Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Question
Chapter 13, Problem 13.3P
(a)
To determine
Find the height for critical equilibrium.
(b)
To determine
Find the factor of safety of the slope against sliding.
(c)
To determine
Find the height for a factor of safety of 2.5 against sliding.
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Students have asked these similar questions
Question No. 16
A long slope is formed in a soil with shear strength
parameters: c' = 0 and d' = 34°. A firm stratum lies
below the slope and it is assumed that the water
table may occasionally rise to the surface, with
seepage taking place parallel to the slope. Use
Ysat = 18 kN/m³ and Yw = 10 kN/m³. The maximum
slope angle (in degrees) to ensure a factor of
safety of 1.5, assuming a potential failure surface
parallel to the slope, would be
The figure below shows a slope with an inclination of B = 56°. If AC represents a trial failure plane inclined at an angle 0 = 33° with the horizontal, determine the factor of safety against sliding
for the wedge ABC. Given H = 8.4 m; y = 20 kN/m³: ' = 21°; and c' = 36 kN/m?.
(Round your final answer to two decimal places.)
F, =
Q.1. Refer to the infinite slope shown in Figure 1. Given: β = 19 ͦ,
ɣ = 20 kN/m3
, Ø = 33 ͦ,
and c’ = 47 kN/m2
. Find the height, H, such that a factor of safety, Fs = 3.1 is maintained
against sliding along the soil-rock interface.
Chapter 13 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
Ch. 13 - Prob. 13.1PCh. 13 - Prob. 13.2PCh. 13 - Prob. 13.3PCh. 13 - Prob. 13.4PCh. 13 - Prob. 13.5PCh. 13 - Prob. 13.6PCh. 13 - Prob. 13.7PCh. 13 - Prob. 13.8PCh. 13 - Prob. 13.9PCh. 13 - Prob. 13.10P
Ch. 13 - Prob. 13.11PCh. 13 - Prob. 13.12PCh. 13 - Prob. 13.13PCh. 13 - Prob. 13.14PCh. 13 - Prob. 13.15PCh. 13 - Prob. 13.16PCh. 13 - Prob. 13.17PCh. 13 - Prob. 13.18PCh. 13 - Prob. 13.19PCh. 13 - Prob. 13.20PCh. 13 - Prob. 13.21PCh. 13 - Prob. 13.22PCh. 13 - Prob. 13.23PCh. 13 - Prob. 13.25PCh. 13 - Prob. 13.26PCh. 13 - Prob. 13.27CTPCh. 13 - Prob. 13.28CTPCh. 13 - Prob. 13.29CTP
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- Knowing that L = 4 m, Concentrated load P = 15 kN and uniform distributed load w = 12 kN/m, determine the slope at C by Castigliano’s Theorem.(E= 200 GPa, I = 40x106 mm4)arrow_forwardA long slope is made up of a cohesionless (c'=0) soil with the internal friction angle of 34°. If the water table rises to the surface of the slope, then determine the maximum possible value of the slope angle to get a factor of safety of 1.5. Take saturated unit weight as18 kN/m3 and the unit weight of water as 10 kN/m3.arrow_forward3. For the slope shown in Figure below, determine the factor of safety against sliding along the circular slip surface AC. Use the ordinary method of slices. 27 m 7.5 m 3 21 m y= 19 kN/m3 c' = 31 kN/m2 6. 5 d'= 24° A 30°arrow_forward
- For the infinite slope shown in Figure 15.46, determine the height, H, for critical equilibrium. Given: β = 27°, γ = 19.5 kN/m3, ϕ′ = 18°, and c′ = 35.9 kN/m3.arrow_forward1. Find the Factor of safety against sliding along the interface for the infinite slope shown in Figure. Also find the height Z that will give F.S of 2 against sliding along the interface. B=25" Z=2.43 m Y= 16 KN/m 10 kN/m² 1-159 Interfacearrow_forwardAn infinite slope of soil, with height 10 m, is inclined at an angle of 35° to the horizontal. The soil has c' = 22 kN/m², ' = 22º. A stability analysis by the method of slices has given the following forces per running meter Σ Shearing forces = 350 kN Σ Normal forces = 755 kN Σ Neutral forces = 175 kN If the length of arc is 19 m then the ratio of F.O.S with respect to cohesion to the F.O.S with respect to shearing strength isarrow_forward
- A cut slope was excavated in saturated clays as shown in the figure. The soil has a unit weight of 17 kN/m³ and an undrained shear strength cᵤ = 20 kPa. The slope make an angle of 60° with the horizontal. Assume stability number m = 0.185. Slope failure occurs along the plane AC with BC = 8 m. Which of the following most nearly gives the stability factor?arrow_forward7. A long slope is formed in a soil with shear strength parameters: c' = 0 and '= 34°. A firm stratum lies below the slope and it is assumed that the water table may occasionally rise to the surface, with seepage taking place parallel to the slope. Use Ysat = 18 kN/m³ and y = 10 kN/m³. The Yw maximum slope angle (in degrees) to ensure a factor of safety of 1.5, assuming a potential failure surface parallel to the slope, would bearrow_forwardFigure 5 shows an infinite slope with H = 30 ft and the groundwater table coinciding with the ground surface. If there is seepage through the soil, determine the factor of safety against sliding along the plane AB. The soil properties are Gs = 2.7, e = 0.8, β = 16 ͦ, Ø = 21 ͦ, and c’ = 1250 lb/ft2.arrow_forward
- A 45 ° slope as shown in figure has been excavated to a depth of 6 m in a saturated clay having the following properties: C₁ = 50 kN/m² ₂ 0 = 0 and y = 19 kN/m²³ Determine the factor of safety. [Take area of wedge 39 m²] ok 3.4 m f 2.65 m 6m 45° 90° = 9marrow_forwardFigure 15.47 shows an infinite slope with H = 9.14 m and the groundwater table coinciding with the ground surface. If there is seepage through the soil, determine the factor of safety against sliding along the plane AB. The soil properties are Gs = 2.7, e = 0.8, β = 16°, ϕ′ = 21°, and c′ = 59.8 kN/m2.arrow_forwardAn embankment has a slope of 30° which was constructed with soil having = 15 = 30 kN/m², b 20° and y kN/m³. The height of the embankment is 20 m. Using Taylor's stability no 1/40, the factor of safety with respect to cohesion is C =arrow_forward
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