Problem 6: Energy Equation Demonstration Recently we saw a laboratory apparatus demonstrate several aspects of the energy equation. As you will recall, the cross-sectional area of the pipe varied from a maximum of 4.909×10+ m² at point A to 7.854x105 m² at point E (factor of 6.25 difference): 75.08 BCDE 51.0 74 35 5.0 Part A What is the smallest velocity at Point E (VE) that will cause cavitation? T = 20°C, and you may assume the pressure at Point A (PA) is one Denver atmosphere, so PA = Patm = 85 kPa. Neglect the piezometer connections - assume they do not exist. [m/s] Part B In reality, of course, we do have piezometer connections at points A-F. What happens in the real apparatus when the discharge equals the result from Part A? (≤25 words)

Structural Analysis
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Problem 6: Energy Equation Demonstration
Recently we saw a laboratory apparatus demonstrate several aspects of the energy equation. As
you will recall, the cross-sectional area of the pipe varied from a maximum of 4.909×104 m² at
point A to 7.854x105 m² at point E (factor of 6.25 difference):
76.08
BCDE
SLOB
74
35
5.0
Part A
What is the smallest velocity at Point E (VE) that will cause cavitation? T = 20°C, and you may
assume the pressure at Point A (PA) is one Denver atmosphere, so PA = Patm = 85 kPa. Neglect
the piezometer connections - assume they do not exist. [m/s]
Part B
In reality, of course, we do have piezometer connections at points A-F. What happens in the real
apparatus when the discharge equals the result from Part A? (≤25 words)
Transcribed Image Text:Problem 6: Energy Equation Demonstration Recently we saw a laboratory apparatus demonstrate several aspects of the energy equation. As you will recall, the cross-sectional area of the pipe varied from a maximum of 4.909×104 m² at point A to 7.854x105 m² at point E (factor of 6.25 difference): 76.08 BCDE SLOB 74 35 5.0 Part A What is the smallest velocity at Point E (VE) that will cause cavitation? T = 20°C, and you may assume the pressure at Point A (PA) is one Denver atmosphere, so PA = Patm = 85 kPa. Neglect the piezometer connections - assume they do not exist. [m/s] Part B In reality, of course, we do have piezometer connections at points A-F. What happens in the real apparatus when the discharge equals the result from Part A? (≤25 words)
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