Chapter 14.4, Problem 41LC

Interpretation Introduction

Interpretation: To determine the effect of molar mass on rates of diffusion and effusion.

Concept Introduction: The process of diffusion would be the transfer of a single material from a region of high concentration to one of low concentration. This indicates that molecules or particles disperse across the medium.

Answer to Problem 41LC

According to Graham's law, a gas's rate of diffusion and effusion would be inversely related to its molar mass squared.

Explanation of Solution

Graham's Law states that at constant pressure as well as temperature, molecules or atoms having a lower molecular mass would effuse more quickly than those with a larger molecular mass. It can be expressed as:

  $\text{Rate=}\sqrt{\frac{1}{\text{Molar}\text{mass}}}$

Hence, by increasing the molar mass rate of diffusion will be decreased.