World of Chemistry, 3rd edition
World of Chemistry, 3rd edition
3rd Edition
ISBN: 9781133109655
Author: Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher: Brooks / Cole / Cengage Learning
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Chapter 11, Problem 65A

(a)

Interpretation Introduction

Interpretation:

The general valence configuration of N needs to be given.

Concept Introduction: The general valence configuration of a given element is the arrangement of electrons in the increasing order of energy in the sub-shells of on atom.

(a)

Expert Solution
Check Mark

Answer to Problem 65A

The general valence configuration of Nitrogen is, N=1s22s22p3

Explanation of Solution

Nitrogen has 7 electrons as its atomic number is given to be 7. So they are arranged as:

  N=1s22s22p3

(b)

Interpretation Introduction

Interpretation:

The general valence configuration of francium needs to be given.

Concept Introduction: The general valence configuration of a given element is the arrangement of electrons in the increasing order of energy in the sub-shells of on atom.

(b)

Expert Solution
Check Mark

Answer to Problem 65A

The general valence configuration of Francium is,

  Fr=31s22s22p63s23p63d104s24p64d105s25p64f145d106s26p67s1

Explanation of Solution

Francium has 87 electrons as its atomic number is given to be 87. So they are arranged as:

  Fr=31s22s22p63s23p63d104s24p64d105s25p64f145d106s26p67s1

(c)

Interpretation Introduction

Interpretation:

The general valence configuration of chlorine needs to be given.

Concept Introduction: The general valence configuration of a given element is the arrangement of electrons in the increasing order of energy in the sub-shells of on atom.

(c)

Expert Solution
Check Mark

Answer to Problem 65A

The general valence configuration of Chlorine is,

  Cl=1s22s22p63s23p5

Explanation of Solution

Chlorine has 17 electrons as its atomic number is given to be 17. So they are arranged as:

  Cl=1s22s22p63s23p5

(d)

Interpretation Introduction

Interpretation:

The general valence configuration of Se element needs to be given.

Concept Introduction: The general valence configuration of a given element is the arrangement of electrons in the increasing order of energy in the sub-shells of on atom.

(d)

Expert Solution
Check Mark

Answer to Problem 65A

The general valence configuration of Selenium is, Se=1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p4

Explanation of Solution

Selenium has 34 electrons as its atomic number is given to be 34. So they are arranged as:

  Se=1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p4

(e)

Interpretation Introduction

Interpretation:

The general valence configuration of the given element Mg needs to be given.

Concept Introduction: The general valence configuration of a given element is the arrangement of electrons in the increasing order of energy in the sub-shells of on atom.

(e)

Expert Solution
Check Mark

Answer to Problem 65A

The general valence configuration of Magnesium is, Mg=1s2 2s2 2p6 3s2

Explanation of Solution

Magnesium has 12 electrons as its atomic number is given to be 12. So they are arranged as:

  Mg=1s2 2s2 2p6 3s2

Chapter 11 Solutions

World of Chemistry, 3rd edition

Ch. 11.2 - Prob. 4RQCh. 11.2 - Prob. 5RQCh. 11.2 - Prob. 6RQCh. 11.3 - Prob. 1RQCh. 11.3 - Prob. 2RQCh. 11.3 - Prob. 3RQCh. 11.3 - Prob. 4RQCh. 11.3 - Prob. 5RQCh. 11.3 - Prob. 6RQCh. 11.4 - Prob. 1RQCh. 11.4 - Prob. 2RQCh. 11.4 - Prob. 3RQCh. 11.4 - Prob. 4RQCh. 11.4 - Prob. 5RQCh. 11.4 - Prob. 6RQCh. 11.4 - Prob. 7RQCh. 11 - Prob. 1ACh. 11 - Prob. 2ACh. 11 - Prob. 3ACh. 11 - Prob. 4ACh. 11 - Prob. 5ACh. 11 - Prob. 6ACh. 11 - Prob. 7ACh. 11 - Prob. 8ACh. 11 - Prob. 9ACh. 11 - Prob. 10ACh. 11 - Prob. 11ACh. 11 - Prob. 12ACh. 11 - Prob. 13ACh. 11 - Prob. 14ACh. 11 - Prob. 15ACh. 11 - Prob. 16ACh. 11 - Prob. 17ACh. 11 - Prob. 18ACh. 11 - Prob. 19ACh. 11 - Prob. 20ACh. 11 - Prob. 21ACh. 11 - Prob. 22ACh. 11 - Prob. 23ACh. 11 - Prob. 24ACh. 11 - Prob. 25ACh. 11 - Prob. 26ACh. 11 - Prob. 27ACh. 11 - Prob. 28ACh. 11 - Prob. 29ACh. 11 - Prob. 30ACh. 11 - Prob. 31ACh. 11 - Prob. 32ACh. 11 - Prob. 33ACh. 11 - Prob. 34ACh. 11 - Prob. 35ACh. 11 - Prob. 36ACh. 11 - Prob. 37ACh. 11 - Prob. 38ACh. 11 - Prob. 39ACh. 11 - Prob. 40ACh. 11 - Prob. 41ACh. 11 - Prob. 42ACh. 11 - Prob. 43ACh. 11 - Prob. 44ACh. 11 - Prob. 45ACh. 11 - Prob. 46ACh. 11 - Prob. 47ACh. 11 - Prob. 48ACh. 11 - Prob. 49ACh. 11 - Prob. 50ACh. 11 - Prob. 51ACh. 11 - Prob. 52ACh. 11 - Prob. 53ACh. 11 - Prob. 54ACh. 11 - Prob. 55ACh. 11 - Prob. 56ACh. 11 - Prob. 57ACh. 11 - Prob. 58ACh. 11 - Prob. 59ACh. 11 - Prob. 60ACh. 11 - Prob. 61ACh. 11 - Prob. 62ACh. 11 - Prob. 63ACh. 11 - Prob. 64ACh. 11 - Prob. 65ACh. 11 - Prob. 66ACh. 11 - Prob. 67ACh. 11 - Prob. 68ACh. 11 - Prob. 69ACh. 11 - Prob. 70ACh. 11 - Prob. 71ACh. 11 - Prob. 72ACh. 11 - Prob. 73ACh. 11 - Prob. 74ACh. 11 - Prob. 75ACh. 11 - Prob. 76ACh. 11 - Prob. 77ACh. 11 - Prob. 1STPCh. 11 - Prob. 2STPCh. 11 - Prob. 3STPCh. 11 - Prob. 4STPCh. 11 - Prob. 5STPCh. 11 - Prob. 6STPCh. 11 - Prob. 7STPCh. 11 - Prob. 8STPCh. 11 - Prob. 9STPCh. 11 - Prob. 10STPCh. 11 - Prob. 11STPCh. 11 - Prob. 12STP
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