Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 13, Problem 13.12P
To determine
Find the critical depth of the excavation.
Find the inclination of the failure plane with respect to the horizontal.
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A cut slope was excavated in sand. The slope is shown in following attachment .
To find the properties of the sand, representative samples were taken for the soil and tested in atriaxial apparatus. A consolidated drained triaxial test was conducted. The result is given below:Chamber pressure = 103 kN/m2Deviator stress at failure = 234.6 kN/m2We know the unit weight of the sand is 16 kN/m3.Use the ordinary method of slices (use 7 slices) and estimate the factor of safety against sliding forshown slip surface and comment on the calculated factor of safety.Please note that:1. The figure is not in scale. You may resketch it in scale and calculate the factor of safety2. The slip surface is circular and passes through the toe of the embankment
The figure below shows a proposed site where an excavation will be made. The 12 ft layer of sand will be removed, so that the top of the 30 ft normally consolidated clay layer will be exposed (Assume that changes in GWT do not affect γt of clay). a. Assume that the water-table location remains the same during excavation. Compute the σ, σ′v, and u values at the middle of the clay layer before and after the excavation b. Assuming 1-D conditions, compute how much the clay layer will deform due to this excavation, in inches. Specify whether this is settlement or heave
A cut slope was excavated in saturated clay for installation of water piping system. The
angle Bof cut slope is 45° with the horizontal. During excavation works, slope failure was
occurred when the cut reached a depth of 4.0 m. Previous soil explorations showed that a
hard layer was located at a depth of 6 m below the ground surface. The unit weight of
saturated clay is 17.5 kN/m. (Assuming an undrained condition).
1.
a)
Determine the undrained cohesion of the clay.
b)
Determine Factor of Safety (FoS) if the depth of cut slope is 3m.
c)
What is the maximum depth of saturated clay can be excavated if the Factor
of Safety (FoS) 1.4 to be implemented?
Chapter 13 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
Ch. 13 - Prob. 13.1PCh. 13 - Prob. 13.2PCh. 13 - Prob. 13.3PCh. 13 - Prob. 13.4PCh. 13 - Prob. 13.5PCh. 13 - Prob. 13.6PCh. 13 - Prob. 13.7PCh. 13 - Prob. 13.8PCh. 13 - Prob. 13.9PCh. 13 - Prob. 13.10P
Ch. 13 - Prob. 13.11PCh. 13 - Prob. 13.12PCh. 13 - Prob. 13.13PCh. 13 - Prob. 13.14PCh. 13 - Prob. 13.15PCh. 13 - Prob. 13.16PCh. 13 - Prob. 13.17PCh. 13 - Prob. 13.18PCh. 13 - Prob. 13.19PCh. 13 - Prob. 13.20PCh. 13 - Prob. 13.21PCh. 13 - Prob. 13.22PCh. 13 - Prob. 13.23PCh. 13 - Prob. 13.25PCh. 13 - Prob. 13.26PCh. 13 - Prob. 13.27CTPCh. 13 - Prob. 13.28CTPCh. 13 - Prob. 13.29CTP
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- In a clayey soil having 50 kN/m² as unit cohesion and 18 kN/m³ as unit weight, an excavation is made with a vertical face. Taking Taylor's stability number as 0.261, what is the maximum depth of excavation so that the vertical face remains stable?arrow_forwardThe excavation shown below will be made on the clay for the construction of a highway. Potential Slope stability analysis is required on the slip plane. The ground is silty clay and c '= 18 kPa,' '= 20o and water = 100 kPa. At point a If the shear stress is 60 kPa, calculate the safety coefficient for this point.arrow_forwardAn excavation is made with a vertical face in a clay soil which has C_{u} = 50kN /(m ^2) gamma_{1} = 18kN / (m^3) and S_{n} = 0.261. The maximum depth of a stable excavation will be nearly?arrow_forward
- An excavation is to be made in purely cohesive soil deposit having c = 20 kN/m² and unit weight = 16 kN/m³. The depth to which the vertical sides of the excavation will remain stable without side supports will be:arrow_forwardAn excavation is rapidly made on site as depicted in the Figure below. The soil wedge above the critical slip surface is divided into thirteen slices. Based on the ordinary method of slices, calculate the ratio (R/S) between the Resisting Force (R) and the Driving Force (S) for slice #3, shortly after the excavation is completed. (Acceptable tolerance = 4%). The geometry of slice #3 and the soil properties are provided in the tables below. The height of water at the middle of the slice is hw = 3.0 m. Note that the total weight of the slice is equal to the weight of the saturated soil below the water table plus the weight of the moist soil above the water table. Hint: the weight of slice #3 is 495 kNarrow_forwardA cut slope was excavated in saturated clay for installation of water piping system. The angle Bof cut slope is 45° with the horizontal. During excavation works, slope failure was occurred when the cut reached a depth of 4.0 m. Previous soil explorations showed that a hard layer was located at a depth of 6 m below the ground surface. The unit weight of saturated clay is 17.5 kN/m³. (Assuming an undrained condition). 1. а) Determine the undrained cohesion of the clay. b) Determine Factor of Safety (FoS) if the depth of cut slope is 3m. What is the maximum depth of saturated clay can be excavated if the Factor of Safety (FoS) 1.4 to be implemented? c)arrow_forward
- Q7: When a vertical face excavation was made in a deposit of clay, it failed at a depth of 2.8 m of excavation. Find the shear strength parameters of the soil if its bulk density is 17 kN/m³.arrow_forwardAnswer Q13 to Q 15 based on following description A cutting in a saturated clay is inclined at a slope 1 vert:1.2 horizontal and has a vertical height of 10.0 m. The bulk unit weight of the soil is 18 kN/m³ and its undrained cohesion is 35 kN/m³. Undrained friction angle, -0. Area of slip mass = 51.2 m², d= 7 m r=12m 2m 1 W 10m FoS of a slope along a circular slip surface is given by; cular F = Wd Calculate the arc length along the slip surface, La a-964.8 m O b. 16.8 m O c. 114.0 m O d. 8.4 m d=5m 1.2arrow_forward3. In a large field with a flat surface, an excavation will take place. According to the drilling works, no groundwater was encountered, and a homogeneous cohesionless soil has been found throughout the excavation depth. As a result of the experiments, the internal friction angle of the relevant soil was found to be 24°, and the dry and saturated unit weights were 17 kN/m³ and 19.2 kN/m², respectively. According to the information given, what is the inclination of the steepest slope that can be excavated in the area?arrow_forward
- Q.4 A 40° slope is excavated to a depth of 8 m in a deep layer of saturated clay having strength parameters c = 58 kN/m², Ø = 0, and y = 18 kN/m³. Determine the factor of safety for the trial failure surface shown in Fig. 4 Q.5 Figure 5 shows an infinite slope with H = 32 ft and the groundwater table coincidingarrow_forwardAn excavation was made in saturated, soft clay (øu=0), with its sides vertical. When the depth of excavation reached 6m, the sides caved in. What was the approximate value of cohesion for the clayey soil? Take unit weight of clay as 20KN/m³.arrow_forwardProperties of soil and concrete 4m O = 30° Cohesion =0 Coefficient of base friction = 0. 50 Soil's ultimiate bearing capacity= 425 kNm deoncrete = 23.6 kN /m? Use Ronkine's theory considering no evoson and future excavation would happen in the Soil. %3D 12 D. %3D a) Determine the location of the active force from the base. b) Determine the total noirmal force reaction of soil at the boser c) Determine FS SLIDING . d) Determine FSauturning o e) Determine FSpering.arrow_forward
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