Organic Chemistry (6th Edition)
Organic Chemistry (6th Edition)
6th Edition
ISBN: 9781260119107
Author: Janice Gorzynski Smith
Publisher: McGraw Hill Education
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Chapter 13.1, Problem 2P
Interpretation Introduction

(a)

Interpretation: The most stable radical that can result from cleavage of CH bond in the given molecule is to be drawn.

Concept introduction: A free radical is an atom or ion with unpaired electrons. They are reactive intermediates formed by the homolysis of covalent bond. Free radicals are classified as 1°, 2° or 3° depending upon the number of alkyl groups attached to it. As number of alkyl substitutents increases, the stability of radical also increases. This is due to the fact alkyl substituents donate their electrons to electron deficient radicals.

Interpretation Introduction

(b)

Interpretation: The most stable radical that can result from cleavage of CH bond in the given molecule is to be drawn.

Concept introduction: A free radical is an atom or ion with unpaired electrons. They are reactive intermediates formed by the homolysis of covalent bond. Free radicals are classified as 1°, 2° or 3° depending upon the number of alkyl groups attached to it. The number of alkyl substitutents increases, the stability of radical increases. This is due to the fact alkyl substituents donate their electrons to electron deficient radicals.

Interpretation Introduction

(c)

Interpretation: The most stable radical that can result from cleavage of CH bond in the given molecule is to be drawn.

Concept introduction: A free radical is an atom or ion with unpaired electrons. They are reactive intermediates formed by the homolysis of covalent bond. Free radicals are classified as 1°, 2° or 3° depending upon the number of alkyl groups attached to it. The number of alkyl substitutents increases, the stability of radical increases. This is due to the fact alkyl substituents donate their electrons to electron deficient radicals.

Interpretation Introduction

(d)

Interpretation: The most stable radical that can result from cleavage of CH bond in the given molecule is to be drawn.

Concept introduction: A free radical is an atom or ion with unpaired electrons. They are reactive intermediates formed by the homolysis of covalent bond. Free radicals are classified as 1°, 2° or 3° depending upon the number of alkyl groups attached to it. The number of alkyl substitutents increases, the stability of radical increases. This is due to the fact alkyl substituents donate their electrons to electron deficient radicals.

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Homolysis of the indicated C–H bond in propene forms a resonancestabilized radical. a.Draw the two possible resonance structures for this radical. b.Use half-headed curved arrows to illustrate how one resonance structure can be converted to the other. c. Draw a structure for the resonance hybrid.
1. What is the bond angle in carbon tetrachloride? 2. What is the product of the reaction of pent-2-ene with Cl2?  3.Which statement is correct? * A. The bond length increases when the difference between the electronegativity of the atoms is higher B. The bond length increases when the number when there is an increase in pi bonds. C. Increasing the bond polarity increases the bond length. D. Sp2 has shorter bond length that sp.   4. How many moles of O2 gas is theoretically needed for 1 mole of hexane?   5. What is the MOST LIKELY product of the reaction of pent-1-ene with HCL?   6. Which one creates a sigma bond? * A. 2 pz atomic orbitals B. 2 py atomic orbitals C. 2 px atomic orbitals D. none of these   7.How many hydrogen atoms are there in trans-1-bromo-2-methylcyclohexane?   8.
Examine the reactant and product for each reaction. Label each transformation as an addition, elimination, or substitution. Br А. Br ОН elimination addition С. substitution D. B.
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