General Chemistry: Principles and Modern Applications (11th Edition)
11th Edition
ISBN: 9780132931281
Author: Ralph H. Petrucci, F. Geoffrey Herring, Jeffry D. Madura, Carey Bissonnette
Publisher: PEARSON
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Chapter 13, Problem 93IAE
Interpretation Introduction
Interpretation:
The temperature that dissociates
Concept introduction:
The Gibbs energy, G, for a system is defined by the equation,
The Gibbs energy change,
Relationship of to the Equilibrium Constant K represents by following equation,
With the use of the above equation twice for two different temperatures, following equation can be derived,
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Consider the chemical equation and equilibrium constant for the formation of ammonia gas; N2(g) + 3 H2(g) ↔2 NH3(g), K = 3.7 x 108 at 25 °CDetermine the equilibrium constant at 25 °C for the reaction NH3(g) ↔ 0.5 N2(g) + 1.5 H2(g).
At 298 K the reaction N(g) + 3 H(g)<-> 2 NH(g) has K = 4.2 x 108. What is the value of Kc for the reaction 1/3 N(g) + H(g)<-> 2/3 NH(g)?
Consider the following reactions and their respective equilibrium constants:
NO(g) + ½Br₂(g) = NOBr(g); K = 5.3
2NO(g) = N₂(g) + O₂(g); K = 2.1 × 10³⁰
Use these reactions and their equilibrium constants to predict the equilibrium constant for the following reaction:
N₂(g) + O2(g) + Br₂(g) = 2NOBr(g)
Express your answer using two significant figures.
Chapter 13 Solutions
General Chemistry: Principles and Modern Applications (11th Edition)
Ch. 13 - Prob. 1ECh. 13 - Consider a sample of ideal gas initially in a...Ch. 13 - Prob. 3ECh. 13 - Prob. 4ECh. 13 - Indicate whether each of the following changes...Ch. 13 - Arrange the entropy changes of the following...Ch. 13 - Prob. 7ECh. 13 - Prob. 8ECh. 13 - Indicate whether entropy increases or decreases in...Ch. 13 - Which substance in each of the following pairs...
Ch. 13 - Without performing any calculations or using data...Ch. 13 - By analogy to tH and tG how would you would you...Ch. 13 - Calculate the entropy change, S , for the...Ch. 13 - Calculate the entropy change, S , for the...Ch. 13 - IN Example 13-3, we dealt with vipH and vipH for...Ch. 13 - Pentane is one of the most volatile of the...Ch. 13 - Prob. 17ECh. 13 - Estimate the normal boiling point of bromine. Br2,...Ch. 13 - Prob. 19ECh. 13 - Refer to Figure 12-28 and equation (13.13) Which...Ch. 13 - Which of the following changes m a thermodynamic...Ch. 13 - If a reaction can be carried out only because of...Ch. 13 - Indicate which of the four cases in Table 13.3...Ch. 13 - Indicate which of the four cases in Table 13....Ch. 13 - For the mixing of ideal gases (see Figure 13-3),...Ch. 13 - In Chapter 14,, we will see that, for the...Ch. 13 - Explain why (a) some exothermic reactions do not...Ch. 13 - Explain why you would expect a reaction of the...Ch. 13 - From the data given in the following table,...Ch. 13 - Use data from Appendix D to determine values of tG...Ch. 13 - At 298 K, for the reaction...Ch. 13 - At 298 K, for the reaction...Ch. 13 - The following tG values are given for 25C ....Ch. 13 - The following tG values are given for 25C ....Ch. 13 - Write an equation for the combustion of one mole...Ch. 13 - Use molar entropies from Appendix D, together with...Ch. 13 - Assess the feasibility of the reaction...Ch. 13 - Prob. 38ECh. 13 - For each of the following reactions, write down...Ch. 13 - H2(g) can be prepared by passing steam over hot...Ch. 13 - In the synthesis of gasesous methanol from carbon...Ch. 13 - Prob. 42ECh. 13 - Use data from Appendix D to determine K at 298 K...Ch. 13 - Use data from Appendix D to establish for the...Ch. 13 - Use data from Appendix D to determine value at 298...Ch. 13 - Prob. 46ECh. 13 - Use thermodynamic data at 298 K to decide in with...Ch. 13 - Use thermodynamic data at 298 K to decide m which...Ch. 13 - For the reaction below, tG=27.07kJmol1 at 298 K....Ch. 13 - For the reaction below, tG=29.05kJmol1 at 298 K....Ch. 13 - For the reaction 2NO(g)+O2(g)2NO2(g) all but one...Ch. 13 - Prob. 52ECh. 13 - Prob. 53ECh. 13 - For the reaction 2SO2(g)+O2(g)2SO2(g),Kz=2.8102M1...Ch. 13 - Prob. 55ECh. 13 - Prob. 56ECh. 13 - Prob. 57ECh. 13 - Prob. 58ECh. 13 - To establish the law of conservation of mass,...Ch. 13 - Currently, CO2 is being studied as a source of...Ch. 13 - Prob. 61ECh. 13 - A possible reaction for converting methanol to...Ch. 13 - What must be the temperature W the following...Ch. 13 - Prob. 64ECh. 13 - The synthesis of ammonia by the Haber process...Ch. 13 - Use data from Appendix D to determine (a) tH,tS ,...Ch. 13 - Prob. 67ECh. 13 - The blowing equilibrium constants have been...Ch. 13 - For the reaction N 2 O 4 ( g ) 2N O 2 ( g ) , H e...Ch. 13 - Prob. 70ECh. 13 - Prob. 71ECh. 13 - Prob. 72ECh. 13 - Titanium is obtained by the reduction of TiCl4(l)...Ch. 13 - Prob. 74ECh. 13 - Prob. 75ECh. 13 - Prob. 76ECh. 13 - Prob. 77IAECh. 13 - Prob. 78IAECh. 13 - Consider the following hypothetical process in...Ch. 13 - One mole of argon gas, Ar(g), undergoes a change...Ch. 13 - Prob. 81IAECh. 13 - Consider the vaporization of water: H2O(l)H2O(g)...Ch. 13 - Prob. 83IAECh. 13 - Prob. 84IAECh. 13 - The following table shows the enthalpies end Gibbs...Ch. 13 - Prob. 86IAECh. 13 - Prob. 87IAECh. 13 - Prob. 88IAECh. 13 - Prob. 89IAECh. 13 - Prob. 90IAECh. 13 - Prob. 91IAECh. 13 - Prob. 92IAECh. 13 - Prob. 93IAECh. 13 - Prob. 94IAECh. 13 - Prob. 95IAECh. 13 - Use the following data to estimate,...Ch. 13 - Prob. 97IAECh. 13 - Prob. 98IAECh. 13 - Prob. 99IAECh. 13 - Prob. 100FPCh. 13 - The graph shows how shows how tG varies with...Ch. 13 - Prob. 102FPCh. 13 - Prob. 103FPCh. 13 - Prob. 104FPCh. 13 - Prob. 105SAECh. 13 - Briefly describe each of the following ideas,...Ch. 13 - Prob. 107SAECh. 13 - Prob. 108SAECh. 13 - Prob. 109SAECh. 13 - The reaction, 2Cl2O(g)2Cl2(g)+O2(g)tH=161kJ , is...Ch. 13 - Prob. 111SAECh. 13 - Prob. 112SAECh. 13 - Prob. 113SAECh. 13 - Prob. 114SAECh. 13 - Prob. 115SAECh. 13 - Prob. 116SAECh. 13 - Which of the following graphs of Gibbs energy...Ch. 13 - At room temperature and normal atmospheric...
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY