prominently found in the body and are different from the germ or sex cells. The chances of mutation in somatic cells are commonly seen.
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Gene Interaction and Epistasis
Hair color is due to the presence of melanin. There are two types of melanin produced by melanocytes. One is eumelanin, which is responsible for black (homozygous), brown (heterozygous), and blond (recessive) hair colors. The other is pheomelanin, which is responsible for red hair color. During melanin synthesis, MCR1gene converts pheomelanin to eumelanin. However, a variant of the MCR1 gene (MCR1variant), prevents this conversion.
A cross between a blond-haired mother and a red-haired father produced 100% brown-haired children. When they came of age, one child married a double heterozygote, and both were blessed with 7 children; 2 with black hair, 2 with brown hair, 1 with blond hair, and 2 with red hair.
Using the 7-step method, determine the genotypes of the P1, the F1, and the F2s. BOX your answers (if handwritten) or HIGHLIGHT your answers (if encoded).
STEP 1: ________________________________________________________
STEP 2:…
Exercise Ill:
For this lab exercise, you will evaluate a human pedigree for a particular disease, Huntington disease.
Huntington disease is a progressive neurodegenerative disorder that is inherited in an autosomal
dominant pattern. The disease presents around the age of 40, although there are juvenile onset
forms of the disease. Suppose that there is a SNP closely linked to the Huntington gene, so close that
there is little crossing over between the SNP and the Huntington gene.
Consider the following family:
Velma's father, now deceased, had Huntington Disease, but neither of his parents had the disease;
therefore, it was a new mutation that caused his disease. Velma's mother does not have the disease.
Before his death, Velma's father was genotyped for the SNP marker that is linked to the Huntington
gene, and it was determined that he has alleles A1 and A2. Velma's mother was also genotyped and
has alleles A1 and A3. Velma has one brother (age 45) who has Huntington Disease, and…
Deletion mapping:
In your diploid model organism, one copy of the chromosome has all normal, dominant alleles of these genes. It is P
Q R STU V (not necessarily in that order). But the other copy of the chromosome has all recessive alleles, p q r
stu v. You find various deletions in which chunks of the "dominant chromosome" are missing, and so there are
recessive phenotypes as shown:
Phenotype -- recessive for genes...
T, Q, and U
R, V, and S
T and U
S and V
Q, P, and R
R and S
First deletion
Second deletion
Third deletion
Fourth deletion
Fifth deletion
Sixth deletion
Seventh deletion
T and Q
Figure out the order of the genes. Show some kind of work.
Chapter 15 Solutions
Biology
Ch. 15.1 - Consequences of Mutations Concept Check: Based on...Ch. 15.1 - Prob. 2CCCh. 15.2 - Prob. 1EQCh. 15.2 - Prob. 2EQCh. 15.2 - Prob. 3EQCh. 15.2 - Prob. 1CCCh. 15.3 - DNA Repair Concept Check: Which components of the...Ch. 15.3 - Why is this person so sensitive to sunlight?...Ch. 15.4 - Prob. 1CCCh. 15.4 - Prob. 2CS
Ch. 15.4 - Prob. 2CCCh. 15.4 - Prob. 3CCCh. 15.4 - Prob. 4CCCh. 15 - Prob. 1TYCh. 15 - Prob. 2TYCh. 15 - Prob. 3TYCh. 15 - Prob. 4TYCh. 15 - Prob. 5TYCh. 15 - The Ames test a. provides a way to determine if...Ch. 15 - Xeroderma pigmentosum a. is a genetic disorder...Ch. 15 - Prob. 8TYCh. 15 - Prob. 9TYCh. 15 - Prob. 10TYCh. 15 - Prob. 1CQCh. 15 - Prob. 2CQCh. 15 - Prob. 3CQCh. 15 - Prob. 1COQCh. 15 - Distinguish between spontaneous and induced...
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