Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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Chapter 11, Problem 39P
Interpretation Introduction
Interpretation:
The role of carbohydrate in the nature and the reason behind its versatility needs to be described.
Concept introduction:
Carbohydrates are the natural compounds of carbon, hydrogen, and oxygen. Carbohydrate is nothing but sugar molecules which acts as an energy source for plants and animals.
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Students have asked these similar questions
Describe aldoses and ketoses.
Describe triose, tetrose, pentose, hexose and heptose.
Describe monosaccharide and list at list three examples.
Describe disaccharide and list at list three examples.
Describe polysaccharide and list at list three examples.
Describe functions of carbohydrates.
Describe the polymerization process of carbohydrates.
Describe the degradation process of carbohydrates.
What is the bond between sugars in a polysaccharide?
Describe the function of sugars in protein structures and functions.
Refer to the figure below. Determine whether the given descriptions between
the relationship of glucose and galactose is correct or incorrect. *
сно
ÇHO
H OH
HO-H
H-
-OH
HO-H
HO
H-
H-OH
ČH,OH
D-Glucose
-H
-OH
H-
-он
CH,OH
D-Galactose
CORRECT
INCORRECT
Glucose and galactose are
both Aldohexoses
They constitute the structure
of the disaccharide maltose
They are epimers at carbon 4
They are not mirror images of
each other, neither an
enantiomeric pair
Consider the following statements:
(1) Complete hydrolysis of a disaccharide produces only monosaccharides.
(2) Dihydroxyacetone, galactose, and ribose are all hexoses.
(3) Both amylopectin and glycogen are branched glucose polymers.
Only one of the statements is true.
Two of the three statements are true.
All three statements are true.
None of the statements are true.
Chapter 11 Solutions
Biochemistry
Ch. 11 - Prob. 1PCh. 11 - Prob. 2PCh. 11 - Prob. 3PCh. 11 - Prob. 4PCh. 11 - Prob. 5PCh. 11 - Prob. 6PCh. 11 - Prob. 7PCh. 11 - Prob. 8PCh. 11 - Prob. 9PCh. 11 - Prob. 10P
Ch. 11 - Prob. 11PCh. 11 - Prob. 12PCh. 11 - Prob. 13PCh. 11 - Prob. 14PCh. 11 - Prob. 15PCh. 11 - Prob. 16PCh. 11 - Prob. 17PCh. 11 - Prob. 18PCh. 11 - Prob. 19PCh. 11 - Prob. 20PCh. 11 - Prob. 21PCh. 11 - Prob. 22PCh. 11 - Prob. 23PCh. 11 - Prob. 24PCh. 11 - Prob. 25PCh. 11 - Prob. 26PCh. 11 - Prob. 27PCh. 11 - Prob. 28PCh. 11 - Prob. 29PCh. 11 - Prob. 30PCh. 11 - Prob. 31PCh. 11 - Prob. 32PCh. 11 - Prob. 33PCh. 11 - Prob. 34PCh. 11 - Prob. 35PCh. 11 - Prob. 36PCh. 11 - Prob. 37PCh. 11 - Prob. 38PCh. 11 - Prob. 39P
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- Identify whether each monosaccharide is an aldose or a ketose. Н НО Н Н НО- CHO ОН H -ОН ОН CH2OH CH2OH H CH₂OH Н НО Н CHO ОН CHO H -ОН CH₂OH н-с ОН CH2OH Н Н Н Н· CH2OH C=0 ОН CH2OH ... CHO ОН ОН ОН CH2OH Но Н Н Н CH2OH c=0 -Н -ОН CH2OH CH2OH О ОН ОН CH2OHarrow_forwardAlthough the first two carbons of fructose and glucose are identical in structure to DHAP and GADP (from glycolysis), DHAP and GADP equilibriate on their in solution to favor the ketone over the aldehyde, while fructose and glucose do not. Why? a)The larger size of the molecule sterically hinders the isomerization b)The larger sugars have more OH groups which hydrogen bond and disrupt isomerization c)The larger sugars cyclize, and there is no carbonyl to isomerize in the cyclic form d)The larger sugars cyclize, and in the cyclic form the hydrogen bonding is very strong e)The larger sugars are less soluble in water than the smaller sugarsarrow_forwardDefine glycolipids.arrow_forward
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