Chapter 11, Problem 41A

(a)

Interpretation Introduction

Interpretation: To determine the balance of chemical reactions.

Concept Introduction: The type of chemical reaction in which the count of atoms will be identical on both sides of the reaction is named a balanced chemical reaction.

Answer to Problem 41A

The balanced complete reaction will be ${\text{H}}_{\text{2}}{\text{C}}_{\text{2}}{\text{O}}_{\text{4}}\text{+KOH}\to {\text{K}}_{\text{2}}{\text{C}}_{\text{2}}{\text{O}}_{\text{4}}{\text{+H}}_{\text{2}}\text{O}$

Explanation of Solution

When oxalic acid is treated with potassium hydroxide, it will give potassium oxalate and water.

The balanced chemical reaction is:

  ${\text{H}}_{\text{2}}{\text{C}}_{\text{2}}{\text{O}}_{\text{4}}\text{+KOH}\to {\text{K}}_{\text{2}}{\text{C}}_{\text{2}}{\text{O}}_{\text{4}}{\text{+H}}_{\text{2}}\text{O}$

(b)

Interpretation Introduction

Interpretation: To determine the balance of chemical reactions.

Concept Introduction: The type of chemical reaction in which the count of atoms will be identical on both sides of the reaction is named a balanced chemical reaction.

Answer to Problem 41A

The balanced complete reaction will be ${\text{CdBr}}_{\text{2}}{\text{(aq)+Na}}_{\text{2}}\text{S(aq)}\to \text{CdS(s)+2NaBr}$

Explanation of Solution

When cadmium bromide is treated with sodium sulfide, it will form cadmium sulfide and sodium bromide.

The balanced chemical reaction is:

  ${\text{CdBr}}_{\text{2}}{\text{(aq)+Na}}_{\text{2}}\text{S(aq)}\to \text{CdS(s)+2NaBr}$