Organic Chemistry - Standalone book
10th Edition
ISBN: 9780073511214
Author: Francis A Carey Dr., Robert M. Giuliano
Publisher: McGraw-Hill Education
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Textbook Question
Chapter 14, Problem 42P
Compounds A and B are isomers of molecular formula
NMR spectra presented in Figure
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Compound 1 has molecular formula C7H16. It shows three signals in the 1H-NMR spectrum, one at 0.85 ppm, one at 1.02 ppm, and one at 1.62 ppm. The relative integrals of these three signals are 6, 1, and 1, respectively.
Compound 2 has molecular formula C7H14. It shows three signals in the 1H-NMR spectrum, one at 0.98 ppm, one at 1.36 ppm, and one at 1.55 ppm. The relative integrals of these three signals are 3, 2, and 2, respectively.
Propose structures for compounds 1 and 2, explaining how you reach your conclusion.
1Compound 1 has molecular formula C7H16. It shows three signals in the 1H-NMR spectrum, one at 0.85 ppm, one at 1.02 ppm, and one at 1.62 ppm. The relative integrals of these three signals are 6, 1, and 1, respectively.
Compound 2 has molecular formula C7H14. It shows three signals in the 1H-NMR spectrum, one at 0.98 ppm, one at 1.36 ppm, and one at 1.55 ppm. The relative integrals of these three signals are 3, 2, and 2, respectively.
Propose structures for compounds 1 and 2, explaining how you reach your conclusion.
Compound 2 has molecular formula C6H12. It shows three signals in the 1H-NMR spectrum, one at 0.96 ppm, one at 2.03 ppm, and one at 5.33 ppm. The relative integrals of these three signals are 3, 2, and 1, respectively.
Provide structure for compound 2, explain how you reached your conclusion.
Chapter 14 Solutions
Organic Chemistry - Standalone book
Ch. 14.3 - Prob. 1PCh. 14.3 - Prob. 2PCh. 14.4 - The 1H NMR signal for bromoform (CHBr3) appears at...Ch. 14.5 - identify the most shielded and least shielded...Ch. 14.5 - (a) Assign the chemical shifts 1.6, 2.2, and 4.8...Ch. 14.5 - Assign the chemical shifts 1.1, 1.7, 2.0, and 2.3...Ch. 14.5 - Assign the chemical shifts 1.6, 4.0, 7.5, 8.2, and...Ch. 14.6 - The 300-MHz 1H NMR spectrum of 1,4-dimethylbenzene...Ch. 14.6 - Prob. 9PCh. 14.6 - How many signals would you expect to find in the...
Ch. 14.7 - Describe the appearance of the 1H NMR spectrum of...Ch. 14.8 - Describe the appearance of the 1H NMR spectrum of...Ch. 14.11 - Prob. 13PCh. 14.11 - Prob. 14PCh. 14.12 - Hydrogen bonding between the oxygen of dimethyl...Ch. 14.14 - Prob. 16PCh. 14.15 - The 13C NMR spectrum of 1-bromo-3-chloropropane...Ch. 14.15 - Consider carbons x, y, and z in p-methylanisole....Ch. 14.15 - Prob. 19PCh. 14.16 - To which of the compounds of Problem 14.16 does...Ch. 14.18 - DEPT spectra for a compound with the formula...Ch. 14.20 - Vibrational frequencies are sensitive to isotopic...Ch. 14.21 - Prob. 23PCh. 14.22 - Prob. 24PCh. 14.23 - Prob. 25PCh. 14.23 - Which one of the C5H8 isomers shown has its max at...Ch. 14.24 - Knowing what to look for with respect to isotopic...Ch. 14.24 - The base peak appears at m/z105 for one of the...Ch. 14.24 - Mass spectra of 1-bromo-4-propylbenzene and...Ch. 14.25 - Prob. 30PCh. 14 - Each of the following compounds is characterized...Ch. 14 - Deduce the structure of each of the following...Ch. 14 - From among the isomeric compounds of molecular...Ch. 14 - The H1NMR spectrum of fluorene has signals at 3.8...Ch. 14 - Prob. 35PCh. 14 - H1NMR spectra of four isomeric alcohols with...Ch. 14 - Prob. 37PCh. 14 - We noted in Section 14.13 that an NMR spectrum is...Ch. 14 - Identify each of the C4H10O isomers on the basis...Ch. 14 - A compound (C3H7ClO2) exhibited three peaks in its...Ch. 14 - Label nonequivalent carbons in the following...Ch. 14 - Compounds A and B are isomers of molecular formula...Ch. 14 - C13 NMR spectra for four isomeric alkyl bromides...Ch. 14 - Prob. 44PCh. 14 - Prob. 45PCh. 14 - Identify the C3H5Br isomers on the basis of the...Ch. 14 - Prob. 47PCh. 14 - A compound (C8H10O) has the IR and H1NMR spectra...Ch. 14 - Deduce the structure of a compound having the...Ch. 14 - Figure 14.53 presents IR, H1NMR, C13NMR and mass...Ch. 14 - H1NMR, C13NMR, IR, and mass spectra are shown for...Ch. 14 - 1H NMR and IR spectra for a compound with the...Ch. 14 - FriedelCraftsalkylation of benzene with...Ch. 14 - Prob. 54DSPCh. 