Chapter 11.2, Problem 16SP

(a)

Interpretation Introduction

Interpretation: The complete and balanced reactions are to be stated.

Concept Introduction : According to the law of conservation of mass, the mass can neither be created nor to be destroyed. Every reaction must be balanced.

Answer to Problem 16SP

The complete and balanced equation is $\text{3NaOH}\left(aq\right)+\text{Fe}{\left({\text{NO}}_{\text{3}}\right)}_{\text{3}}\left(aq\right)\to \text{Fe}{\left(\text{OH}\right)}_{\text{3}}\left(s\right)+3{\text{NaNO}}_{\text{3}}\left(aq\right)$ .

Explanation of Solution

The complete and balanced equation is given as:

  $\text{NaOH}\left(aq\right)+\text{Fe}{\left({\text{NO}}_{\text{3}}\right)}_{\text{3}}\left(aq\right)\to \text{Fe}{\left(\text{OH}\right)}_{\text{3}}\left(s\right)+{\text{NaNO}}_{\text{3}}\left(aq\right)$

The co-efficient of 3 is placed before $\text{NaOH}$ and ${\text{NaNO}}_{\text{3}}$ . The balanced equation is:

  $\text{3NaOH}\left(aq\right)+\text{Fe}{\left({\text{NO}}_{\text{3}}\right)}_{\text{3}}\left(aq\right)\to \text{Fe}{\left(\text{OH}\right)}_{\text{3}}\left(s\right)+3{\text{NaNO}}_{\text{3}}\left(aq\right)$

(b)

Interpretation Introduction

Interpretation: The complete and balanced reactions are to be stated.

Concept Introduction : According to the law of conservation of mass, the mass can neither be created nor to be destroyed. Every reaction must be balanced.

Answer to Problem 16SP

The complete and balanced equation is $\text{3Ba}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(aq\right)+2{\text{H}}_{\text{3}}{\text{PO}}_{\text{4}}\left(aq\right)\to {\text{Ba}}_3{\left({\text{PO}}_{\text{4}}\right)}_{\text{2}}\left(s\right)+6{\text{HNO}}_{\text{3}}\left(aq\right)$ .

Explanation of Solution

The complete and balanced equation is given as:

  $\text{Ba}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(aq\right)+{\text{H}}_{\text{3}}{\text{PO}}_{\text{4}}\left(aq\right)\to {\text{Ba}}_3{\left({\text{PO}}_{\text{4}}\right)}_{\text{2}}\left(s\right)+{\text{HNO}}_{\text{3}}\left(aq\right)$

The co-efficient of 3 is placed before $\text{Ba}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}$ , 2 before ${\text{H}}_{\text{3}}{\text{PO}}_{\text{4}}$ and 6 before ${\text{HNO}}_{\text{3}}$ . The balanced equation is:

  $\text{3Ba}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}\left(aq\right)+2{\text{H}}_{\text{3}}{\text{PO}}_{\text{4}}\left(aq\right)\to {\text{Ba}}_3{\left({\text{PO}}_{\text{4}}\right)}_{\text{2}}\left(s\right)+6{\text{HNO}}_{\text{3}}\left(aq\right)$

(c)

Interpretation Introduction

Interpretation: The complete and balanced reactions are to be stated.

Concept Introduction : According to the law of conservation of mass, the mass can neither be created nor to be destroyed. Every reaction must be balanced.

Answer to Problem 16SP

The complete and balanced equation is $\text{FeS}\left(s\right)+2\text{HCl}\left(aq\right)\to {\text{FeCl}}_2\left(s\right)+{\text{H}}_{\text{2}}\text{S}\left(g\right)$ .

Explanation of Solution

The complete and balanced equation is given as:

  $\text{FeS}\left(s\right)+\text{HCl}\left(aq\right)\to {\text{FeCl}}_2\left(s\right)+{\text{H}}_{\text{2}}\text{S}\left(g\right)$

The co-efficient of 2 is placed before $\text{HCl}$ . The balanced equation is:

  $\text{FeS}\left(s\right)+2\text{HCl}\left(aq\right)\to {\text{FeCl}}_2\left(s\right)+{\text{H}}_{\text{2}}\text{S}\left(g\right)$