ENGINEERING FUNDAMENTALS
6th Edition
ISBN: 9781337705011
Author: MOAVENI
Publisher: CENGAGE L
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Chapter 13, Problem 5P
To determine
Plot the efficiency curve.
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Convert a flow of water flowing in a pipe 410
Liters/ hr into
kg/hr,
_m³/min
discharge in kg/hr
discharge in m3/min
4. The horizontal pump in the Figure discharges 13°C water at 26 m/h. Neglecting losses,
what power in kW is delivered to the water by the pump? y = 9790 N/m
100 kPa
300 kPa
Pump
D=12 cm
Dz=4 cm
A pump pumps water from one tank (open to atmosphere) to another tank (open to atmosphere) at a height of 25 m. A pipe with a diameter of 50 mm and a length of 100 m (e=1.5 mm) is used in the system. Since the variation of the pump's head with the flow rate is given as H= 50-20000Q^2, calculate the water flow through the pipe by ignoring the local losses (ρ=1000 kg/m^3, μ= 0.001 N.s/m)
Chapter 13 Solutions
ENGINEERING FUNDAMENTALS
Ch. 13.2 - Prob. 1BYGCh. 13.2 - Prob. 2BYGCh. 13.2 - Prob. 3BYGCh. 13.2 - Prob. 4BYGCh. 13.2 - Prob. 5BYGCh. 13.2 - Prob. BYGVCh. 13.4 - Prob. 1BYGCh. 13.4 - Prob. 2BYGCh. 13.4 - Prob. 3BYGCh. 13.4 - Prob. 4BYG
Ch. 13.4 - Prob. BYGVCh. 13.5 - Prob. 1BYGCh. 13.5 - Prob. 2BYGCh. 13.5 - Prob. 3BYGCh. 13.5 - Prob. 4BYGCh. 13.5 - Prob. 5BYGCh. 13.5 - Prob. BYGVCh. 13 - Prob. 1PCh. 13 - Prob. 2PCh. 13 - An elevator has a rated capacity of 2200 lb. It...Ch. 13 - Prob. 4PCh. 13 - Prob. 5PCh. 13 - Prob. 6PCh. 13 - Prob. 7PCh. 13 - Prob. 8PCh. 13 - Prob. 9PCh. 13 - Prob. 10PCh. 13 - Prob. 12PCh. 13 - Prob. 14PCh. 13 - Prob. 15PCh. 13 - Prob. 16PCh. 13 - Prob. 17PCh. 13 - Prob. 18PCh. 13 - Prob. 19PCh. 13 - Prob. 20PCh. 13 - Prob. 22PCh. 13 - Prob. 23PCh. 13 - Prob. 24PCh. 13 - Prob. 25PCh. 13 - Prob. 26PCh. 13 - Prob. 28PCh. 13 - Prob. 29PCh. 13 - Prob. 30PCh. 13 - Prob. 31PCh. 13 - Prob. 32PCh. 13 - Prob. 33PCh. 13 - Prob. 34PCh. 13 - Prob. 35PCh. 13 - Prob. 37PCh. 13 - Prob. 38P
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- The setup shown in the figure is being used to measure the energy loss across a valve. The velocity of flow of the oil is 1.2 m/s. Calculate the value of K if the energy loss is expressed as K (v 2 / 2g). 1.0 m Oil (sg = 0.90) Flow 380 mm Mercury (sg = 13.54)arrow_forwardThe following data were recorded when a centrifugal pump worked at its maximum efficiency: Q = 40 /ps ; Manometric head developed = 25 m; Input shaft horse power = 11.9 W. What is the non- dimensional specific speed of the pump it it was running at 1500 rpm? (May adopt the following (all in S.I. units): g¹/4 = 1.77, g/2² = 3-132, g/=5.544, √√21.414,5 = 2.236 and 10 = 3.162)arrow_forwardA tube of diameter 25 mm is used (as shown in the below figure) as a siphon to discharge water from a large open vessel into a drain at atmospheric pressure, (Given: Atmospheric pressure = 101.325 kPa) ignoring friction losses (3) (1) Determine (a)Velocity of flow through syphon (b)Discharge through the syphon (c)The minimum pressure inside the syphon (2) 160 mm 80 mm, 100 mmarrow_forward
- An open cylindrical vessel 1.2 m in diameter and 2.1 m high is 2/3 full of water. Compute the amount of water that will be spilled out of the vessel if the vessel is rotated about its vertical axis at a constant angular speed of 90 rpm. Select one: O a. 16 liters O b. 13 liters O c. 9.6 liters O d. 10 litersarrow_forwardThe discharge through a 75mm diameter orifice at the bottom of a large tank was measured to be 1734 liters for every minute. If the head over the orifice remains constant at 5.5m, determine the coefficient of discharge. (A 0.91 В 0.63 0.84 No Answer among the choices (E) 0.72arrow_forwardProblem 6: Energy Equation Demonstration Recently we saw a laboratory apparatus demonstrate several aspects of the energy equation. As you will recall, the cross-sectional area of the pipe varied from a maximum of 4.909×104 m² at point A to 7.854x105 m² at point E (factor of 6.25 difference): 76.08 BCDE SLOB 74 35 5.0 Part A What is the smallest velocity at Point E (VE) that will cause cavitation? T = 20°C, and you may assume the pressure at Point A (PA) is one Denver atmosphere, so PA = Patm = 85 kPa. Neglect the piezometer connections - assume they do not exist. [m/s] Part B In reality, of course, we do have piezometer connections at points A-F. What happens in the real apparatus when the discharge equals the result from Part A? (≤25 words)arrow_forward
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