14 - Prob. 55DSPCh. 14 - Prob. 56DSPCh. 14 - Prob. 57DSPCh. 14 - Prob. 58DSP
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- The H1H1 NMR spectrum shown corresponds to an unknown compound with the molecular formula C6H10C6H10. There are no strong IR bands between 2100 and 2300 or 3250 and 3350 cm−1. Deduce and draw the structure of the molecule that corresponds to the spectrum.arrow_forwardThe following NMR spectra were obtained from a compound with the molecular formula C4H6O. Use this information to predict its structure.arrow_forward16-17 Propylamine (bp 48°C), ethylmethylamine (bp 37°C), and trimethylamine (bp 3°C) are constitutional isomers with the molecular formula C3HgN. Account for the fact that trimethylamine has the lowest boiling point of the three and propylamine has the highest.arrow_forward
- Camphor, a saturated monoketone from the Asian camphor tree, is used among other things as a moth repellent and as a constituent of embalming fluid. If camphor has M+=152.1201 by high-resolution mass spectrometry, what is its molecular formula? How many rings does camphor have?arrow_forwardHow would you use NMR (either 13C or 1H) to distinguish between the following pairs of isomers?arrow_forwardA ¹H NMR spectrum is shown for a molecule with the molecular formula of C9H10O2. Draw the structure that best fits this data. 1H 11 10 9 8 SH 7 4 214 21 1 pom Qarrow_forward
- Compound 1 has molecular formula C7H15Cl. It shows two signals in the 1H-NMR spectrum, one at 1.08 ppm and one at 1.59 ppm. The relative integrals of these two signals are 3 and 2, respectively. Propose structures for compound 1, explaining how you reach your conclusion.arrow_forwardFigure 1.9: The structure of this acid (C5H10O2) is: 4 singlet triplet 3 doublet 3 n=8 Figure 3: ¹H-NMR of unknown ether C (molecular formula C5H12O). Figure 1.10: The structure of this ether (C5H10O2) is: Figure 1.11: The structure of this compound (C7H16) is: мий doublet n=8 ми ми doublet triplet 1arrow_forwardThe two isomeric carboxylic acids that give the following NMR spectra both have the formula C3H5C1O2. Draw their structures.arrow_forward
- Compound 1 has molecular formula C6H12. It shows three signals in the 1H-NMR spectrum, one at 0.96 ppm, one at 2.03 ppm, and one at 5.33 ppm. The relative integrals of these three signals are 3, 2, and 1, respectively. Compound 2 has molecular formula C7H15Br. It shows two signals in the 1H-NMR spectrum, one at 1.08 ppm and one at 1.59 ppm. The relative integrals of these two signals are 3 and 2, respectively. Propose structures for compounds 1 and 2, explaining how you reach your conclusion.arrow_forwardCompound B has molecular formula C9H12. It shows five signals in the 1H-NMR spectrum - a doublet of integral 6 at 1.22 ppm, a septet of integral 1 at 2.86 ppm, a singlet of integral 1 at 5.34 ppm, a doublet of integral 2 at 6.70 ppm, and a doublet of integral 2 at 7.03 ppm. The 13C-NMR spectrum of B shows six unique signals (23.9, 34.0, 115.7, 128.7, 148.9, and 157.4). Identify B and explain your reasoning.arrow_forwardSolve the structure of this compound by looking at the 1H, 13C NMR data provided. You must fill all of the parts to this question in the given spaces. Molecular formula: C6H14N2O2arrow_forward
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