Biology
5th Edition
ISBN: 9781260487947
Author: BROOKER
Publisher: MCG
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Chapter 13, Problem 5TY
Summary Introduction
Introduction: Protein sorting and the function of secreting is carried out by SRP RNA – protein complex. Polypeptides are directed to the plasma membrane in bacteria and to the ER in eukaryotes. In bacteria, the SRP is made up of one ncRNA and one protein and in eukaryotes; it has six proteins and one ncRNA.
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The addition of the poly-A tail adds more than 200 units of adenine to the strand of mRNA, yet no protein has a continuous line of more than 200 phenylalanines in its structure. Why is this so?
A. RNA splicing occurs and removes the noncoding sequences.
B. The poly-A tail and 5' GTP cap do not translate into proteins.
C. The adenines are reabsorbed by the cell and help to form other forms of RNA.
D. The tRNA does not recognize the poly-A tail.
A scientist mutates eIF-2 to eliminate its GTP hydrolysis capability. How would this mutated form of eIF-2 alter translation? a. Initiation factors would not be able to bind to mRNA. b. The large ribosomal subunit would not be able to interact with mRNA transcripts. c. tRNAi-Met would not scan mRNA transcripts for the start codon. d. eIF-2 would not be able to interact with the small ribosomal subunit.
Imagine that mutations occurred in one of the inverted repeat sequences within the rho-independent
terminator sequence of a bacterium. What would likely be the consequence of this mutation?
Select one:
a. Transcription may not be initiated at all.
b. Transcription may end prematurely.
c. Transcription may be delayed.
d. The rho protein won't be able to bind and transcription may not be terminate.
e. Transcription may not be terminated and result in much longer RNA.
Chapter 13 Solutions
Biology
Ch. 13.1 - Prob. 1CCCh. 13.2 - Prob. 1CCCh. 13.3 - Prob. 1EQCh. 13.3 - Prob. 2EQCh. 13.3 - Prob. 3EQCh. 13.3 - Effects of Non-coding RNAs on Translation and mRNA...Ch. 13.4 - Non-coding RNAs and Protein Sorting Core Skill:...Ch. 13.5 - Core Skill: Modeling The goal of this modeling...Ch. 13 - Prob. 1TYCh. 13 - Prob. 2TY
Ch. 13 - Prob. 3TYCh. 13 - Prob. 4TYCh. 13 - Prob. 5TYCh. 13 - Prob. 6TYCh. 13 - With regard to miRNAs and siRNAs, which of the...Ch. 13 - Cas1 and Cas2 proteins play a role during which of...Ch. 13 - Which of the following components bind to...Ch. 13 - Abnormalities in the expression of ncRNAs are...Ch. 13 - An ncRNA may have one or more of the following...Ch. 13 - What is RNA interference (RNAi)? Explain how the...Ch. 13 - Prob. 3CQCh. 13 - Prob. 1COQCh. 13 - Go to the PubMed website and search for non-coding...
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- You design a protein with an N-terminal signal sequence and a single transmembrane domain. You also decide to tag your protein with GFP. If you want the GFP to be outside the cell, where should the GFP appear in the amino acid sequence? а. Between the signal sequence and the transmembrane domain b. At the C-terminal end of the protein (i.e., the last part of the protein to be translated с. Between the transmembrane domain and the C-terminus d. The GFP can be anywhere in the amino acid sequencearrow_forwardIf there is a mutation in importin that prevents it from interacting with the NLS of cargo proteins, what affect, if any, would this have on the UPR (unfolded protein response). A. Ran-GEF would bind to the importin promoting cargo entry into the nucleus and transcription of UPR response genes. B. Gene regulatory protein would not be imported into the nucleus thus preventing transcription of UPR response genes C. MRNA would not be imported into the nucleus thus preventing transcription of UPR response genes D. Ran-GTP would not be imported to the nucleus thus preventing transcription of UPR response genes E. No effect, these are completely unrelated processes.arrow_forwardIf you imagine a messenger RNA molecule in the cytoplasm of a cell, which of the following will likely affect how much protein is made by translation of this message? A. The presence of appropriate snRNPs. B. The length of the polyA tail. C. The strength of hydrogen bonds holding the mRNA to ribosomal RNA. D. The ability of the mRNA to pair with itself to form a helix-turn-helix structure.arrow_forward
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- What are two reasons that a eukaryotic gene (e.g. Green Fluorescent Protein in jellyfish) will not be expressed if it is inserted into a bacterial genome with no alterations? a. Bacterial genes do not contain introns b. Bacterial promoters have different consensus sequences than eukaryotic ones c. Transcription of this gene is affected by the simultaneous processes of transcription and translation d.arrow_forwardWhich of the following statements about trp operon regulation is TRUE? A. Low trp levels result in trp repressor binding. O B. High trp levels result in transcriptional antitermination. C. Low trp levels cause the ribosome to fall off at the trp codons in the upstream ORF. O D. High trp levels cause the ribosome to fall off at the trp codons in the upstream ORF. O E. Low trp levels result in transcriptional antitermination. QUESTION 34 Consider the following partial diploid for the lac operon system. lacl+ O+ lac Z+Y-A- lacls O+ 1. 2. lac Z-Y+ A+ In this configuration, which of the following statements is TRUE? A. With no lac present, ZYA will all be expressed. B. with lac present none of the genes (ZYA) will be expressed. O C. With no lac present, only YA will be expressed. D. None of these answers is correct. E. With no lac present, only Z will be expressed.arrow_forwardE. coli are grown on a medium containing lactose. Once glucose is added to the medium, the bacteria stop fermenting lactose. Which of the following BEST explains the observed effect? A. Cellular levels of cAMP are lowB.Glucose is bound to the promoter C. Repressor protein is bound to the operator D. Repressor protein is bound to the promoterarrow_forward
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