Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Question
Chapter 13, Problem 13.10P
To determine
Find the factor of safety with respect to sliding.
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Find slope at D in degrees using double integration method. Consider 250 mm x 400 mm (b x h) section and E = 120 GPa. Use a = 3.2 m, b = 19.1 kN/m, and c = 25.5 kN
A slope is shown in the figure below. If AC represents a trial failure plane, determine the factor of safety against sliding for the wedge ABC. Given: β= 570 , ϒ = 17.5 kN/m3 , φ’ = 13.50 , and c’ =27 kN/m2Please use the Culmann’s method
B. Briefly Comment on how to analyze a slope and determine the factor of safety against overturning.
This is a question from slope stability bishop method
Please Note i am not asking for the entire problem to be completed, i am simply seeking guidance on how to calculate slice 1 entire row that is highlighted in red.
example
how did we derive the values of (W) in the table.
formula ....W=ybz but im not getting the values
see diagram attached
Question
A compacted earth fill is constructed on a soft, saturated clay (figure below). The fill was compacted to an average dry unit weight of 19 kN m3 ⁄ and water content of 15%. The shearing strength of the fill was determined by CU tests on samples compacted to representative field conditions. The shear strength parameters are ?? = 45 kPa, ??′ = 34°, and ???′ = 28°. The variation of undrained shear strength of the soft clay with depth as determined by simple shear tests is shown in the figure below, and the friction angle at the critical state is ???′ = 30°. The average water content of the soft clay is 40%. Compute the factor of safety…
Chapter 13 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
Ch. 13 - Prob. 13.1PCh. 13 - Prob. 13.2PCh. 13 - Prob. 13.3PCh. 13 - Prob. 13.4PCh. 13 - Prob. 13.5PCh. 13 - Prob. 13.6PCh. 13 - Prob. 13.7PCh. 13 - Prob. 13.8PCh. 13 - Prob. 13.9PCh. 13 - Prob. 13.10P
Ch. 13 - Prob. 13.11PCh. 13 - Prob. 13.12PCh. 13 - Prob. 13.13PCh. 13 - Prob. 13.14PCh. 13 - Prob. 13.15PCh. 13 - Prob. 13.16PCh. 13 - Prob. 13.17PCh. 13 - Prob. 13.18PCh. 13 - Prob. 13.19PCh. 13 - Prob. 13.20PCh. 13 - Prob. 13.21PCh. 13 - Prob. 13.22PCh. 13 - Prob. 13.23PCh. 13 - Prob. 13.25PCh. 13 - Prob. 13.26PCh. 13 - Prob. 13.27CTPCh. 13 - Prob. 13.28CTPCh. 13 - Prob. 13.29CTP
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- A cut slope was excavated in a saturated clay. The slope made an angle of 39.55 degree with the horizontal. Slope failure occurred when the cut reached a depth of 6 m. Previous soil explorations showed that a rock layer was located at a depth of 10 m below the ground surface. Assuming an undrained condition and γsat = 18 kN/m3, Analyze the following. a. undrained cohesion of the clay.b. nature of the critical circle?c. With reference to the toe of the slope, at what distance did the surface of sliding intersect the bottom of the excavation?arrow_forwardUsing Method of Virtual work, determine the slope at point A. Use E = 200GPA and I = 100x10° mm Use Castigliano's Theorem and determine the slope at A. Use E = 200GP and I = 100x1o mm* 40 kN 40 kN A B -1.5 m -1.5 m- -1.5 m+1.5 m-arrow_forwardThe figure below shows a slope with an inclination of B = 56°. If AC represents a trial failure plane inclined at an angle 0 = 33° with the horizontal, determine the factor of safety against sliding for the wedge ABC. Given H = 8.4 m; y = 20 kN/m³: ' = 21°; and c' = 36 kN/m?. (Round your final answer to two decimal places.) F, =arrow_forward
- Use the conjugate beam method and determine the slope at B and the displacement at C. Take L = 1 m, w = 7 kN/m and EI = 10000 kNm². A L Part 1) The magnitude of slope at B, OB B ★ Part 2) The magnitude of displacement at C, Ac = 10-3 rad mm O Larrow_forward3. For the slope shown in Figure below, determine the factor of safety against sliding along the circular slip surface AC. Use the ordinary method of slices. 27 m 7.5 m 3 21 m y= 19 kN/m3 c' = 31 kN/m2 6. 5 d'= 24° A 30°arrow_forwardBriefly explain the meaning of FS = 1.0 for sand followed by the infinite slope analysis.arrow_forward
- A cut slope was excavated in saturated clays as shown in the figure. The soil has a unit weight of 17 kN/m³ and an undrained shear strength cᵤ = 20 kPa. The slope make an angle of 60° with the horizontal. Assume stability number m = 0.185. Slope failure occurs along the plane AC with BC = 8 m. Which of the following most nearly gives the stability factor?arrow_forwardSand is placed on a rock slope, as shown in Figure Q2. (a) Show that sand will be stable (i.e., no sliding sliding) ifarrow_forwardA 45° slope as shown in figure has been excavated to a depth of 6 m in a saturated clay having the following properties Cu= 50 kN/m², qu=0° and y = 19 kN/m³ Determine the factor of safety. [Take area of wedge = 39 m²]arrow_forward3. For the planar wedge shown below: 22 m Slip surface 39° 28° Calculate the factor of safety against plane failure assuming: p (degree) > (kN/m³) c (kPa) 55 2800 1850 c: cohesion of rock mass; y: unit weight of rock mass; p: friction angle of rock mass جیهان کاظیarrow_forwardA 45 ° slope as shown in figure has been excavated to a depth of 6 m in a saturated clay having the following properties: C₁ = 50 kN/m² ₂ 0 = 0 and y = 19 kN/m²³ Determine the factor of safety. [Take area of wedge 39 m²] ok 3.4 m f 2.65 m 6m 45° 90° = 9marrow_forwardAn embankment has a slope of 30° which was constructed with soil having = 15 = 30 kN/m², b 20° and y kN/m³. The height of the embankment is 20 m. Using Taylor's stability no 1/40, the factor of safety with respect to cohesion is C =arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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