Chapter 11, Problem 55A

(a)

Interpretation Introduction

Interpretation:

The balanced equation needs to be determined for the decomposition reaction when Aluminum is obtained from Aluminum oxide with the addition of a large amount of electrical energy.

Concept Introduction:

A chemical reaction where two or more products are given by one reactant is called a decomposition reaction and the general form of such reaction is $\text{AB}\to \text{A}+\text{B}$ .

Answer to Problem 55A

The balanced chemical equation is ${\text{2Al}}_2{\text{O}}_3\left(\text{s}\right)\to 2\text{Al}\left(\text{s}\right)+3{\text{O}}_{\text{2}}\left(\text{g}\right)$ .

Explanation of Solution

Chemical symbols and formulas are used for representing a chemical reaction where reactants are written on the left side and chemical products are written on the right side.

The chemical equation is balanced by making the number and types of atoms on the left and right sides of the equation as same.

It is given that Aluminum is obtained from Aluminum oxide with the addition of a large amount of electrical energy, so, the balanced chemical equation will be:

  ${\text{2Al}}_2{\text{O}}_3\left(\text{s}\right)\to 2\text{Al}\left(\text{s}\right)+3{\text{O}}_{\text{2}}\left(\text{g}\right)$

(b)

Interpretation Introduction

Interpretation:

The balanced equation needs to be determined for the decomposition reaction when heating tin(IV) hydroxide gives tin(IV) oxide and water.

Concept Introduction:

A chemical reaction where two or more products are given by one reactant is called a decomposition reaction and the general form of such reaction is $\text{AB}\to \text{A}+\text{B}$ .

Answer to Problem 55A

The balanced chemical equation is $\text{Sn}{\left(\text{OH}\right)}_4\stackrel{\Delta }{\to }{\text{SnO}}_{\text{2}}+{\text{2H}}_{\text{2}}\text{O}$ .

Explanation of Solution

Chemical symbols and formulas are used for representing a chemical reaction where reactants are written on the left side and chemical products are written on the right side.

The chemical equation is balanced by making the number and types of atoms on the left and right sides of the equation as same.

It is given that Aluminum is obtained from Aluminum oxide with the addition of a large amount of electrical energy, so, the balanced chemical equation is retrieved by breaking one single compound into its components for a decomposition reaction and absorption of energy is required which is represented by delta sign and the equation becomes as:

  $\text{Sn}{\left(\text{OH}\right)}_4\stackrel{\Delta }{\to }{\text{SnO}}_{\text{2}}+{\text{2H}}_{\text{2}}\text{O}$

(c)

Interpretation Introduction

Interpretation:

The balanced equation needs to be determined for the decomposition reaction when silver carbonate decomposes into silver oxide and carbon dioxide when it is heated.

Concept Introduction:

A chemical reaction where two or more products are given by one reactant is called a decomposition reaction and the general form of such reaction is $\text{AB}\to \text{A}+\text{B}$ .

Answer to Problem 55A

The balanced chemical equation is ${\text{Ag}}_2{\left(\text{CO}\right)}_4\stackrel{△}{\to }{\text{Ag}}_2\text{O}+{\text{CO}}_{\text{2}}$ .

Explanation of Solution

Chemical symbols and formulas are used for representing a chemical reaction where reactants are written on the left side and chemical products are written on the right side.

The chemical equation is balanced by making the number and types of atoms on the left and right sides of the equation as same.

It is given that Aluminum is obtained from Aluminum oxide with the addition of a large amount of electrical energy, so, the balanced chemical equation is retrieved by breaking one single compound into its components for a decomposition reaction and absorption of energy is required which is represented by delta sign and the equation becomes as:

  ${\text{Ag}}_2{\left(\text{CO}\right)}_4\stackrel{△}{\to }{\text{Ag}}_2\text{O}+{\text{CO}}_{\text{2}}$