Chapter 11, Problem 52A

(a)

Interpretation Introduction

Interpretation:

The balanced chemical equation needs to be determined for a single replacement reaction that takes place in an aqueous solution when steel wood (iron) is placed in sulfuric acid.

Concept Introduction:

In a single replacement reaction, a more reactive element replaces the less reactive element from its compound.

Answer to Problem 52A

The balanced chemical equation is $\text{Fe}+{\text{H}}_2{\text{SO}}_4\to {\text{FeSO}}_4+{\text{H}}_2$ .

Explanation of Solution

It is known that a given reaction is a single replacement reaction so according to the activity series the steel wood (iron) is more reactive than hydrogen so it replaces the hydrogen in sulfuric acid.

Hence the balanced chemical equation is $\text{Fe}+{\text{H}}_2{\text{SO}}_4\to {\text{FeSO}}_4+{\text{H}}_2$ .

(b)

Interpretation Introduction

Interpretation:

The balanced chemical equation needs to be determined for a single replacement reaction that takes place when mercury is poured into an aqueous solution of zinc nitrate.

Concept Introduction:

In a single replacement reaction, a more reactive element replaces the less reactive element from its compound.

Answer to Problem 52A

No reaction.

Explanation of Solution

From the activity series of metals, mercury is not more reactive than zinc, thus no replacement of zinc takes place in the single replacement reaction.

(c)

Interpretation Introduction

Interpretation:

The balanced chemical equation needs to be determined for a single replacement reaction that takes place when bromine reacts with aqueous barium iodide.

Concept Introduction:

In a single replacement reaction, a more reactive element replaces the less reactive element from its compound.

Answer to Problem 52A

The balanced chemical equation is ${\text{Br}}_2\left(\text{l}\right)+{\text{Bal}}_{\text{2}}\left(\text{aq}\right)\to {\text{BaBr}}_{\text{2}}\left(\text{aq}\right)+{\text{I}}_{\text{2}}\left(\text{aq}\right)$ .

Explanation of Solution

It is known that as one goes down in group 7A in the periodic table the activity of halogens decreases so Bromine (Br) is more reactive than Iodide (I). Thus, Iodide is replaced by Bromine in the single replacement reaction.

Hence, the balanced chemical equation is ${\text{Br}}_2\left(\text{l}\right)+{\text{Bal}}_{\text{2}}\left(\text{aq}\right)\to {\text{BaBr}}_{\text{2}}\left(\text{aq}\right)+{\text{I}}_{\text{2}}\left(\text{aq}\right)$ .