Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Question
Chapter 13, Problem 13.4P
To determine
Find the factor of safety against sliding along plane AB.
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Please calculate the critical factor of safety for the following slope configuration using the following m
ethods: Using slope stability charts
Layer 1
Clay
c=35 kN/sq.m
Friction Angle=0
Unit Weight-18 kN/cu.m
Layer 2
Silty Sand
c=5 kN/sq.m
Friction Angle=35 deg
Unit Weight=18 kN/cu.m
Slope Height=10 m
Slope Angle=30 Degrees
Layer 1
An infinite slope of granular soil has a slope of 29 degrees. The soil has a dry unit weight of 18.02kN/m^3 and a saturated unit weight of 21.15kN/m^3. The soil has a depth of 5 meters over ledge rock measure vertically. Effective friction angle and soil cohesion are 14 degrees and 25 kPa, respectively.
a) Compute the factor of safety considering no seepage.
b) Compute the factor of safety considering full seepage
(Note:Depth of rock layer is 2m not 12 m.)
Q A cut slope was excavated in a saturated clay with a slope angle β = 57 ͦ with the horizontal. Slope failure occurred when the cut reached a depth of 8 m. Previous soil explorations showed that a rock layer was located at a depth of 2 m below the ground surface. Assuming an undrained condition and that ɣsat = 21 kN/m3 : Determine the undrained cohesion of the clay (Fig 3). What was the nature of the critical circle? With reference to the top of the slope, at what distance did the surface of the sliding intersect the bottom of the excavation?
Chapter 13 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
Ch. 13 - Prob. 13.1PCh. 13 - Prob. 13.2PCh. 13 - Prob. 13.3PCh. 13 - Prob. 13.4PCh. 13 - Prob. 13.5PCh. 13 - Prob. 13.6PCh. 13 - Prob. 13.7PCh. 13 - Prob. 13.8PCh. 13 - Prob. 13.9PCh. 13 - Prob. 13.10P
Ch. 13 - Prob. 13.11PCh. 13 - Prob. 13.12PCh. 13 - Prob. 13.13PCh. 13 - Prob. 13.14PCh. 13 - Prob. 13.15PCh. 13 - Prob. 13.16PCh. 13 - Prob. 13.17PCh. 13 - Prob. 13.18PCh. 13 - Prob. 13.19PCh. 13 - Prob. 13.20PCh. 13 - Prob. 13.21PCh. 13 - Prob. 13.22PCh. 13 - Prob. 13.23PCh. 13 - Prob. 13.25PCh. 13 - Prob. 13.26PCh. 13 - Prob. 13.27CTPCh. 13 - Prob. 13.28CTPCh. 13 - Prob. 13.29CTP
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- A 9m cut slope is shown in the figure. The unit weight of soil is 17kN/m3. Friction angle and cohesion along the rock surface are 20 degrees and 24kPa respectively. The slope makes an angle of 300 from horizontal and the failure plane is at 150. Determine the developed frictional force on the failure plane.arrow_forward4. A slope is 5 m high and has an angle of 45°. The soil parameters of the soil are: c'= 18 kN/m?, O'=15° and y = 17.1 kN/m³. Determine the factor of safety, Fs, using Michalowski's (2002) kinematic approach for c'-o' soils.arrow_forwardA cut slope was excavated in saturated clay for installation of water piping system. The angle Bof cut slope is 45° with the horizontal. During excavation works, slope failure was occurred when the cut reached a depth of 4.0 m. Previous soil explorations showed that a hard layer was located at a depth of 6 m below the ground surface. The unit weight of saturated clay is 17.5 kN/m³. (Assuming an undrained condition). 1. а) Determine the undrained cohesion of the clay. b) Determine Factor of Safety (FoS) if the depth of cut slope is 3m. What is the maximum depth of saturated clay can be excavated if the Factor of Safety (FoS) 1.4 to be implemented? c)arrow_forward
