Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Question
Chapter 13, Problem 13.6P
(a)
To determine
Find the factor of safety of the slip plane.
(b)
To determine
Find the factor of safety of the slip plane using the ultimate friction angle.
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Students have asked these similar questions
A cut slope was excavated in saturated clay for installation of water piping system. The
angle Bof cut slope is 45° with the horizontal. During excavation works, slope failure was
occurred when the cut reached a depth of 4.0 m. Previous soil explorations showed that a
hard layer was located at a depth of 6 m below the ground surface. The unit weight of
saturated clay is 17.5 kN/m³. (Assuming an undrained condition).
1.
а)
Determine the undrained cohesion of the clay.
b)
Determine Factor of Safety (FoS) if the depth of cut slope is 3m.
What is the maximum depth of saturated clay can be excavated if the Factor
of Safety (FoS) 1.4 to be implemented?
c)
A cut slope was excavated in saturated clay for installation of water piping system. The
angle Bof cut slope is 45° with the horizontal. During excavation works, slope failure was
occurred when the cut reached a depth of 4.0 m. Previous soil explorations showed that a
hard layer was located at a depth of 6 m below the ground surface. The unit weight of
saturated clay is 17.5 kN/m. (Assuming an undrained condition).
1.
a)
Determine the undrained cohesion of the clay.
b)
Determine Factor of Safety (FoS) if the depth of cut slope is 3m.
c)
What is the maximum depth of saturated clay can be excavated if the Factor
of Safety (FoS) 1.4 to be implemented?
A 40° slope is excavated to a depth of 8 m in a deep layer of saturated clay
having strength parameters, c = 60 kN/m², p = 0, and y- 19 kN/m³. Determine the
factor of safety for the trial failure surface shown in below figure using Swedish
circle method.
8 m
40°
95⁰
R = 10.2 m
4m-
W = 1050 kN
THE W
Chapter 13 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
Ch. 13 - Prob. 13.1PCh. 13 - Prob. 13.2PCh. 13 - Prob. 13.3PCh. 13 - Prob. 13.4PCh. 13 - Prob. 13.5PCh. 13 - Prob. 13.6PCh. 13 - Prob. 13.7PCh. 13 - Prob. 13.8PCh. 13 - Prob. 13.9PCh. 13 - Prob. 13.10P
Ch. 13 - Prob. 13.11PCh. 13 - Prob. 13.12PCh. 13 - Prob. 13.13PCh. 13 - Prob. 13.14PCh. 13 - Prob. 13.15PCh. 13 - Prob. 13.16PCh. 13 - Prob. 13.17PCh. 13 - Prob. 13.18PCh. 13 - Prob. 13.19PCh. 13 - Prob. 13.20PCh. 13 - Prob. 13.21PCh. 13 - Prob. 13.22PCh. 13 - Prob. 13.23PCh. 13 - Prob. 13.25PCh. 13 - Prob. 13.26PCh. 13 - Prob. 13.27CTPCh. 13 - Prob. 13.28CTPCh. 13 - Prob. 13.29CTP
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- A trench was cut in a clay slope as shown in the figure. When the trench reached a depth of 3 m, the top portion of the clay suddenly failed. On investigating, the failure was observed to be a slip plane approximately parallel to the original slope. Clay Y = 17.5 kN/m² 3m 36° The undrained shear strength (in kPa) of the clay will be.arrow_forwardA cut slope is to made. The unit weight of soil is 17 kN/m^3 and the angle of internal friction is 20°. The soil has a cohesion of 24 kPa. The cut slope makes an angle of 30° with the horizontal and the height is 9 m. if the trial failure plane is 15°from the horizontal. Determine the following: 1. Frictional force along the failure plane. 2. Cohesive force along the failure plane. 3. Factor of safety against sliding.arrow_forwardAn infinite slope of granular soil has a slope of 29 degrees. The soil has a dry unit weight of 18.02kN/m^3 and a saturated unit weight of 21.15kN/m^3. The soil has a depth of 5 meters over ledge rock measure vertically. Effective friction angle and soil cohesion are 14 degrees and 25 kPa, respectively. a) Compute the factor of safety considering no seepage. b) Compute the factor of safety considering full seepagearrow_forward
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- (Note:Depth of rock layer is 2m not 12 m.) Q A cut slope was excavated in a saturated clay with a slope angle β = 57 ͦ with the horizontal. Slope failure occurred when the cut reached a depth of 8 m. Previous soil explorations showed that a rock layer was located at a depth of 2 m below the ground surface. Assuming an undrained condition and that ɣsat = 21 kN/m3 : Determine the undrained cohesion of the clay (Fig 3). What was the nature of the critical circle? With reference to the top of the slope, at what distance did the surface of the sliding intersect the bottom of the excavation?arrow_forward1. Determine the gradient of each point from point 1. ( 2540 2540 2290 650-m from point 1-2 850-m from point 1-3 1550-m from point 1-4 Contour map units: meters 2. Given a density of a cubical quart rock to be 2650 kg/m³, determine the lithostatic stress on 800,000 cm³ volume if the acceleration is 980 cm/sec² with a depth of burial to be 6 miles./arrow_forwardAnswer Q13 to Q 15 based on following description A cutting in a saturated clay is inclined at a slope 1 vert:1.2 horizontal and has a vertical height of 10.0 m. The bulk unit weight of the soil is 18 kN/m³ and its undrained cohesion is 35 kN/m³. Undrained friction angle, -0. Area of slip mass = 51.2 m², d= 7 m r=12m 2m 1 W 10m FoS of a slope along a circular slip surface is given by; cular F = Wd Calculate the arc length along the slip surface, La a-964.8 m O b. 16.8 m O c. 114.0 m O d. 8.4 m d=5m 1.2arrow_forward
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