- A cut slope was excavated in a saturated clay. The slope made an angle of 39.55 degree with the horizontal. Slope failure occurred when the cut reached a depth of 6 m. Previous soil explorations showed that a rock layer was located at a depth of 10 m below the ground surface. Assuming an undrained condition and γsat = 18 kN/m3, Analyze the following. a. undrained cohesion of the clay.b. nature of the critical circle?c. With reference to the toe of the slope, at what distance did the surface of sliding intersect the bottom of the excavation?arrow_forwardIn the problem the slope appeared to be stable with a factor of safety = 2.7. What happens to that factor of safety if the water table rises to the level shown below? Use a unit weight of 20.1 kN/m³, and bedding strength parameters are reduced by the effective parameters ofc' = 15 kPa and p'= 20°. 20.0 m Seepage Original ground surface 1.5 16° 85.0 m 11.3 m 3.2 m Rock's bedding planes Proposed new ground surfacearrow_forwardA cut slope was excavated in saturated clay for installation of water piping system. The angle Bof cut slope is 45° with the horizontal. During excavation works, slope failure was occurred when the cut reached a depth of 4.0 m. Previous soil explorations showed that a hard layer was located at a depth of 6 m below the ground surface. The unit weight of saturated clay is 17.5 kN/m. (Assuming an undrained condition). 1. a) Determine the undrained cohesion of the clay. b) Determine Factor of Safety (FoS) if the depth of cut slope is 3m. c) What is the maximum depth of saturated clay can be excavated if the Factor of Safety (FoS) 1.4 to be implemented?arrow_forward
- Q.3. A cut slope was excavated in a saturated clay with a slope angle β = 57 ͦ with the horizontal. Slope failure occurred when the cut reached a depth of 8 m. Previous soil explorations showed that a rock layer was located at a depth of 2 m below the ground surface. Assuming an undrained condition and that ɣsat = 19 kN/m3 : Determine the undrained cohesion of the clay (Fig 3). What was the nature of the critical circle? With reference to the top of the slope, at what distance did the surface of the sliding intersect the bottom of the excavation?arrow_forwardAn infinite slope of clay soil has a slope of 29 degrees. The soil has a specific gravity of 2.7 and a void ratio of 0.47. The soil has a depth of 5m over ledge rock measured vertically. Effective friction angle and soil cohesion are 14 degrees and 25kPa respectively. Assuming the ground water table is in the ground surface, determine the limiting depth of this soil, measured vertically over ledge rock. A 1.25m B 5.95m 3.67m D 6.88marrow_forwardA cut slope of h= 7m was excavated in a saturated clay with a slope of angle beta = 45 degrees with the horizontal. The Previous explorations showed that a rock layer was located at a depth of 14 m. Given that, c = 60 kN/m² and unit weight = 17 kN / (m ^ 3) . Determine the factor of safety.arrow_forward
- 6. Plot the variation of Ovo, Dovo and u with depth for the soil profile overleaf. 4 m Sand Ym = 17.5 kN/m³ 2 m Ym = 17.0 kN/m3 Sandy gravel 3 m Ysat = 19.5 kN/m3 3 m Clay Ysat = 19.0 kN/m³ %3Darrow_forward2. A cut slope is to be made as shown. The unit weight of soil is 18KN/cu.m and the angle of internal friction is 22°. The soil has cohesion of 30 Kpa. The cut slope makes an angle of 30° with the horizontal and the height is 12 m. If the failure plane is 15° from horizontal. Determine a. Frictional force along the failure plane b. Cohesive force along the failure plane Factor of safety against sliding B 24 m A trial failure plane 12 m 30 15° Carrow_forwarde 120 m GL. 118 m GWL (2) A ground soil profile is shown in the right 7 Y =19 KN/m³ Y-21 KN/m³ figure. Soil layer information and their unit weights clay v 116 m are presented in the figure. The groundwater level Y-20 KN/m³ sand is 2 m below the ground surface. Find the vertical 111 m. effective overburden aressure and plot its clay Y=21 KN/m³ distribution curve. 107 m.arrow_forward
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